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UGA PHYSICS 1111 LAB FINAL EXAM QUESTIONS AND ANSWERS.docx

Typology: Exams

2024/2025

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Download UGA PHYSICS 1111 LAB FINAL EXAM QUESTIONS AND ANSWERS.docx and more Exams Physics in PDF only on Docsity! UGA PHYSICS 1111 LAB FINAL EXAM QUESTIONS AND ANSWERS LAB 1 INTRO LAB EXCERCISE -Study Error -Precision -SIG FIGS -Construction of Graphs -How to use air track measurement system for motion exercises - answer ... LAB 1: error & accuracy & %error & diff - answer -Error: diff between value of physical quantity determined by experiment and true value -Types of error may occur during an experiment: experimentalist not take the time to be as accurate & detailed -Accuracy: percentage diff or absolute diff -Percentage Error = (Estimated- Actual)/ (Actual) x 100 Percent difference= (value 1 - value 2/ ((value 1 + value 2)/2)) * 100 LAB 1- precision - answer -related to way u carried out measurements & how u reported ur results -precision of a number indicated by # of sig figs used LAB 1: air track continued sources of friction slowing glider down - answer -air resistance -friction from hitting bumpers lab 1: air track continued cause glider to accelerate even after you let go (ignore friction) - answer - add more air once glider in motion -tilting air track lab 1: air track continued yellow ruler stip on air track measures - answer distance between two successive placements on glider lab 1: air track continued what do ur results say ab accuracy of motion detector? - answer -affects time & position based on where it started lab 1: air track continued orientation of motion detector - answer oriented up: detect motion stop metal plate which skews data oriented down: motion might affect data bc of glider LAB 2: = -measure accel of object sliding down inclined plane & deduce accel due to gravity from data - answer ... LAB 2: (equation) if initial coordinate of object is x0 then later time (t) - answer x=x0 + v0t + 1/2at^2 Lab 2: (equation) velocity is the object at any time: - answer v=v0 + at LAB 2: third useful equation - answer v^2 = v0^2 + 2a(x-x0) LAB 2: Meanings of A, B, and C - answer y=C + Bt + At^2 A=1/2 of the accel (m/s^2) B= Initial velocity (m/s) C= initial postion (m) LAB 2: Q4: are the numbers obtained for B and C reasonable? explain - answer yes bc they should both be close to zero LAB 2: Q5: deduce G - answer g= a/(sin(theta)) LAB 2: object's position as function of time, graph linear & object's acceleration? - answer zero LAB 3: EQUILIRIBRIM OF A POINT MASS procedure - answer static equilibrium of object w/ mass under concurrent forces LAB 3: two conditions met when body is equilibrium - answer 1) vector sum of all forces acting on object must = zero 2) sum of all the torques acting on object must = zero LAB 3: What is a concurrent force? - answer lines of action all intersect at common pt LAB 3: Vector addition - answer graphical and analytical LAB 3: Vector addition: graphical - answer LAB 3: drawing vectors: length of arrow proportional to magnitude of vector. - answer TRUE LAB 3 adding two vectors graphically resultant can be determined by using Pythagorean theorem. - answer TRUE LAB 3: Once the x and y components of a resultant found analytically, the direction of resultant can be determined using arctangent function - answer TRUE LAB 3: Which of the following vectors are the resultant of adding vectors A and B? A= 2.7N @ 48 deg, B=4.N @ 201 deg - answer vector a: x-component: 2.7cos(48) y-component: 2.7sin(48) vector b: x-component: 4.1cos(201) y-component: 4.1sin(201) add a's x component + b's x component add a's y + b's y sqrt(sum of a and b's x component)^2 + sum of a and b's y component^ answer for ^ that = magnitude answer for degrees part (sum of a and b's y component / sum of a and b's x-component) LAB 4: Newton's second law - answer measure mass in motion on leveled air track F=MA LAB 4: measuring accel & not tension of masses & tension in string connecting them (equation) - answer a= m2/ m1 + m2 LAB 4: Procedure - answer -Level air track -Perform initial motion measurements using a 10-gram mass on glider. -Practice moving glider, then collect data w/a motion detector & computer while allowing glider to move from maximum stretch of string to its first bounce. - Analyze data w/curve-fitting tool to Q3: avg accl meaurements - answer avg=1/2(a'+a'') = m2g/m1+m2 a' means case 1 a'' means case 2 LAB 4 Q4: Is a leveling air track necessary for accurate measurements in procedure 4 - answer yes and no yes, ensures only acc acting on glider is due to forces specifically apply