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" A. 9.8m/s2 B. 4.9m/s2 C. 2.5m/s2 D. 1.9m/s2 E. 1.1m/s2"26/02/2013
"Venus has a mass of about 0.0558 times the mass of Earth and a diameter of about 0.381 times the diameter of Earth. The acceleration of a body falling near the surface of Venus is about:"
" A. 0.21m/s2 B. 1.4m/s2 C. 2.8m/s2 D. 3.8m/s2 E. 25m/s2"26/02/2013
" A. R2/M B. M/R2 C. MR2 D. M/R E. R/M"26/02/2013
"Let F1 be the magnitude of the gravitational force exerted on the Sun by Earth andF2be the magnitude of the force exerted on Earth by the Sun. Then:"
" A. F1is much greater than F2 B. F1is slightly greater than F2 C. F1is equal to F2 D. F1is slightly less than F2 E. F1is much less than F2"26/02/2013
"A particle might be placed 1. inside a uniform spherical shell of massM, but not at the center 2. inside a uniform spherical shell of massM, at the center 3. outside a uniform spherical shell of massM, a distance rfrom the center 4. outside a uniform solid sphere of massM, a distance 2rfrom the center Rank these situations according to the magnitude of the gravitational force on the particle, least to greatest."
"A. All tie B. 1, 2, 3, 4 C. 1 and 2 tie, then 3 and 4 tie D. 1 and 2 tie, then 3, then 4 E. 1 and 2 tie, then 4, then 3"26/02/2013
"Earth exerts a gravitational force on the Moon, keeping it in its orbit. The reaction to this force, in the sense of Newton’s third law, is: "
"A. the centripetal force on the Moon B. the nearly circular orbit of the Moon C. the gravitational force on Earth by the Moon D. the tides due to the Moon E. the apple hitting Newton on the head."26/02/2013
" A. the mass of the planet B. the mass of the Sun C. the distance between the planet and the Sun D. the reciprocal of the distance between the planet and the Sun E. the product of the mass of the planet and the mass of the Sun"26/02/2013
"A. depends on the local value ofg B. is used only when Earth is one of the two masses C. is greatest at the surface of Earth D. is a universal constant of nature E. is related to the Sun in the same way thatgis related to Earth"26/02/2013
"A shearing force of 50N is applied to an aluminum rod with a length of 10m, a cross-sectional area of 1.0×10−5 m, and a shear modulus of 2.5×10power10 N/m2 . As a result the rod is sheared through a distance of:"
" A. zero B. 1.9mm C. 1.9cm D. 19cm E. 1.9m"26/02/2013
"To shear a cube-shaped object, forces of equal magnitude and opposite directions might be applied:"
" A. to opposite faces, perpendicular to the faces B. to opposite faces, parallel to the faces C. to adjacent faces, perpendicular to the faces D. to adjacent faces, neither parallel or perpendicular to the faces E. to a single face, in any direction"26/02/2013