Can someone please help with my CALCULUS hw? I don't understand.?
"A particle’S placement (in meters) is offered because of the equating s(testosterone levels) = 5x sinfulness(2 times), within the separation [-a single, iv] minutes. Precisely what is their instantaneous velocity in to = 3?
"Find the derivative of the position function in order to find the velocity formula, then plug in 0 to find instantaneous velocity: s(t)=5xsin(2x)-> s'(t)= 5x*2cos(2x)+ 5sin(2x)-> 0+ 5sin(0)= 0-> The answer is C. 0."