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Class: PHYS - Physics 3 - Advanced; Subject: Physics; University: Universidad Virtual del Tecnologico de Monterrey; Term: Forever 1989;
Typology: Quizzes
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DEFINITION 10 So, this is one of the formulas for velocity. It means:Total energy = gravitational potential energy + kinetic energy= mass times gravitational acceleration times height from the surface of the earth + of mass times velocity squared = gravitation acceleration times height 1 - gravitational acceleration times height 2 = velocity squared
Although, this is an amazing recourse to look at the technology is fairly new and is almost impossible to collect any data on how it was made or how it works similarly to all other companies that have created similar softwares. This means it wasnt much use for my experiment other than some inspiration. However, in order to complete this experiment general knowledge on velocity, projectile and gravitational acceleration is required. TERM 17
DEFINITION 17 The velocity of an object is the rate of changing of its position with respect to the frame of reference, and its function of time. Velocity is equivalent to a specification of an objects speed and direction of motion. Velocity is a fundamental concept of kinematics the branch of classical mathematics that describes the motion of bodies. Velocity is closely related to kinetic and potential energy which was crucial elements in this experiment. TERM 18
DEFINITION 18 Kinetic energy is possessed by an object in motion. Kinetic energy is directly proportional to the mass of the object and to the square of its velocity. K.E. = m velocity squared.If the mass has units of kilograms and the velocity of metres per second, the kinetic energy has units of kilograms meters per second squared. Kinetic energy is usually measured in units of Joules. TERM 19
DEFINITION 19 One Joule is equal to 1kg meters sqared per seconds squaredPotential energy is energy an object has because of its position relative to some other object. The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is mass in kilograms, g is the acceleration due to gravity and h is the height in metres. TERM 20
DEFINITION 20 These two energy types can then be used to find the velocity. The physics and mathematics of a projectile is also key in this experiment. A projectile is an object upon which the only force acting is gravity. By definition, a projectile has a single force that acts upon it the force of gravity. If there were any other forces acting upon an object, then that object, would not be a projectile.
Projectile motion of any object is a parabola. The motion of projectiles is analysed in terms of two independent motions at right angles. The horizontal component of the motion is at a constant velocity, while the vertical motion is subject to a constant acceleration due to gravity. The horizontal and vertically movement are the two components of the projectiles motion. Since perpendicular components of motion are independent of each other, these two components must be discussed separately. TERM 22
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DEFINITION 23 When studying projectiles range is often considered. The range of an object in projectile motion I defined as the distance from the point of projection to the point at which the particle reaches the ground again. Subsequent to the study of projectile motion scientists also conducted significant research on the gravitational impact. This research was often discussed through a free-falling object. TERM 24
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I later decided the outcome of this experiment although sophisticated and diverse would be basic knowledge and skills not allowing me to push myself. After speaking to Mr Gove, Mr Johnston, Mr Edwards and Mrs Woodward I decided that my new aim would be to calculate the parabola of a scooter Ollie and determine whether executing a trick mid-air would change the expected and actual landing position. TERM 32
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DEFINITION 33 Soon after this I spoke with Ms Woodward and I decided to model the experiment instead. Initially I was going to use a propeller to simulate the trick however I later decided this would be an added for and my experiment would be invalid. Subsequently to several debates with Science and Mathematics teachers I settled on determining whether changing the distribution of mass on a model car affected the landing distance and relating this to a trick simulation if possible. TERM 34
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Ramps Used During my experiment I used two ramps. I initially decided on one which would be the standard launching ramp used for the projectile however, I realised that in order to keep the velocity prior to the launch off the ramp consistent I would have to use another drop in ramp. I manipulated the blue track to include a second ramp prior to the launching ramp. It consistently stayed exactly 130cm from the ground. This ramp allowed the velocity to stay as consistent as possible allowing the calculations to be more reliable. TERM 37
DEFINITION 37 Release of Car Another implication I used to keep the velocity consistent was how I released the car. I was concerned if I let go of the car, I would apply a force from my hands subconsciously. My solution to this was to place my finger at the edge of the car in the same marked position each time and letting go releasing the car opposed to dropping it. This small design change ensured the velocity was staying accurate. TERM 38
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I believe this is because although the centre of mass didnt change the weight distribution of mass did change slightly impacting the landing position. As the weight is at the front theoretically the nose of the car should land first due to the gravitational force on the weight. This experiment however was impacted by the interruption of the metal electrical box running along the edge of the wall. TERM 47
DEFINITION 47 This impacted the results as the projectiles that should have had a longer distance were interrupted affecting its landing position. This is what differentiates the second test from the first. As the second test didnt have the interruption the projectiles that should have gone further went further creating a larger distance between the results. There is a consistent trend through the two results however, being that the runs with the mass uncentred generally didnt travel as far. TERM 48
DEFINITION 48 Unfortunately, I cannot relate this experimental design to the scooter trick as the centre of mass doesnt change, there isnt weight distribution change in a scooter trick and the model just didnt generally represent this. In future I would like to code a propeller that spun around on release of the launch point to simulate the trick however, I wasnt able to execute this in the time given. TERM 49
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