Math Homework: Fractions, Decimals, and Radicals, Assignments of Algebra

Solutions to exercises 4.1 to 4.10 from a math homework assignment. Topics covered include rational numbers, proper and improper fractions, mixed numbers, decimal numbers, terminating and repeating decimals, reducing fractions, evaluating expressions, and simplifying radicals.

Typology: Assignments

Pre 2010

Uploaded on 08/19/2009

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HOMEWORK 04. Due Thursday, October 02
Exercise 4.1. Answer the following questions.
What is a rational number?
Which fraction is called proper? Which fraction is called improper?
Give two examples of proper fractions and two examples of improper
fractions. Explain.
Which number is called a mixed number? Give two examples of a
mixed number.
What is a decimal number? What is a terminating decimal number?
What is a repeating decimal number?
Exercise 4.2. Reduce the following fraction to its lowest terms. Determine
whether this number is proper fraction or not. If not, present it as a mixed
number.
26 ÷91;
135 ÷120;
148 ÷124;
Solution.26
91 =2·13
7·13 =2
7.
135
120 =5·27
5·24 =27
24 =3·9
3·8=9
8.
148
124 =2·74
2·62 =74
62 =2·37
2·31 =37
31.
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HOMEWORK 04. Due Thursday, October 02

Exercise 4.1. Answer the following questions.

  • What is a rational number?
  • Which fraction is called proper? Which fraction is called improper? Give two examples of proper fractions and two examples of improper fractions. Explain.
  • Which number is called a mixed number? Give two examples of a mixed number.
  • What is a decimal number? What is a terminating decimal number? What is a repeating decimal number?

Exercise 4.2. Reduce the following fraction to its lowest terms. Determine

whether this number is proper fraction or not. If not, present it as a mixed

number.

• 26 ÷ 91;

• 135 ÷ 120;

• 148 ÷ 124;

Solution.

Exercise 4.3. Present each decimal number as a ratio of two integers. DO

NOT reduce the fraction into lowest terms.

  • 0 .2345, 0.452 (terminating)
  • 0 .51, 5. 2 39 (repeating)

Solution. 0.2345 = 2345 10000

Let a = 0. 51515151 · · · = 0.51. We multiply this number by 10, 100,

1000, etc. until we see how to get rid of the repeating part.

We get 10a = 5. 1515151 · · · = 5.15.

100 a = 51. 51515151 · · · = 51.51. We see that 100a and a have the same

digits after the decimal point. Then, 100a − a = 51. 51 − 0 .51, or 99a = 51.

Therefore, a =

Let a = 5. 239393939 · · · = 5. 2 39. Then, 10a = 52. 39393939 · · · = 52.39,

100 a = 523. 93939393 · · · = 523.93, 1000a = 5239. 39393939 · · · = 5239.39.

We can see that the numbers 10a and 1000a have the same digits after the

decimal point. Therefore, 1000a − 10 a = 5239. 39 − 52 .39, or 990a = 5178.

Thus, a =

Exercise 4.4. Evaluate the expression. Explain each step.

÷

Exercise 4.9. Perform the indicated operation. Simplify the answer when

possible.

√^125

Solution. First, we simplify all square roots:

Second, we gather all terms:

4 × 2 ×

3 + 7 × 5 ×

3 − 10 × 4 ×

Exercise 4.10. Rationalize the denominator.

√^20

√^4 ·^5

√^5

√^5

√^19

√^10

√^10

√^6

√^50

√^25

= √^5

= √^5

√^7

=^5