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Material Type: Notes; Class: Quantum Mechanics II; Subject: Physics; University: Syracuse University; Term: Spring 2004;
Typology: Study notes
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Today
**** Establish the expression [exercise]
( A~ · ~σ)( B~ · ~σ) = A~ · B~ + i( A~ × B~) · ~σ,
for vector operators A, ~B~ that commute with ~σ.
**** Reproduce effect of S+ and S− on spinors - check with Pauli matrices.
Note “interesting” that one can go back and forth between 〈S~〉and nˆ. [Not true for other spins. Why not?]
One use for quantum cryptography: securely distributing a one-time key (with no fear of eavesdropping). Relies on non-commutativity of the spin operators and the collapse of the wave function upon observation. Other schemes also depend on quantum “en- tanglement”.
Here is the classic example, Bennett and Brassard, 1984 (adapted to spin-1/2 - usually is described with photons):
Example:
Alice chooses the random sequence
|+, ˆz〉, |+, ˆx〉, |+, xˆ〉, |−, ˆz〉, |+, xˆ〉, |−, zˆ〉
The particles are sent to Bob.
Bob makes measurements, randomly chosen, along the axes x, x, z, z, x, x.
At this point Alice publicly announces “z, x, x, z, x, z” and Bob publicly announces “x, x, z, z, x, x”.
They agree on the 2nd, 4th, and 5th spins. So they now jointly know the sequence “+,-,+” which they can use as a bit sequence “101”= key. Alice decides to send the message plaintext= 001 , which gets converted to plaintext ⊕ key = 001 ⊕ 101 = 100. Only Bob, who knows that “101” is the key, can properly convert the ciphertext to plaintext: 100 ⊕ 101 = 001.
Now, Alice and Bob can also check for snoops who might be peeking at their bits. If Claire had been using an apparatus in between that was making measurements, it would change the amplitudes.
[This all gets more complicated with errors in the signal, etc. Errors in alignment of apparatus or patterns in random number generators might provide an attacker with clues. Photons work better than electrons or spin-1/2 atoms; here one sets polarizers in 4 directions left-right, up-down, and 2 π/ 4 rotations to prepare photons polarized in 4 different directions, but the scheme is the same.]
Symmetries and Conservation Laws - a reminder
NOTE: the rotation operators in Feynman are for a change of the frame (passive trans- formation). So all angles are inverted to get the rotation operators in Shankar!
This is very simple, really, in quantum mechanics. To explain magnetic moments in a constant magnetic field, one needs all these ideas of torque, etc.
The result is precession, similar to precession in classical mechanics, but easier.
The Hamiltonian for a magnetic moment in a magnetic field is
H = −~μ · B,~
where the magnetic moment operator is related to the spin operator by
~μ = γ S~ =
gq 2 mc
Where the proportionality constant γ has been redefined in terms of a unitless “g- factor”. For orbital angular momentum, g = 1. For spin, it depends: gelectron ≈ 2 , gproton ≈ 5. 6 , and γneutron = − 3 .8( (^2) M e neutronc^
The time evolution operator U (t) is now given by U (t) = exp(−iHt/¯h) = exp[iγt(S~· B^ ~)/¯h]. What other operator is this equal to?
Example: consider a spin-1/2 particle in the state |+, ˆx〉 in a field oriented in the zˆ- direction. What is its state as a function of time? What are 〈Sx(t)〉, 〈Sy (t)〉, and 〈Sz (t)〉?
Note the μ-decay experiment and possible indications of new particles (supersymme- try).