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P1 V1 T1

State 1

P2 V2 T2

State 2

P V n

constant

Polytropic process

We have a total of 7 unknowns. 3 in state 1, 3 in state 2, and n, the polytrpoic process exponent. If given any 5 out of these 7, then the remaining 2 can be found. For example, if we know T1, P1, V1, n, P2, then we can find V2, and T2

Polytrpoic process by Nasser Abbasi polytropic.vsd August 2004

**n=0 const
P
**

**n constant VP
**

**v
**

n=1, const T

n=k, adiapatic, const S

EXPANSION QUADRANT

COMPRESSIONQU ADRANT

Ignore this quadrant in real

engineering equipments

Ignore this quadrant in real

engineering equipments

Initial

state

point

**n=1 const
T
**

**T
**

**s
**

n=0, const P

EXPANSION QUADRANT

COMPRESSIONQU ADRANT

Initial

state

point

**n=k const S
**

Clock wise, n=0,1,k,infinity

Clock wise, n=0,1,k,infinity

**n constant V
**

Ignore this quadrant in real

engineering equipments

Ignore this quadrant in real

engineering equipments

Heat OUT processes

Heat IN processes

Heat IN processes

Heat OUT processes

Process lines to left of adiabatic line means negative Q (i.e. heat OUT), on the right are positive Q (i.e. heat IN) process