Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
Community
Ask the community for help and clear up your study doubts
Discover the best universities in your country according to Docsity users
Free resources
Download our free guides on studying techniques, anxiety management strategies, and thesis advice from Docsity tutors
Step-by-step solutions for quiz 4 in physics 1112, focusing on finding the current in a parallel resistor and the power dissipated in a resistor in a circuit. It includes calculations for collapsing the circuit, finding equivalent resistances, and determining current and power.
Typology: Quizzes
1 / 1
Physics 1112 CRN 87210 Quiz 4 Name
(a) the current in the 50 ohm resistor SHOW ALL WORK (b) the power dissipated in the 100 ohm resistor. SHOW ALL WORK First, collapse the circuit to a battery and an effective resistance... The 50 Ω resistor and 80 Ω resistor are in parallel. 1 50 +
Ref f Ref f = 30.77 Ω Now, the 30 Ω, 100 Ω, and the 30.77 Ω resistors are all in series.
Ref f = 30.77 Ω + 100 Ω + 30 Ω Ref f = 160.77 Ω
That current travels through the 30 Ω, 100 Ω, and 30.77 Ω resistors. So,
P = I^2 R = (0. 0933 A)^2 (100 Ω) = 0. 870 W Now, determine the voltage across the 30.77 Ω resistor...
V = IR = (0. 0933 A)(30.77 Ω) = 2. 87 V
That voltage is across both the 50 Ω and 80 Ω resistors.
V = IR (2. 87 V ) = I(50 Ω) I = 0. 0574 A