How many grams of CaBr2 are needed to prepare 4.65 L of a 7.65 M solution?

  • a) 7110 g
  • b) 0.00303 g
  • c) 122 g
  • d) 0.178 g
  • e) 4270 g
  • f) 5.26 g
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First, calculate moles using molarity and solvent. Secondly, calculate molar mass. Finally multiply the results of both steps. More on molarity, molality and molar mass explained in lecture slides.
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