for exp LAB 4: why is a' - a'' most useful for friction force? - answer Shows magnitude of friction force LAB 5: Procedure: uniform circular motion- obseve dynamics of object moving circular path. ar=v^2/R - answer LAB 5: Q1 radial force depends on square of rotation of speed (force vs radius graph) - answer results in a line, a positive linear correlation LAB5: Q2: quantity described by slope of F vs v^2 graph - answer mass over radius m/r is the slope LAB 5: Q3: vertical intercept on calculated mass vs # of mass graph - answer initial weight of carriage prior to adding mass LAB5 : Q4 What does a linear relationship mean for calculated data v radius of rotation? significance of mass ratio (energy compared to mass)? - answer Direct correlation between the radius and calculated data. When radius increases, so does the calculated data it represents the law of conservation of mass LAB5 LAB 5: dont stuy - answer this shut LAB 6: PROCEDURE - answer mass (m) approaches stationary (m') w velocity a completely inelastic collision takes place & combined masses (m + m') swing upwards max height (y) above initial position m' free flight procedure -Swing pendulum, set apparatus near table edge, load and fire gun to mark projectile strike on floor. -Cover impact point with white paper and carbon paper; secure with tape or weights. -Fire gun 5x, measure range -Record distance of vertical fall for each flight. -Calc initial velocity ballistic pend procedure -Set pendulum to catch projectile; observe highest swing. -Fire gun, record pendulum's max height five times. -Compute pendulum's average height change. -Calculate projectile's pre-collision speed; measure masses if unknown. LAB 6: equation for momentum conservation: - answer mv= (m + m')V LAB 6: primary objective of this experiment is to use two different methods to calculate _____________ of a projectile fired by a ballistic pendulum. - answer INTIAL VELOCITY LAB 6: ballistic pendulum: How fast were objects moving right a\fter collision? - answer turn cm to m. cm divide 1000 to m v = sqrt 2 x g xh LAB 6: ballistic pendulum: How fast ball moving initially? - answer v1=(m1 + m2)V/m1 LAB 6: Ki = 2Kf Lab 8: elastic collision- what happened to left glider after collision? why? - answer -velocity changed direction -magnitude of velocity dec bc lost momentum -not true elastic col. bc KE not conserved LAB 8: unknown mass- after collision, what happened to speed of more massive glider - answer speed dec LAB 8: after collision, is speed of less massive glider larger or smaller than the initial speed of the more massive glider - answer speed of less massive is larger LAB 8: value of unknown mass - answer m1v1=m1vf+m2v2f LAB 8: caused errors of unknown mass - answer -air track not leveled -force used LAB 8: speeds & directions of each glider before & after the collision - answer -smaller mass hits larger mass = velocity inc more LAB 8: inelastic collision, ________ is conserved, but _______ is not. - answer Momentum KE LAB 8: quantities conserved in elastic collision: - answer KE and momentum LAB 8: collisions: magnitude of object's momentum? - answer Mass x Velocity LAB 8: collisions: magnitude of object's kinetic energy? - answer 1/2 X Mass X Velocity^2 static equilibirum: what is shortest wrench you would need to tighten the lug nuts to specifications? - answer L=TORQUE/Force - Lab 9 Is there a point on the meter stick where the sum of torques not be zero? - answer yes=meter stick isn't balanced around center of mass LAB 9: SITUATIONS YOU HAVE ENCOUNTERED OUTSIDE OF LAB THAT IVOLVE TORQUE - answer SEESAW: rotating around central point w center of gravity WRENCH: rotating around central point where force applies LAB 10: simple harmonic motion PROCEDUE restoring force=system back to equilbirum - answer -mass excutes vibratory motion under force proportional to displacement OF mass from equilbirum position -mass on end of string properties: Restoring force MUST act on body System MUST HVAE mass LAB 10: why do all peaks in graph get smaller as the time inc - answer friction from bumpers & glider wants to get equilibrium LAB 10: WHY DOES SHM TAKE PLACe - answer conservation force LAB 10: object right of spring's equilibrium, spring's restoring force will... - answer ACT TO LEFT Lab 10 SHM: spring constant k equation - answer f/x LAB 10: EQUATIONS: - answer period? T(period)= 2PIsqrt m/k wavelength of standing wave pattern - answer wavelength=2L/n lab 11: speed of waves traveling along the string? - answer solve for wavelength THEN wave speed: (c) c= HZ x wavelength answer - Lab 11 variables - answer cursive L=distance of 1 nodes wavelength= 2 x L tensionFt=mg