Thermodynamic Parameters - General Chemistry - Solved Quiz, Exercises of Chemistry

Download Thermodynamic Parameters - General Chemistry - Solved Quiz and more Exercises Chemistry in PDF only on Docsity! 1. 6 pts. Using the table of thermodynamic parameters provided, calculate the enthalpy change for the following reaction: (g) O 5 (g) NH 4 (g) O H6 (g) NO 4 232 +⎯→⎯+ kJ/mol 906.2)6(-241.826 - 4(90.29) - 5(0)(-45.9) 4 H =+=∆ The sign is positive which means that heat is consumed. This means that if 4 moles of NO react with 6 moles of water, 906.2 kJ of heat will be consumed. 2. 2 pts. If 1.00 mole of NO reacts completely with water vapor (as in the reaction above) how many kJ of heat would be transferred in the process? Would the heat be consumed or released? kJ 226.6NO mol 0.1 NO mol 4 rxn mol 1 rxn mol kJ 906.2 =⋅⋅=q The heat is consumed. 3. 2 pts. The heat capacity of ice is 2.1 J/g-K. How many J of heat would be needed to warm 12 grams of ice from -10.0 oC to -5.0 oC? T)((mass)capacity)heat ( ∆⋅⋅=q J 126(5.0)(12)2.1) ( =⋅⋅=q Docsity.com