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Nyquist Diagrams: Exercises and Explanations for Control Systems, Exams of Electronics

A comprehensive set of exercises and explanations related to nyquist diagrams in control systems. It covers key concepts such as the nyquist stability criterion, frequency response analysis, and the relationship between nyquist diagrams and bode plots. Detailed examples and solutions, making it a valuable resource for students and professionals in the field of control engineering.

Typology: Exams

2019/2020

Uploaded on 02/11/2025

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NYQUIST
NYQUIST-
-ovi DIJAGRAMI
ovi DIJAGRAMI
AUDITORNE VJE
AUDITORNE VJEŽBE
ŽBE
pf3
pf4
pf5
pf8
pf9
pfa

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NYQUISTNYQUIST

ovi DIJAGRAMIovi DIJAGRAMI

AUDITORNE VJE^ AUDITORNE VJE

ŽBEŽBE

PRIKAZ OSNOVNIH

Č

LANOVA U NYQUIST-ovom DIJAGRAMU

s



j

ω

P

0

č

lan

G(s)

G(

j

ω =

G

ϕ =

B

N

ϕ

− ϕ

B

N

Im

Im

arctg(

arctg(

Re

Re

P

K

P

K

P

K

Re

Im

Re

Im

K

P

P

1

č

lan

G(s)

P

K

Ts

G(

j

ω =

P

K

T

j

ω

G

P

2

K

(T

ω

G(

j

ω =

P

K

T

j

ω

T

T

j j

ω

ω

P 2

2

K

T

ω

P

2

2

TK

T

j

−ω

ω

G

2

2

P

P

2

2

2

2

K

K

T

T

T

ω

ω

ω

ZADATAKZADATAK

1 1.

PP

22

č

lan

č

lan

G(s)

G(

ω = j

G

B

N

ϕ = ϕ

− ϕ

P

2

2

2

1

K

T s

T s

P

2

2

2

1

K

T (

T (

ω

ω +

j

j

P

2

2

2

1

K

T

T

ω

ω

j

P

2

2

2

2

2

1

K

T

(T

ω

ω

N

= −ϕ

N

Im

arctg(

Re

1

2

2

2

T

arctg(

T

ω

ω

G

ω ϕ

Re

Im

P

K

Re

Im

K

P

ω

=

1 T

2 π 2

2

P

1

T

K

T

Re

Im

2

P

1 T

K

T

π

∞^0

Re

Im

ω = ∞

Re

Im

č

lan 2. reda može imati maksimalno kašnjenje : č

lan 2. reda može imati maksimalno kašnjenje :

ϕ

max

π

max

n

π 2

ϕ

DD

00

č

lan

č

lan

G(s)

d

G( j

T

ω =

ω j

G

B

N

ϕ = ϕ

− ϕ

d

T

arctg(

ω

ϕ =

d

T s d

T

ω

B

= ϕ

B

Im

arctg(

Re

π 2

G

ω ϕ

1 T

D π 2

Re

Im

π 2

π 2

Re

Im

ω

=

Re

Im

ω = ∞ 1

Re

Im

D 1 T

ω =

ZADATAKZADATAK

(^2) 2.

Za regulacijsku stazu prema slici potrebno je izra

č

unati frekvencijske karakteristike i dati prikaz

K

x

u

x

i

1

s

T

1 1

1

s

T

1 2

K

3

= 1

2

T

T

1

=

=

G(s)

G(

ω = j

K

(s

1)(s

2

s

2s

2

ω

ω +

j

j

2

− ω

ω j

G

2

2

B

B

2

2

N

N

Re

Im

G

G

G

Re

Im

2

2

2

− ω

ω

4

2

ω

ω

AFK

2

ω

amplitudno – frekvencijske karakteristike (AFK) i fazno-frekvencijske karakteristike (FFK) uNyquistovom dijagramu.

Re

Im

Re

Im

Re

Im

Re

Im

Re

Im

B

N

ϕ = ϕ

− ϕ

N

= −ϕ

2

arctg(

ω

− ω

FFK

2

G(

ω =

− ω

ω

j

j

2 2

− ω

ω

− ω

ω j j

2

2

2

2

− ω

− ω

ω

2

2

2

− ω

− ω

ω

j

G

ω ϕ

∞^0

π 2

π

3

ω

=

1,

ω

=

0, ω

= ω = ∞

Re

Im

Re

Im

2

G(

ω =

−ω

ω

j

j

G(

ω = j

2 2

−ω

ω

−ω

ω j j

2

4

2

2

ω

ω

ω

ω

j

j

2

4

2

ω

ω

ω

4

2

ω

ω

ω

j

2

ω

3

ω

ω

j

−π

ω Re Im

ϕ G

π 2

Re

Im

Re

Im

10

9

− ω

=

Re

Im

ω

=

Re

Im

ω

=

Re

Im

ω = ∞

-^ -

za lakše crtanje:za lakše crtanje:

ZADATAKZADATAK

(^4) 4.

Za sustav prikazan blok-dijagramom odrediti AFK i FFK i dati prikaz u Nyquistovom dijagramu

.

x

u

x

i

2

s 3

K

1

s 2

1

1

s

1 +

K=10^ K=

G(s)

G(

ω = j

G

B

N

ϕ = ϕ

− ϕ

3

2

6s

13s

9s

(2s

1)(3s

2)(s

2

3

ω

ω −

ω

j

3

2

ω

ω

ω +

j

j

j

6

4

2

ω

ω

ω

2

2

3

2

ω

ω −

ω

AFK

N

= −ϕ

3

2

arctg(

ω −

ω

ω

FFK