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Examples of solving direct variation problems and finding the slope of linear functions. It includes multiple choice questions and their solutions related to linear functions. The concept of direct variation is explained and applied to solve problems.
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TEMPERATURE^ The equation to convert Celsius temperature C to Kelvin temperature K is shown.
a. (^) State the independent and dependent variables.Explain. b. Determine the C- and K- intercepts and describe what the intercepts mean in this situation. 62/87,21 a. (^) The Kelvin temperature is dependent on the Celsius temperature. So, the Celsius temperature is the independent variable and the Kelvin temperature is the dependent variable.
b. The C - intercept is (±273, 0) and it means that a Celsius temperature of ±273 degrees is equal to a Kelvin temperature of 0 degrees. The K - intercept is (0, 273) and it means that a Celsius temperature of 0 degrees is equal to a Kelvin temperature of 273 degrees. Graph each equation. y = x + 2 62/87,21 To graph the equation, find the x - and y - intercepts. Plot these two points. Then draw a line through them. To find the x - intercept, let y = 0.
To find the y - intercept, let x = 0.
So, the x - intercept is ±2 and the y - intercept is 2.
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variable and the Kelvin temperature is the dependent variable.
b. The C - intercept is (±273, 0) and it means that a Celsius temperature of ±273 degrees is equal to a Kelvin temperature of 0 degrees. The K - intercept is (0, 273) and it means that a Celsius temperature of 0 degrees is equal to a Kelvin temperature of 273 degrees. Graph each equation. y = x + 2 62/87,21 To graph the equation, find the x - and y - intercepts. Plot these two points. Then draw a line through them. To find the x - intercept, let y = 0.
To find the y - intercept, let x = 0.
So, the x - intercept is ±2 and the y - intercept is 2.
y = 4 x 62/87,21 The slope of y = 4 x is 4. Graph (0, 0). From there, move up 4 units and right 1 unit to find another point. Then draw a line containing the points.
x + 2 y = ± 1 62/87,21 To graph the equation, find the x - and y - intercepts. Plot these two points. Then draw a line through them. To find the x - intercept, let y = 0.
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± 3 x = 5 ± y 62/87,21 To graph the equation, find the x - and y - intercepts. Plot these two points. Then draw a line through them. To find the x - intercept, let y = 0.
To find the y - intercept, let x = 0.
So, the x - intercept is DQGWKH y - intercept is 5.
Solve each equation by graphing. 4 x + 2 = 0 62/87,21 The related function is y = 4 x + 2. 7RJUDSKWKHIXQFWLRQPDNHDWDEOH
x f ( x ) = 4 x + 2 f ( x ( x, f ( x ) ) ± 4 f (± 4 ) = 4(± 4 ) + 2 ± 14 (±4, ±14) ± 2 f (± 2 ) = 4(± 2 ) + 2 ± 6 (±2, ±6) ±0.5 f (±0.5) = 4(±0.5) + 2 0 (±0.5, 0) 0 f (0) = 4(0) + 2 2 (0, 2) 2 f (2) = 4(2) + 2 10 (2, 10) eSolutions Manual - Powered by Cognero Page 4 Practice Test - Chapter 3
Solve each equation by graphing. 4 x + 2 = 0 62/87,21 The related function is y = 4 x + 2. 7RJUDSKWKHIXQFWLRQPDNHDWDEOH
The graph intersects the x - axis at. So, the solution is. x f ( x ) = 4 x + 2 f ( x ( x, f ( x ) ) ± 4 f (± 4 ) = 4(± 4 ) + 2 ± 14 (±4, ±14) ± 2 f (± 2 ) = 4(± 2 ) + 2 ± 6 (±2, ±6) ±0.5 f (±0.5) = 4(±0.5) + 2 0 (±0.5, 0) 0 f (0) = 4(0) + 2 2 (0, 2) 2 f (2) = 4(2) + 2 10 (2, 10) 4 f ( 4 ) = 4( 4 ) + 2 18 (4, 18) 0 = 6 ± 3 x 62/87,21 The related function is y = í 3 x + 6. 7RJUDSKWKHIXQFWLRQPDNHDWDEOH
The graph intersects the x - axis at 2. So, the solution is 2. x f ( x ) = ± 3 x + 6 f ( x ( x, f ( x ) ) ± 4 f (± 4 ) = ±3(± 4 ) + 6 18 (±4, 18) ± 2 f (± 2 ) = ±3(± 2 ) + 6 12 (±2, 12) 0 f (0) = ±3(0) + 6 6 (0, 6) 2 f (2) = ±3(2) + 6 0 (2, 0) 3 f ( 3 ) = ±3(3) + 6 ± 3 (3, ±3) 4 f ( 4 ) = ±3( 4 ) + 6 ± 6 (4, ±6) 5 x + 2 = ± 3 62/87,21 The related function is y = 5 x + 5. 7RJUDSKWKHIXQFWLRQPDNHDWDEOH eSolutions Manual - Powered by Cognero Page 5 Practice Test - Chapter 3
The graph intersects the x - axis at 2. So, the solution is 2. Find the slope of the line that passes through each pair of points. (5, 8), (±3, 7) 62/87,21 So, the slope is. (5, ±2), (3, ±2) 62/87,21
So, the slope is 0. (±4, 7), (8, ±1) 62/87,21 So, the slope is. (6, ±3), (6, 4) 62/87,21 eSolutions Manual - Powered by Cognero Page 7 Practice Test - Chapter 3
So, the slope is. (6, ±3), (6, 4) 62/87,21
So, the slope is undefined. MULTIPLE CHOICE Which is the slope of the linear function shown in the graph?
