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Problems with Solution for University Physics I | PHYS 2050, Exams of Physics

Material Type: Exam; Professor: Kaldon; Class: University Physics I; Subject: Physics; University: Western Michigan University; Term: Summer 1 2006;

Typology: Exams

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X2.17a

PHYS-205(17) (Kaldon-20619)

Name

_________S

O L U T I O

N_______

Exam 2A - 100,000 points + 20,000 WMU-Summer I 2006



points Book Title __________________________________________

06/04/2006•Rev.

State Any Assumptions You Need To Make – Show All Work – Circle Any Final Answers

Use Your Time Wisely – Work on What You Can – Be Sure to Write Down Equations

Feel Free to Ask Any Questions



2a



2b



2c



2e

EXAM 2 [FORM - A]

PHYS-2050 (KALDON-17)

SUMMER I 2006

WMU

If F=ma,

then does F²=mama?

Physics 2050 / Exam 2 [Form-A]

Summer 2006

Page 2

(b) The weight of the loaded elevator at rest is 10,500 N. With what force must the guy pull on the rope? Assume all the cable tensions are the same. a rope. Draw the Free Body Diagram of the loaded elevator car at rest. 1.) (a) A cargo elevator at an open mine shaft is being pulled on by means of Problem One – “The One That Goes Up and Down” (35,000 points)

F

T

w

T

w

T

w

N

N

y

















0

1

1

1

,

.

(c) If the elevator is to be lowered at 1.11 m/s², with what force must the guy pull on the rope?

w

mg

m

w g

N

m

s

kg

F

T

w

ma

T

w

ma

T

w

ma

N

kg

m

s

N

y

y

y

y

 















     



2

1

1

1

2

,

.

/

.

,

.

.

/

b

gc

h

(d) If the elevator is to be lowered at 1.11 m/s, with what force must the guy pull on the rope?

F

T

w

T

w

T

w

N

N

y

















0

1

1

1

,

.

Same answer as (b)!

Physics 2050 / Exam 2 [Form-A]

Summer 2006

Page 3

(e) If there was

no

air resistance, then the elevator would be in free fall the whole way. Use conservation

of energy to find the speed of the elevator after it has fallen 933 meters.

NOTE: Missing part of the sentence here! If the cable breaks and there was

no

air resistance…

mgh

mv

mgh

mv

mgh

mv

gh

v

v

gh

v

gh

m

s

m

m

s

1

21

1 2

2

21

22

1

21

22

1

21

22

2 2

1

2

1

2



















.

/

.

/

c

hb

g

NOTE: OK if student starts with v

1

= -1.11 m/s from part (d) rather than from rest…

mgh

mv

mgh

mv

h

mgh

mv

mv

gh

v

v

v

gh

v

v

gh

v

m

s

m

m

s

m

s

1

21

12

2

1

2

2 2

2

1

21

12

21

22

1

21

1 2

21

22

2 2

1

1 2

2

1

1 2

2

2

0

2

2 2 9 81

933

111

135 3



























 



;

.

/

.

/

.

/

c

hb

g b

g

Physics 2050 / Exam 2 [Form-A]

Summer 2006

Page 4

2.) Problem Two – “The One With The Star Problems” (30,000 points)



(a) A small red ball (mass

m = 0.200 kg

) is moving to the right with a speed 10.0 m/s at time zero.

It is attached to an elastic cord which applies a force to the left with



F

C x i

elastic

 



. Find the distance

d

it takes the ball to come to a stop, where

x

0

= 0

and the coefficient of the cord is

C = 5.00 N/m

, using

work and energy.

K

mv

kg

m

s

J

W

F ds F dx

Cx dx

C

x dx

C

x

Cd

W

K

K

K

J

Cd

J

Cd

d

J

C

J

N

m

d

J

N

m

m

x

d

d

d

d

f

i

















 

 

 







 

 











z

z

z

z

21

2

21

2

0

0

0

2

0

2

2

2

2

.

.

/

.

.

.

.

.

.

/

.

.

/

.

b

gb

g

b

g

b

g







An object of mass

m = 12.0 kg

begins its motion with the following equation. All other constants are

zero.

(b) Find the force,

F

, acting on this object at time

t = 1.00 sec

.

a

d

x

d t

m

s

t

F

ma

kg

m

s

t

kg m

s

t

F t

kg m

s

N





















2

2

6

4

6

4

6

4

6

4

(

.

/

)

.

(

.

/

)

(

.

/

)

(

.

sec)

(

.

/

)

.

sec

.

b g b g d x

d t

m

s

t

2

2

6

4

12 0



(

.

/

)

Physics 2050 / Exam 2 [Form-A]

Summer 2006

Page 5



(c) A block of mass

m = 1.00 kg

starts out at rest at a position

x

0

= 4.00 meters

, and moves with a force

F

t

t

x

N

s

( )

.



2

2

d

i

. Find the position

x

of the block after 5.00 seconds.

