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A series of questions and answers related to molecular biology, focusing on amino acids, proteins, and metabolism. Topics covered include protein structure, mutations, enzymes, metabolic pathways, and more. It serves as a valuable resource for students studying biology, particularly those in university-level courses.
Typology: Exams
Available from 04/28/2024
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The2ndOAReadinessCheckisdesignedtogiveyouadditionalpracticewithnewassessment- stylequestions to help prepare for success on the OA. Thus, please try to mimic exam- like conditions bytakingthetestinone<2hrsittingwithoutanystudyaidsapartfromyourwhiteboard/ scrappaper. Note: You can take the 2nd OA Readiness Check again if you're so inclined, but you can not edityourresponseasyoumayhavedonewiththetopicquestions.Youwillbeabletoseethere sultsafterwards.
1/ 3’TATTCGCAT5’ 3’TACGCTTAT 5’ 3’GATAGCATA5’ 5’ATAAGCGTA3’ Feedback The correct answer is 3' TAT TCG CAT 5'. Remember complementary means “Matching or Pairing”Youhavetoremembertopayattentiontoyournumbersaswellasyourletters(A-T,G-C,5'- 3').Thecorrectansweris 3’ATGCGA ATA5’(originalsequence) 5’TACGCTTAT3’(complementarysequence) Butweaskedfor itinthe3’direction, somirroranswer togivecorrectanswer:3’TATTCGCAT 5’
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Tyr Val TyrIle Gln IleIleAsp Val LeuHisLys Feedback ThecorrectanswerisIleAspVal.Wearestartingatthecodingstrand,andhavetoremembertherelationship between coding DNA and mRNA. These two strands are non-complementary andparallel.Sowecopythecoding strand,changeT --->U,andthenwritethemRNAsequence: 3’ATGCAGATA5’coding 3’AUGCAGAUA5’mRNA Mirror by changing orientation: 5’ AUA GAC GUA 3’ReadchartIleAspVal(chartisindirectionof5'--->3')
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TyrTyrArg Ile Met AlaSer Val IleSerHis Gln Correctanswer SerValIle Feedback Thecorrect answerisCbecause 5’TATTAC CGA3’template iscomplementaryandantiparallelso3’AUAAUGGCU5’butitisinthewron gorientation,somirror 5’UCGGUAAUA3’andread the
1/ dNTPs,Primer,RNAPolymerase,templateRNAd NTPs,Primer,DNAPolymerase,templateDNA ATP,Primer,mRNApolymerase;templatemRNA
AcetylCoA, RNAprimer, DNALigase,Template phosphate Feedback Thecorrect answerisb
1/ 0% 25% 50% 75% 100% Feedback The correct answer is c 50%Homozygous recessive: aaHeterozygous:Aa
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Feedback The correct answer is BAUC GUAACA IleValThr Ile GlyThr MissenseIleValThr IleValSTOPnonsenseIl eLeuThr Missense
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Silent Missens eNonsen seInserti on Feedback ThecorrectanswerisA:silentmutation.Thenucleotidesequencechanges,butitcodesforthesameamino acid
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Option Feedback ThecorrectanswerisAbecauseanautosomaldominantdisorderwouldbeinheritedonnumberedchromo somes, not sex chromosomes X or Y. Also, at least one dominant allele (yellow box) needstobe presentfortheindividual tohavethedominantdisease.
0/ Autosomal dominantAutosom alrecessive X-linked DominantX- Linkedrecessive Correctanswer X-Linkedrecessive Feedback Thecorrectanswerisx-linkedrecessivebecauseparentsdonothaveit(II-5-6)butachilddoesIII-
Feedback Thecorrect answerisD
1/ ADNA-bindingproteinblocks RNAPolymerasefrombindingtothepromotersequence,facilitatingthetra nscriptionoftheMECP2gene. Transcriptionfactorsareunabletobindtothetranscriptionstartsiteofthe MECP2genebecausenucleosomesaretightlypackedtogether. Transcriptionactivatorscausenucleosomestoseparate,exposingtheME CP2gene. RNAPolymerasebinds totheMECP2geneandbeginstranslation. Feedback The answer is B. Gene expression is increased when nucleosomes are widely spaced andtranscriptionfactorsandRNAPolymeraseareabletobindtothetranscriptionstartsiteofthegene.
1/ Coding and Non- templateTemplateand mRNA Coding and mRNATemplatea ndtRNA Feedback ThecorrectanswerisB.ThetemplateandmRNAstrandsarecomplementarytoeachother.
1/ Translation,Replication,Transcrip tionTranscription,Replication,Tra nslationTranslation, Transcription, ReplicationReplication,Transcript ion,Translation
1/ Thehomologouschromosomeisusedtoreplacetheincorrectlyaddedbase withthe correctone. DNAPolymeraseremoves theincorrectbaseandaddsinthecorrectbase. Thyminedimersoccur. DistortionofthedoublehelixoccursandisrepairedbyRNAPolymerase. Feedback ThecorrectanswerisB.DNAPolymeraserepairsmismatcherrorsthatoccurduringDNAreplication.
