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Practice paper – Set. 2 A Level Biology B (Advancing Biology) H422/03 Practical skills in biology MARK SCHEME
Typology: Exams
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A Level Biology B (Advancing Biology) H422/03 Practical skills in biology MARK SCHEME Duration: 1 hour 30 minutes
This document consists of 19 pages MARKING INSTRUCTIONS PREPARATION FOR MARKING SCORIS
Crossed Out Responses Where a candidate has crossed out a response and provided a clear alternative then the crossed out response is not marked. Where no alternative response has been provided, examiners may give candidates the benefit of the doubt and mark the crossed out response where legible. Rubric Error Responses – Optional Questions Where candidates have a choice of questions across a whole paper or a whole section and have provided more answers than required, then all responses are marked and the highest mark allowable within the rubric is given. Enter a mark for each question answered into RM assessor, which will select the highest mark from those awarded. (The underlying assumption is that the candidate has penalised themselves by attempting more questions than necessary in the time allowed.) Multiple Choice Question Responses When a multiple choice question has only a single, correct response and a candidate provides two responses (even if one of these responses is correct), then no mark should be awarded (as it is not possible to determine which was the first response selected by the candidate). When a question requires candidates to select more than one option/multiple options, then local marking arrangements need to ensure consistency of approach. Contradictory Responses When a candidate provides contradictory responses, then no mark should be awarded, even if one of the answers is correct. Short Answer Questions (requiring only a list by way of a response, usually worth only one mark per response) Where candidates are required to provide a set number of short answer responses then only the set number of responses should be marked. The response space should be marked from left to right on each line and then line by line until the required number of responses have been considered. The remaining responses should not then be marked. Examiners will have to apply judgment as to whether a ‘second response’ on a line is a development of the ‘first response’, rather than a separate, discrete response. (The underlying assumption is that the candidate is attempting to hedge their bets and therefore getting undue benefit rather than engaging with the question and giving the most relevant/correct responses.) Short Answer Questions (requiring a more developed response, worth two or more marks) If the candidates are required to provide a description of, say, three items or factors and four items or factors are provided, then mark on a similar basis – that is downwards (as it is unlikely in this situation that a candidate will provide more than one response in each section of the response space.) Longer Answer Questions (requiring a developed response) Where candidates have provided two (or more) responses to a medium or high tariff question which only required a single (developed) response and not crossed out the first response, then only the first response should be marked. Examiners will need to apply professional judgment as to whether the second (or a subsequent) response is a ‘new start’ or simply a poorly expressed continuation of the first response.
The lower mark should be awarded where the level descriptor has been evidenced but aspects of the communication statement (in italics) are missing. In summary:
Mark Scheme H422/03 Practice Paper – Set 2
(ii) (chymosin is a) mammalian enzyme (so) active / works best , at 37oC 37 oC / optimum temperature , is in the middle (of the range chosen) max 2 IGNORE ruminant (b) Suggestion: pH should be , controlled / the same Reason: ensures pH is constant therefore does not , affect enzyme activity / alter enzyme structure Suggestion: same concentration of , enzyme / chymosin Reason: increase in enzyme concentration will , speed up the reaction / clotting process Suggestion: same type of milk used Reason: different types of milk may have different concentration of , protein / substrate Suggestion: same concentration of , milk / substrate , used Reason: increase in concentration will , speed up the reaction / clotting 4 Correct reason MUST be linked to the suggestion ALLOW chymosin works at low pH found in stomach ALLOW ORA Question Answer Marks Guidance process ALLOW ORA
(c) (i) idea that the reaction could still continue if not enough inhibitor is used idea that too much inhibitor could affect the quality of the final product idea of increased cost to commercial cheese producers if more inhibitor is used than needed to stop the reaction 2 max (ii)* Summary of instructions to markers: Read through the whole answer. (Be prepared to recognise and credit unexpected approaches where they show relevance.) Using a ‘best-fit’ approach based on the science content of the answer, first decide which of the level descriptors, Level 1 , Level 2 or Level 3 , best describes the overall quality of the answer. Then, award the higher or lower mark within the level, according to the Communication Statement (shown in italics): o award the higher mark where the Communication Statement has been met. o award the lower mark where aspects of the Communication Statement have been missed.