The line passes through the points (±2, 3) and (3, 1).
The slope is , so the correct choice is B. Suppose y varies directly as x****. Write a direct variation equation that relates x and y****. Then solve. If y = 6 when x = 9, find x when y = 12. 62/87,21 eSolutions Manual - Powered by Cognero Page 8 Practice Test - Chapter 3
So, x = 6 when y = ±6. If y = ±5 when x = ±2, what is y when x = 14? 62/87,21
So, the direct variation equation is Substitute 14 for x and find y.
So, y = 35 when x = 14. If y = 2 when x = ±12, find y when x = ±4. 62/87,21
So, the direct variation equation is Substitute ±4 for x and find y .´
So, y = ZKHQ x = ±4. BIOLOGY The number of pints of blood in a human body varies directly with the person¶s weight. A person who weighs 120 pounds has about 8.4 pints of blood in his or her body. a. Write and graph an equation relating weight and amount of blood in a person¶s body. b. (^) Predict the weight of a person whose body holds 12 pints of blood. 62/87,21 a. To write a direct variation equation, find the constant of variation k. Let x = 120 and y = 8.4.
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So, y = ZKHQ x = ±4. BIOLOGY^ The number of pints of blood in a human body varies directly with the person¶s weight. A person who weighs 120 pounds has about 8.4 pints of blood in his or her body. a. (^) Write and graph an equation relating weight and amount of blood in a person¶s body. b. (^) Predict the weight of a person whose body holds 12 pints of blood. 62/87,21 a. (^) To write a direct variation equation, find the constant of variation k. Let x = 120 and y = 8.4.
So, the direct variation equation is y = 0.07 x. b. Using the direct variation equation from part a, let y = 12. So, a person who holds 12 pints of blood would weigh about 171 pounds. Find the next three terms of each arithmetic sequence. 0, ±15, ±30, ±45, ±60, « 62/87,21 Find the common difference by subtracting two consecutive terms.
The common difference between terms is ±6RWRILQGWKHQH[WWHUPVXEWUDFWIURPWKHODVWWHUP7RILQGWKH next term, subtract 15 from the resulting number, and so on.
So, the next three terms of this arithmetic sequence are ±75, ±90, ±105. eSolutions Manual - Powered by Cognero Page 11 Practice Test - Chapter 3
The common difference is 4.
An arithmetic sequence is a numerical pattern that increases or decreases at a constant rate called the common difference. To find the common difference, subtract two consecutive numbers in the sequence.
The difference between terms is not constant, so the sequence is not an an arithmetic sequence and does not have a common difference
An arithmetic sequence is a numerical pattern that increases or decreases at a constant rate called the common difference. To find the common difference, subtract two consecutive numbers in the sequence.
The common difference is 4.
MULTIPLE CHOICE^ In each figure, only one side of each regular pentagon is shared with another pentagon. Each side of each pentagon is 1 centimeter. If the pattern continues, what is the perimeter of a figure that has 6 pentagons? F (^) 15 cm H 20 cm G (^) 25 cm J (^) 30 cm 62/87,21 The perimeter increases by 3 as the number of polygons increases by 1. Continue the sequence to find the perimeter of a figure that has 6 pentagons.
Number of Pentagons Perimeter 1 5 2 8 3 11 Number of Pentagons Perimeter 4 14 eSolutions Manual - Powered by Cognero Page 13 Practice Test - Chapter 3
The common difference is 4.
MULTIPLE CHOICE^ In each figure, only one side of each regular pentagon is shared with another pentagon. Each side of each pentagon is 1 centimeter. If the pattern continues, what is the perimeter of a figure that has 6 pentagons? F (^) 15 cm H (^) 20 cm G 25 cm J (^) 30 cm 62/87,21 The perimeter increases by 3 as the number of polygons increases by 1. Continue the sequence to find the perimeter of a figure that has 6 pentagons.
So, a figure that has 6 pentagons has a perimeter of 20 centimeters. The correct choice is H. Number of Pentagons Perimeter 1 5 2 8 3 11 Number of Pentagons Perimeter 4 14 5 17 6 20 eSolutions Manual - Powered by Cognero Page 14 Practice Test - Chapter 3