Math 106: Review for Exam II - Integration Techniques and Applications, Exams of Calculus

Key points of this exam are: Constant, Function, Present, Logarithms, Inverse Trig, Algebraic, Trig, Exponentials, Rational Functions, Polynomial Divided

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2012/2013

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Math 106: Review for Exam II
INTEGRATION TIPS
Substitution: usually let u= a function that’s “inside” another function, especially if du (possibly off
by a multiplying constant) is also present in the integrand.
Parts: Zu dv =uv Zv du or Zuv0dx =uv Zu0v dx
How to choose which part is u? Let ube the part that is higher up in the LIATE mnemonic below.
(The mnemonics ILATE and LIPET will work equally well if you have learned one of those instead;
in the latter Ais replaced by P, which stands for “polynomial”.)
Logarithms (such as ln x)
Inverse trig (such as arctan x, arcsin x)
Algebraic (such as x, x2, x3+ 4)
Trig (such as sin x, cos 2x)
Exponentials (such as ex, e3x)
Rational Functions (one polynomial divided by another): if the degree of the numerator is greater than
or equal to the degree of the denominator, do long division then integrate the result.
Partial Fractions: here’s an illustrative example of the setup.
3x2+ 11
(x+ 1)(x3)2(x2+ 5) =A
x+ 1 +B
x3+C
(x3)2+Dx +E
x2+ 5
Each linear term in the denominator on the left gets a constant above it on the right; the squared
linear factor (x3) on the left appears twice on the right, once to the second power. Each irreducible
quadratic term on the left gets a linear term (Dx +Ehere) above it on the right.
Trigonometric Substitutions: some suggested substitutions and useful formulae follow.
Radical Form pa2x2pa2+x2px2a2
Substitution x=asin t x =atan t x =asec t
sin2x+ cos2x= 1 tan2x+ 1 = sec2x
sin2x=1
2cos(2x)
2cos2x=1
2+cos(2x)
2
sin(2x) = 2 sin xcos x
Powers of Trigonometric Functions: here are some strategies for dealing with these.
Zsinmxcosnx dx Possible Strategy Identity to Use
modd Break off one factor of sin xand substitute u= cos x. sin2x= 1 cos2x
nodd Break off one factor of cos xand substitute u= sin x. cos2x= 1 sin2x
meven AND neven Use sin2x+ cos2x= 1 to reduce to only powers of sinxsin2x=1
2cos(2x)
2
or o nly p owers of cos x, then use table of integrals #39-42 cos2x=1
2+cos(2x)
2
or identities shown to right of this box.
pf3
pf4

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Math 106: Review for Exam II

INTEGRATION TIPS

  • Substitution: usually let u = a function that’s “inside” another function, especially if du (possibly off by a multiplying constant) is also present in the integrand.
  • Parts:

u dv = uv −

v du or

uv′^ dx = uv −

u′v dx

How to choose which part is u? Let u be the part that is higher up in the LIATE mnemonic below. (The mnemonics ILATE and LIPET will work equally well if you have learned one of those instead; in the latter A is replaced by P, which stands for “polynomial”.) Logarithms (such as ln x) Inverse trig (such as arctan x, arcsin x) Algebraic (such as x, x^2 , x^3 + 4) Trig (such as sin x, cos 2x) Exponentials (such as ex^ , e^3 x)

  • Rational Functions (one polynomial divided by another): if the degree of the numerator is greater than or equal to the degree of the denominator, do long division then integrate the result. Partial Fractions: here’s an illustrative example of the setup.

3 x^2 + 11 (x + 1)(x − 3)^2 (x^2 + 5)

A

x + 1

B

x − 3

C

(x − 3)^2

Dx + E x^2 + 5

Each linear term in the denominator on the left gets a constant above it on the right; the squared linear factor (x − 3) on the left appears twice on the right, once to the second power. Each irreducible quadratic term on the left gets a linear term (Dx + E here) above it on the right.

  • Trigonometric Substitutions: some suggested substitutions and useful formulae follow.

Radical Form

a^2 − x^2

a^2 + x^2

x^2 − a^2 Substitution x = a sin t x = a tan t x = a sec t

sin^2 x + cos^2 x = 1 tan^2 x + 1 = sec^2 x sin^2 x =

cos(2x) 2

cos^2 x =

cos(2x) 2 sin(2x) = 2 sin x cos x

  • Powers of Trigonometric Functions: here are some strategies for dealing with these.

sinm^ x cosn^ x dx Possible Strategy Identity to Use m odd Break off one factor of sin x and substitute u = cos x. sin^2 x = 1 − cos^2 x n odd Break off one factor of cos x and substitute u = sin x. cos^2 x = 1 − sin^2 x m even AND n even Use sin^2 x + cos^2 x = 1 to reduce to only powers of sin x sin^2 x =

cos(2x) 2 or only powers of cos x, then use table of integrals #39-42 cos^2 x =

cos(2x) 2 or identities shown to right of this box.

tanm^ x secn^ x dx Possible Strategy Identity to Use m odd Break off one factor of sec x tan x and substitute u = sec x. tan^2 x = sec^2 x − 1 n even Break off one factor of sec^2 x and substitute u = tan x. sec^2 x = tan^2 x + 1 m even AND n odd Use identity at right to reduce to powers of sec x alone. tan^2 x = sec^2 x − 1 Then use table of integrals #51 or integration by parts.

Useful Trigonometric Derivatives and Antiderivatives d dx

tan x = sec^2 x

d dx

sec x = sec x tan x

sec x dx = ln | sec x + tan x| + C

  • Improper integrals: look for ∞ as one of the limits of integration; look for functions that have a vertical asymptote in the interval of integration. It may be useful to know the following limits. lim x→∞ ex^ =

lim x→∞ e−x^ = Note: this is the same as lim x→−∞ ex

lim x→∞ 1 /x = Note: the answer is the same for lim x→∞ 1 /x^2 and similar functions

lim x→ 0 +^

1 /x = Note: the answer is the same for lim x→ 0 +^

1 /x^2 and similar functions

lim x→∞ ln x =

lim x→ 0 +

ln x =

lim x→∞ arctan x =

  1. Evaluate the following.

(a)

sin^6 x cos^3 x dx

(b)

dx √ 100 + x^2

  1. Find the second-degree Taylor polynomial for f(x) =

x centered at x = 100.

  1. What is the maximum possible error that can occur in your Taylor approximation from the previous problem on the interval [100, 110]?
  2. Use comparisons to show whether each of the following converges or diverges. If an integral converges, also give a good upper bound for its value.

(a)

1

6 + cos x x^0.^99

dx

(b)

1

4 x^3 − 2 x^2 2 x^4 + x^5 + 1

dx

  1. The probability density function (pdf) of the length (in minutes) of phone calls on a certain wireless network is given by f(x) = ke−^0.^2 x^ where x is the number of minutes. Note that the domain is x ≥ 0 since we can’t have a negative number of minutes.

(a) What must be the value of k?

(b) What fraction of calls last more than 3 minutes?