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University Physics I - Examination 1 | PHYS 2050, Exams of Physics

Material Type: Exam; Professor: Kaldon; Class: University Physics I; Subject: Physics; University: Western Michigan University; Term: Spring 2002;

Typology: Exams

Pre 2010

Uploaded on 07/28/2009

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PHYS-205(H9) (Kaldon-28632)

Name ______________________________________________

Exam 1 - 100,000 points + 20,000WMU - Winter 2002

(^)  (^) points

Book Title __________________________________________

1/29/2002•Rev.

State Any Assumptions You Need To Make – Show All Work – Circle Any Final Answers Use Your Time Wisely – Work on What You Can – Be Sure to Write Down Equations

Feel Free to Ask Any Questions



2a



2b



2c



2e

PHYS-205(H9) EXAM 1

Slot Cars!

Physics 205 (H9) / Exam 1

Winter 2002

Page 2

Rock-Em, Sock-Em Slot Cars

(50,000 points)

and the launch/landing heights are the same, what is the angle(c) The big new feature that came out one year was putting a jump into the kit. If the gap is 40.0 cm wide(b) If it takes 4.02 meters for the slot car to get up to speed from rest, what is the acceleration of the car?slot car to race around the track one time at this speed?might have 60.0 feet of track (18.3 meters) and cars traveling at 8.88 m/s. (a) How long does it take for aguide pin that stuck down into the plastic roadway so they’d (mostly) stay on the road. A typical setup 1.) When Dr. Phil was a kid, some of his friends had HO-scale slot cars – little toy electric cars with a



(^) of

the ramp, if

(^) v (^0) = 8.88 m/s

?

NOTE: If you cannot solve this

problem directly, try solving part (d) first using v

0x (^) = 8.88 m/s,

(d) How much time does it take the slot car to cross the 40.0 cm gap? and take a 2000 point penalty.

See the NOTE in part (c).

centripetal acceleration, (e) Zipping along at 8.88 m/s, the slot car goes around a curve of radius 18" (45.7 cm). Find the

(^) a c , of the car.

Physics 205 (H9) / Exam 1

Winter 2002

Page 3

“Can You Survive FOX-TV’s New Show

(^) The Star Problem Chamber

?”

(50,000 points)

2.) An equation of motion is based on the fourth derivative:

(^) d y dt

m s

t

m s

m

s t

4 4

5

(^4)

(^7) 3









.. / (. / ).

And all other

(^) y -component constants are zero.



(a) Find the equation for the

(^) y -component of the

acceleration,

(^) a y , of this object.



(b) Find the equation for the

(^) y -component of the velocity,

(^) v y (^) , of this object.



(c) Find the equation for the position,

(^) y , of this object.

Physics 205 (H9) / Exam 1

Winter 2002

Page 4

(d) If

(^) a x = 5.25 m/s²

(^) , find the vector acceleration,

(^) a  (^) , in Standard Form for the time

(^) t = 1.01 seconds

.

If

you did not get answers to (a), use

(^) a 

m s t j

y  

(.

/

)



(^5) (^3) .



(e) Find the value of the seventh derivative,

dt^ d y 7 7 , at time

(^) t = 1.01 seconds

.

dt^ d y

t (^) m s

m s

m s t

4 4

5

(^4)

(^7) 3









.. / (. / )