1/ Removalofasingledamagednucleotide Damagetoafeworseveralnucleotidesareidentified,thenmanynucleotid esareremovedandall arereplacedto repairtheDNAsegment RequiredwhentherearebreaksinthedoublestrandedDNAstrandwhichca uses discontinuityinboth strands Insertionofathyminedimer Feedback ThecorrectanswerisB,severalnucleotidesareremovedwhereinBERasinglenucleotideisremoved
0/ Hydrogenbonds Ionicbonds Hydrophobicinteractions Disulfidebonds Correctanswer Hydrogen bondsIonic bonds Feedback
1/ Hydrophobic interactionsHydrogen bondsDisulfidebonds Ionicbonds Feedback Thecorrectanswerarecovalent(disulfide)bonds C
1/ IonicbondHydrophob ic interactionHydrogen bond Disulfidebond Feedback ThecorrectanswerishydrogenbondsC
1/ Activationener gyEnzymesDe hydration Hydrolysis Feedback ThecorrectanswerisadehydrationreactionC
1/ PrimaryS econdary Tertiary Quaternary Feedback Tertiary,myoglobinisasinglesubunitproteinC
1/ PrimaryS econdary TertiaryQ uaternary Feedback Secondary levelhasalphahelicesandbetapleatedsheetsB
1/ PrimaryS econdary
TertiaryQ uaternary Feedback Secondary structure B is the correct answer. Primary and secondary structures involve interactionsbetweenthebackbones,tertiaryandquaternarystructuresinvolveinteractionsbetweenthevari ablegroups
0/ Aprotein has optimal function inits primarystructure. Allproteinscarryoutcellularfunctionswhentheyhaveobtainedtheirfinalq uaternarystructure. Ionicbondsbetweenthebackbonegroupsofaminoacidsstabilizeaprotein' stertiarystructure. Thehydrophobiceffectprimarilycontributestoasinglesubunitprotein's tertiarystructure. Correctanswer Thehydrophobiceffectprimarilycontributestoasinglesubunitprotein'st ertiarystructure. Feedback ThecorrectanswerisD.Thehydrophobiceffectdrivestheformationofthecoreofaprotein, whichisthepredominant contributing factor totheprotein's tertiarystructure.
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Nothingtheywillbindnormally Thehydrogenbondwillnolongerbeformed,andtheproteinwillbemisfolde d Nothing, they will form a hydrophobic interactionThey willformadisulfidebond Feedback Thecorrect answerisB
1/ DisulfidebondformationbycysteineaminoacidsI rondeficiency Aggregationofhydrophobicaminoacids Ionicbondsformedbyhydrogenbondingofaminoacids Feedback Answeris C
1/ IonicDi sulfide Charge d
Feedback Answeris Dpeptidebonds Peptide
0/ Option Option
Correctanswer Option Feedback Cisthecorrect answer Option Option
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Ionic bonds will continue to form, allowing the protein to fold as normal.Hydrophobicinteractionswillcontinuetooccurresultinginnorm alfolding.Ionicbondswillnolongerform,potentiallycausingtheproteint omisfold. Hydrophobicinteractionswillbebroken,potentiallycausingaggregation. Feedback Thecorrect answerisCanionicbondwillnot formbetweentwochargedaminoacids,leadingtoamisfoldedprotein.
1/ IonicbondsHydrophob icinteractions Disulfide bondsNoneofth eabove Feedback ThecorrectanswerisBheatwilldisrupthydrophobicinteractions
0/ HemoglobinwillswitchintotheR-stateanddeliveroxygen Hemoglobinwillbindandstoreoxygen HemoglobinwillswitchintotheT- stateanddeliveroxygenHemoglobinwillswitchintotheR- stateandbindoxygen Correctanswer HemoglobinwillswitchintotheT-stateanddeliveroxygen Feedback The correct answer is C (Hemoglobin will switch into the T-state and deliver oxygen) becauseHemoglobinswitchesintotheT- stateanddeliversoxygenintheacidic(lowpH)environmentofexercisingmuscle tissue.
Feedback Thecorrect answerisD(CO)Carbonmonoxidecanbindtohemoglobinwithagreater affinitythanoxygen. Hemoglobinbindsoxygeninacooperativemanner,whileMyoglobinbinds oxygenwitharelativelyhigheraffinityandstoresoxygen. Hemoglobinhastertiarystructure,whileMyoglobinhasquaternarystru ctureandbindsoxygenin acooperativemanner. HemoglobinstoresoxygenandMyoglobindeliversoxygentooxygen- deprivedmuscletissue. Myoglobinisboundby2,3-BPGandchangesintotheT- statetodeliveroxygen Feedback ThecorrectanswerisA.(Hemoglobinbindsoxygeninacooperativemanner,whileMyoglobinbindsoxygen with a relatively higher affinity and stores oxygen.) Hemoglobin has 4 subunits and bindsoxygen in a cooperative manner. Cooperativity means that as one molecule of oxygen binds tohemoglobin, the shape of hemoglobin changes to make it easier to bind subsequent molecules ofoxygen.Myoglobin’sjobistostoreoxygen, soit bindstooxygenwithahighaffinityandstoresit.
