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A comprehensive set of exercises and explanations related to nyquist diagrams in control systems. It covers key concepts such as the nyquist stability criterion, frequency response analysis, and the relationship between nyquist diagrams and bode plots. Detailed examples and solutions, making it a valuable resource for students and professionals in the field of control engineering.
Typology: Exams
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PRIKAZ OSNOVNIH
Č
LANOVA U NYQUIST-ovom DIJAGRAMU
s
j
ω
0
č
lan
G(s)
j
ω =
ϕ =
B
N
ϕ
− ϕ
B
N
Im
Im
arctg(
arctg(
Re
Re
P
P
P
Re
Im
Re
Im
K
P
1
č
lan
G(s)
P
Ts
j
ω =
P
j
ω
P
2
ω
j
ω =
P
j
ω
j j
ω
ω
P 2
2
ω
P
2
2
j
−ω
ω
2
2
P
P
2
2
2
2
ω
ω
ω
ZADATAKZADATAK
1 1.
22
č
lan
č
lan
G(s)
ω = j
B
N
ϕ = ϕ
− ϕ
P
2
2
2
1
T s
T s
P
2
2
2
1
ω
ω +
j
j
P
2
2
2
1
ω
ω
j
P
2
2
2
2
2
1
ω
ω
N
= −ϕ
N
Im
arctg(
Re
1
2
2
2
arctg(
ω
ω
ω ϕ
Re
Im
P
Re
Im
K
P
ω
=
2 π 2
2
P
1
T
K
T
Re
Im
2
P
1 T
K
T
π
Re
Im
ω = ∞
Re
Im
č
lan 2. reda može imati maksimalno kašnjenje : č
lan 2. reda može imati maksimalno kašnjenje :
ϕ
max
π
max
n
π 2
ϕ
00
č
lan
č
lan
G(s)
d
G( j
ω =
ω j
B
N
ϕ = ϕ
− ϕ
d
T
arctg(
ω
ϕ =
d
T s d
T
ω
B
= ϕ
B
Im
arctg(
Re
π 2
ω ϕ
D π 2
Re
Im
π 2
π 2
Re
Im
ω
=
Re
Im
ω = ∞ 1
Re
Im
D 1 T
ω =
ZADATAKZADATAK
(^2) 2.
Za regulacijsku stazu prema slici potrebno je izra
č
unati frekvencijske karakteristike i dati prikaz
K
x
u
x
i
1
s
T
1 1
1
s
T
1 2
K
3
= 1
2
T
T
1
=
=
G(s)
ω = j
(s
1)(s
2
s
2s
2
ω
ω +
j
j
2
− ω
ω j
2
2
B
B
2
2
N
N
Re
Im
Re
Im
2
2
2
− ω
ω
4
2
ω
ω
2
ω
amplitudno – frekvencijske karakteristike (AFK) i fazno-frekvencijske karakteristike (FFK) uNyquistovom dijagramu.
Re
Im
Re
Im
Re
Im
Re
Im
Re
Im
B
N
ϕ = ϕ
− ϕ
N
= −ϕ
2
arctg(
ω
− ω
2
ω =
− ω
ω
j
j
2 2
− ω
ω
− ω
ω j j
2
2
2
2
− ω
− ω
ω
2
2
2
− ω
− ω
ω
j
ω ϕ
π 2
π
3
ω
=
1,
ω
=
0, ω
= ω = ∞
Re
Im
Re
Im
2
ω =
−ω
ω
j
j
ω = j
2 2
−ω
ω
−ω
ω j j
2
4
2
2
ω
ω
ω
ω
j
j
2
4
2
ω
ω
ω
4
2
ω
ω
ω
j
2
ω
3
ω
ω
j
−π
ω Re Im
ϕ G
π 2
Re
Im
Re
Im
10
9
− ω
=
Re
Im
ω
=
Re
Im
ω
=
Re
Im
ω = ∞
-^ -
za lakše crtanje:za lakše crtanje:
ZADATAKZADATAK
(^4) 4.
Za sustav prikazan blok-dijagramom odrediti AFK i FFK i dati prikaz u Nyquistovom dijagramu
.
x
u
x
i
2
s 3
K
1
s 2
1
1
s
1 +
K=10^ K=
G(s)
ω = j
B
N
ϕ = ϕ
− ϕ
3
2
6s
13s
9s
(2s
1)(3s
2)(s
2
3
ω
ω −
ω
j
3
2
ω
ω
ω +
j
j
j
6
4
2
ω
ω
ω
2
2
3
2
ω
ω −
ω
N
= −ϕ
3
2
arctg(
ω −
ω
ω