**_- The science content determines the level.
Question Answer Marks Guidance is mostly relevant. Level 1 (1–2 marks) The apparatus and an outline method are suggested but information may be missing to provide reliable results. There is limited reference to variables and how they are controlled. The information is communicated with only a little structure. Communication is hampered by the inappropriate use of technical terms. 0 marks No response or no response worthy of credit. transparent
(ii) curve / line , starts at the same point 1 ALLOW ECF from 1(d)(i) if identified as competitive inhibitor Question Answer Marks Guidance AND is the same shape as sketch graph AND curve / line , levels out / plateaus , at a lower rate of reaction than sketch graph Total 17
Question Answer Marks Guidance 2 (a) (i) meiosis 1 DO NOT ALLOW mitosis ALLOW meiosis 1 (ii) anaphase 1 1 ALLOW telophase 1 ALLOW anaphase OR telophase if 2(a)(i) states meiosis 1 (b) X follicle cells / follicular tissue / corona radiata Y cytoplasm / yolk Z zona pellucida / layer of, glycoproteins / gel 3 DO NOT ALLOW ‘follicle’ (c) on photomicrograph where no sperm are present: germ layer absent no cells close to basement membrane lumen largely empty/proliferation of Leydig cells (purple stained cells between seminiferous tubules) max 2 ORA throughout (d) to stain different tissues/cell types different colours allows viewer to differentiate between, tissues/cell types max 1 ALLOW means untrained viewer can tell cells/tissues apart OWTTE
(e) (i) x-axis labelled ‘days from start of treatment’ AND scale occupies more than 50% of paper AND scale with equidistant points AND zero/0 correctly shown y-axis labelled ‘mean sperm count (million per cm^3 )’ AND scale occupies more than 50% of paper AND scale with equidistant points (^4) Days from start of treatment Mean sperm count (million per cm^3 ) 0 25 30 35 60 44 90 60 120 69 Question Answer Marks Guidance all points correctly and clearly plotted straight line of best fit (l.o.b.f.) (ii) decrease in variability over time 1 ALLOW variability among patients decreases (with time) (iii) 3.7 x 10^5 cm-3^ day-1^ 2 Correct answer with correct sig fig but wrong unit = 1 mark Correct answer with wrong sig fig but right unit = 1 mark ACCEPT answer in range 3.5 to 3.8 x 10^5 ALLOW million per cm^3 per day ALLOW correct answer not in standard form Total 15 Question Answer Marks Guidance 3 (a) (i) light dependent (reactions) 1 ALLOW Hill reaction
(ii) (it acts as an) electron acceptor 1 ALLOW reduced (iii) maintains (chemical) activity of chloroplasts 1 ALLOW references to maintaining pH in context of (chemical) activity of chloroplasts (b) (i) red 1 (ii) 3 consecutive readings of same value (in test tube E) 1 ALLOW the reaction had stopped in (test tube) E (iii) chloroplasts physically damaged during preparation of leaf extract photosystems / chlorophyll present in supernatant other reducing agents / AW present in supernatant max 2 DO NOT ALLOW any suggestion of chemical damage Total 7
Question Answer Marks Guidance 4 (a) Stage 2 DNA is being denatured / 2 strands separate (by H-bonds breaking) Stage 3 primers, anneal / bind, to complementary strands (of DNA)
ALLOW DNA is being annealed (b) (i) (Taq DNA polymerase / it) catalyses the addition of nucleotides (to the primers) to form DNA strands / polynucleotides 1 ALLOW extends the DNA from the primers (allowing for the formation of cDNA strands) ALLOW makes double stranded DNA from single stranded DNA template (ii) (Taq DNA polymerase / it is) not (thermally) denatured by the high temperatures needed to separate the DNA strands / at 90°C
IGNORE optimum at ~70°C (c) (i) 1 x 10^9 (a.u) 1 DO NOT ALLOW 1000 000 000 ALLOW answers in range 5x10^8 to 2.5x10^9 (ii) log(arithmic) 1 Total 7
Question Answer Marks Guidance 5 (a) Summary of instructions to markers: Read through the whole answer. (Be prepared to recognise and credit unexpected approaches where they show relevance.) Using a ‘best-fit’ approach based on the science content of the answer, first decide which of the level descriptors, Level 1 , Level 2 or Level 3 , best describes the overall quality of the answer. Then, award the higher or lower mark within the level, according to the Communication Statement (shown in italics): o award the higher mark where the Communication Statement has been met. o award the lower mark where aspects of the Communication Statement have been missed.
**_- The science content determines the level.
Level 3 (5-6 marks) There is a comprehensive consideration of regions of the graph which are accurately explained in relation to stomatal aperture size. The adaptive significance of the conductance pattern is discussed in relation to transpiration and photosynthesis. There is a well-developed line of reasoning which is clear and logically structured and uses scientific terminology at an appropriate level. All the information presented is relevant and forms a continuous narrative. Level 2 (3-4 marks) There is some consideration of regions of the graph which are correctly linked to stomatal aperture size. A discussion of the adaptive significance of the conductance pattern is attempted and may consider transpiration or photosynthesis. There is a line of reasoning presented with some structure and use of appropriate scientific language. The information presented is mostly relevant. Level 1 (1–2 marks) Stomata are identified as the structures which will alter conductance values. An attempt is made to link stomatal opening with the correct times of day. There is little consideration of the adaptive significance of the patterns of conductance. 6 Indicative scientific points may include Changes in the leaf
(b) Advantages (up to a maximum of 2 marks) Line transect enables Spearman’s rank to be used to measure correlation unbiased as only those plants touching the line are sampled straightforward – no estimation of (number or area of) sub-regions easily repeatable Stratified sampling more representative of sub-regions Disadvantages (up to a maximum of 2 marks) Line transect only plants touching the line should be sampled which may lead to ‘gaps’ in the data strategy for choosing a plant nearest to the sampling point may lead to bias Stratified sampling requires (accurate) estimation of area of sub-regions time consuming distance from road must be measured at each sampling point (time consuming because) target species may be absent in randomly selected area 4 DO NOT ALLOW double marks for statements reversed for the other method ALLOW ORA for any point as long as no double marks e.g. a disadvantage of stratified sampling is that it is less easily repeatable DO NOT ALLOW any suggestion that repeats are done on the same transect Question Answer Marks Guidance
5 (c) (i) 0.7 2 ALLOW 0. If answer is incorrect or missing: ALLOW 1 mark for 0.3 OR 0.25 (not subtracting the calculated figure from 1) Species n n/N (n/N)^2 A 2 0.13 0. B 6 0.40 0. C 2 0.13 0. D 2 0.13 0. E 3 0.20 0. ∑( n/N)^2 = 0. 1 - 0.2507 = 0. 5 (c) (ii) (higher biodiversity) in the Succulent Karoo shows greater species evenness / less dominated by a few species / greater stability (higher biodiversity) in the Succulent Karoo shows greater species richness / greater number of different species
ALLOW ORA throughout Total 14