1/ CO Mg 2,3- BPGCO
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Thehemoglobincurvewillshifttotherightwhenthereisahighconcentrati onofH+ (protons) andtheconcentration of CO2is high. Thehemoglobincurvewillshifttotheleftwhenthereisahighconcentrati onofH+ (protons)andtheconcentrationof CO2is low. Thehemoglobincurvewillshifttotherightwhenthereisalowconcentrati onofH+ (protons)andtheconcentrationof CO2is low. Thehemoglobincurvewillshifttotheleftwhenthereisahighconcentrati onofH+ (protons)and theconcentrationofCO2is high. Feedback The correct answer is A (The Hemoglobin curve will shift to the right when there is a highconcentrationofH+(protons)andtheconcentrationofCO2ishigh.).ArightshiftintheHemoglobincurve correlates with a decrease in pH. At low pH, H+/proton concentration is high (this occurs inmuscle tissue and tells Hemoglobin to release oxygen). In the muscle tissue, at low pH, CO2concentrationis highbecause itisbeing producedby themuscles.
1/1 HemoglobinadoptstheT- stateconformationandthehemegroupsbecomeplanar. HemoglobinadoptstheR- stateconformationandthehemegroupsbecomeplanar.
HemoglobinadoptstheT- stateconformationandthehemegroupsbecomebent. HemoglobinadoptstheR- stateconformationandthehemegroupsbecomebent. Feedback The correct answer is B (Hemoglobin adopts the R-state conformation and the heme groupbecomesplanar.).WhenHemoglobinbindsoxygen(inthelungs)inchangesintotheR- stateandthehemegroups takeona planarshape.
1/1 Bicarbonate binds to Susie’s hemoglobin and stabilizes the T- stateconformation, which favors the delivery of oxygen to the developing fetuses.2,3- BPGbindstoSusie’shemoglobinandstabilizestheT- stateconformation,whichfavorsthedeliveryof oxygentothedevelopingfetuses. CarbonmonoxidebindstoSusie’shemoglobinandstabilizestheR- stateconformation, which increases the delivery of oxygen to the developingfetuses. BicarbonateinducesSusie’shemoglobintoadoptanon- planarconformationandbindoxygensothatthedevelopingfetusesaresu fficientlyoxygenated. Feedback The correct answer is B (2,3-BPG binds to Susie’s Hemoglobin and stabilizes the T- stateconformation,whichfavors thedeliveryofoxygentothedevelopingfetuses.).2,3- BPGbindstoHemoglobinandstabilizestheT-statewhichfavorsoxygendelivery.
1/1 Carbondioxideisconvertedtobicarbonateandbindstohemoglobin,which shuttles the carbon dioxide to the lungs so that it can be exhaled out of thebody.
Feedback The correct answer is D. (Carbonic Anhydrase converts carbon dioxide to bicarbonate, which canflow through the bloodstream to the lungs. In the lungs, Carbonic Anhydrase converts bicarbonatebacktocarbondioxidesothatitcanbeexhaledoutofthebody.)CO2isawasteproductproducedi nthetissuesfromaerobicrespiration.TheCO2isconvertedtobicarbonate(HCO3-)inthetissuesasawaytos huttleCO2tothelungssothatit canbeexhaledoutof thelungs. Inthelungs,HCO3-isconverted backtoCO2and CO2is exhaledoutofthebody. Feedback The correct answer is D (The amount of E would increase). If enzyme 4 is inhibited, then D will nolongerbemade,soCwillbuildupandenzymewouldconvertmoreCtoE, thusE wouldincrease. Carbondioxideflowsthroughthebloodstreamtothelungssothatitcanbe exhaledoutof thebody. Carbonicanhydrasehelpscarbondioxidesticktohemoglobin,whichshuttl esthe carbon dioxide to the lungs. In the lungs, Carbonic Anhydrase convertscarbondioxidetoagassothatitcanbeexhaledoutofthebody. Carbonicanhydraseconvertscarbondioxidetobicarbonate,whichcanflo wthrough the bloodstream to the lungs. In the lungs, Carbonic Anhydraseconvertsbicarbonatebacktocarbondioxidesothatitcanbeex haledoutofthebody.
1/1 The amount of A would decreaseThe amount of D would increaseThe amount of C would decreaseTheamountofEwoul dincrease
1/1 The amount of compound C would build upTheamountofcompoundBwouldbuil dup The amount of compound D would increaseTheamountofcompoundAwould decrease Feedback Thecorrect answerisB(Theamountof compoundBwouldbuildup). Whenanenzymeisinhibitedwithinapathway,theenzyme’ssubstratebuildsupanditssubsequentproducts
1/1 CompetitiveN on- competitive Sequenti alCongru ent Feedback ThecorrectanswerisB(Non- competitive).Aninhibitorthatbindstoasiteotherthantheenzyme'sactivesite(allostericsite)isaNon- competitiveinhibitor.
1/1 Kinase PhosphataseAc
etyltransferase Dehydrogenas e