Normal Boiling Point - General Chemistry - Solved Quiz, Exercises of Chemistry

Download Normal Boiling Point - General Chemistry - Solved Quiz and more Exercises Chemistry in PDF only on Docsity! 1. 3 pts. What is the temperature of -76.7 oC on the Kelvin scale? 196.4 K 2. 3 pts. How many atmospheres of pressure are the equivalent of 778 mm Hg? 1.02 atm 3. 3 pts. A steel vessel 2.00 L in volume contains an unknown gas sample. The pressure is 1.02 atm and the temperature is 27.0 oC. How many moles of this gas are present, assuming that the sample of gas behaves ideally? The ideal gas constant is equal to 0.08206 L-atm/K-mol. 0.083 mol 4. 3 pts. Circle the one you would predict to have the higher normal boiling point: CH3 CH2 OH CH3 O CH3 ethanol methyl ether Now Explain your answer: Ethanol will have the higher boiling point because of hydrogen bonding which is possible between the OH hydrogen and the oxygen of another molecule. 5. 6 pts. Consider the following reaction and stated equilibrium constant: 2 2 4( ) 2 ( ) ( ) 0.0025 pXe g F g XeF g K atm −+ → = If we introduce 0.50 atm of Xe and 0.50 atm of F2 in an empty flask, what will be the partial pressures of all three gases in the mixture at equilibrium? 4 2 4 2 2 2.0025 .00031 .00031 atm .50 atm .50 153 (.5 )(. ) t 5 a 2 m X XeF X e e F Xe F F P x x P P x x P P P = = = == = − − Docsity.com 6. 25 pts. Calculate the pH, the pOH, and the concentrations of all species in solution for each of the following. CIRCLE FINAL ANSWERS 0.015 M hydrochloric acid (HCl) pH=1.82 pOH=12.18 [H3O+] = .015 [OH-] = 7 x 10-13 [Cl ] = .015 2.550 M propanoic acid (CH3CH2COOH) pH=2.240 pOH=11.760 [H3O+] = .00575 [OH-] = 2 x 10-12 [CH3CH2COO- ] = .00575 [CH3CH2COOH] = 2.544 5.000 M sodium perchlorate (NaClO4) pH=7.000 pOH=7.000 [H3O+] = 1 x 10-7 [OH-] = 1 x 10-7 [Na+ ] = 5.000 [ClO4-] = 5.000 2.700 M sodium propanoate (CH3CH2COONa) pH=9.659 pOH=4.341 [H3O+] = 2 x 10-10 [OH-] = 4.56 x 10-5 [Na+ ] = 2.700 [CH3CH2COO-] = 2.700 [CH3CH2COOH] = 4.56 x 10-5 1.500 M methylamine (CH3NH2) pH=12.395 pOH=1.605 [H3O+] = 4 x 10-13 [OH-] = 0.0248 [CH3NH3+] = 0.02483 [CH3NH2] = 1.475 Docsity.com