Assume any other constants

are zero.

F

t

t

F

ma

a

F

m

t

kg

m

s

t

d td x

v

d x d t

d td x

dt

m

s

t

dt

m

s

t

C

C

x

d x d t

dt

m

s

t dt

m s t C C x m

m

s

t

x

sN

x

x

x

x

N

s

x

( )

.

.

.

.

/

.

/

.

/

(

)

.

/

.

/

(

.

)

.

/



 



































z

z

z

z



0

2

2 2

2

4

2

2

2

2

2

4

2

31

4

3

31

4

3

1

3 4

4

4

0

4

4

d

i

d

i

c

h

c

h

c

h

c

h

c

h

c

h

.

(

.

sec)

.

/

.

sec

.

00

4

4

m

x t

m

s

m

m









c

hb

g

carts ( (d) Jerry is putting grocery carts away at Meijer. He takes one of the

m = 10.2 kg

) and gives it a shove so it is traveling at 4.75 m/s.

just sitting there. Find the speedIt crashes into and sticks with a group of five grocery carts that were

V

of the new group of grocery carts.

p

p

m v

m v

m v

m v

m v

m v

m m m m m m

m V

mv

mV

V

mv

m v m s m s

before

after



           













1 1 2 2 3 3 4 4 5 5 6 6 1 2 2 3 4 5 6

0

b

g

.

/

.

/

Physics 2050 / Exam 2 [Form-A]

Summer 2006

Page 6



(e) An object of mass 1.00 kg has a motion that follows the following equations. Find the magnitude

K

of the kinetic energy of the object at time

t = 0

and

t = 10.0 seconds

. Then find how much Work was

done to move the object – It Won’t Take Calculus for this last bit.

x t

m

m

s

m

s

( )

.

.

/

.

/







2

3

t

t

2

3

x t

m

m

s

m

s

v

d td x

d

d t

m

m

s

m

s

m

s

m

s

m

s

m

s

v tv

m

s

m

s

m

s

K K

mv

i

f

( )

.

.

/

.

/

.

.

/

.

/

(.

/

)

(5.

/

)

(. / ) (. / )

( ( )

. sec)

(

.

/

)

. sec)

(

.

/

)

. sec)

.

/

































 







0

00

0

0

0

2

3

2

3

2

3

2

3

2

3

21

2

t

t

t

t

t

t

t

t

(

(

2

3

2

3

2

2

2

c

h

21

2

0

.

.

/

,

,

,

kg

m

s

J

W K K K J J

f

i

b

gb

g





     



Physics 2050 / Exam 2 [Form-A]

Summer 2006

Page 7

3.) Frida has to get a refrigerator ( Problem Three – “The One With All The Angles” (35,000 points)

m = 135 kg

) loaded onto a truck, using a

speed.find (a) the force needed to push the refrigerator up the ramp at a constantramp that is angled at 22°. If the refrigerator glides on frictionless rollers,

F

F

w

F

w

mg

kg

m

s

N

x

x

x

























1

1

2

0

. sin

/

sin

.



b

gc

h

(b) The ramp is 1.50 m tall, while the angled part is 4.00 m long. Show that the work to raise the

refrigerator 1.50 m is the same as the work in pushing the refrigerator up the slope without friction.

W

mgh

kg

m

s

m

J

W

Fd

N

m

J













2

b

gc

hb

g

b

gb

g

.

/

.

.

.

(c) If the elevator did

not

have the rollers, that it could sit on the ramp and be held in place by static

friction without being held by Frida. Find the

minimum

coefficient of static friction,



s

.

F

F

w

F

F

w

F

F

w

w

mg

mg

mg

mg

y

N

y

x

f

s

x

f

s s N s y x

s s













 



























 

0

0

, ,max

, ,max

cos

sin

sin

cos

tan

tan

.



















Physics 2050 / Exam 2 [Form-A]

Summer 2006

Page 8

the maximum force Frida can push the stopped refrigerator without having it move up the ramp?(d) The actual coefficients of friction between the refrigerator and the ramp are 0.857 and 0.657. What is

F

F

w

F

w

F

F

F

w

F

F

w

w

w

mg

mg

mg

kg

m

s

N

y

N

y

N

y

x

f

s

x

f

s

x

s

y

x

s

s

















 









































0

0

1

1

2

;

cos

sin

cos

sin

.

/

.

cos

sin

, ,max

, ,max

 











b

g

b

gc

h b

g

c

h

constant speed with friction? (e) What is the force that Frida needs to apply to the refrigerator to get it up the ramp if is sliding at a

F

F

w

F

w

F

F

F

w

F

F

w

w

w

mg

mg

mg

kg

m

s

N

y

N

y

N

y

x

f

k

x

f

k

x

k

y

x

k

k

















 









































0

0

1

1

2

;

cos

sin

cos

sin

.

/

.

cos

sin

,

,

 











b

g

b

gc

h b

g

c

h