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Enzyme Kinetics: Understanding Enzyme Reactions and Comparing Enzymes - Prof. Paul J. Layb, Study notes of School management&administration

An overview of enzyme kinetics, including the role of enzymes in catalyzing reactions, the concept of specificity and efficiency, and the michaelis-menton equation. It also discusses the significance of enzyme kinetics in comparing chemical reactions and enzymes, as well as the importance of turnover number and michaelis constant in evaluating enzyme efficiency and specificity. The document also touches upon the significance of enzyme kinetics in determining the effect of active site amino acids and identifying enzyme inhibitors.

Typology: Study notes

2010/2011

Uploaded on 11/15/2011

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Download Enzyme Kinetics: Understanding Enzyme Reactions and Comparing Enzymes - Prof. Paul J. Layb and more Study notes School management&administration in PDF only on Docsity! 7 September Enzymes affect the kinetics of a reaction Can use enzyme kinetics to Compare chemical reactions Compare enzymes as catalysts Specificity and efficiency Study enzyme mechanisms Chemical Kinetics Experiments Rate or velocity: v = Δ [P] t S k−1 ← k 1 → P; at v0 only k1 is significant, v0 = k1 [S] Compare rates or velocities (v0) as it varies with [S] “Simple” case E + S ↔ES ↔ EP ↔ E + P E + S associate E catalyzes conversion of S to P E + P dissociate Michaelis and Menton Used initial velocities (v0), plot vs. [S] Simplifies reaction to E + S k−1 ← k 1 → ES k 2 → E + P Gives hyperbolic curve Michaelis – Menton equation V0 = Vmax [S ] KM+[S ] KM – Michaelis Constant – [S] at ½ Vmax Briggs and Haldane Applied M&M Kinetics in terms and conditions useful for enzyme comparison [ES] in “steady state” Not changing K2 rate limiting (k2< < k-1) [S] very high Enzyme is saturated [ES] ≈ [Et] [Et] known V0 = k2 [ES] So v0 = k2 [Et] Produces Terms Useful for Comparing Enzymes E + S k−1 ← k 1 → ES k 2 → E + P Turnover Number V0 = Vmax = k2 [Et] K2 = Vmax [Et ] = kcat in rxns s (measures efficiency) Michaelis Constant KM = (k−1+k2) k1