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ECE 3336 – INTRODUCTION TO CIRCUITS AND ELECTRONICS
HOMEWORK
- The current i C (t) through the capacitor in Figure 1 is given by the plot shown in Figure 2. It is
given that v C
(2[ms]) = 6[V]. Find v C
(8[ms]).
v
C
(t)
150 [pF]
i
C
(t)
Figure 1
i
C
(t) , [A]
t,[ms]
3
3
6 9 12
Figure 2
- In the circuit shown below, the switched closed at t = 0. No energy was stored in the
capacitor, and no energy was stored in the inductor, at t = 0. The expression for v S (t) is given
below.
Find the power delivered by the voltage source at t = 5[s].
2
2
V ( ) 6 ; for 0.
s
S
v t t t
600[H]
v
S
(t)
4.7[k]
t = 0
1[mF]
2.2[k]
- In the circuit shown below, the two switches were open for a long time before t = 0, until all
voltages and currents stopped changing. Then, both switches closed at t = 0. Then, switch SWA
opened again 2[s] later.
a) Find i Q
b) Find i X
).
c) Find i Q
).
d) Find i X
i X
- 3 [k]
4 i X
[V]
- 7 [k]
L
1
3 [mH]
t = 0
Switch SWA
t = 0
- 2 [k]
Switch SWB
t = 2 [s]
i Q
- In the circuit shown below, switches SW1 and SW2 have been closed for a long time before
t = 0, allowing all voltages and currents to stop changing.
At t = 0, switch SW1 opens and remains open.
At t = 0.5[s], switch SW2 opens and remains open.
a) Find i L
b) Find i X
).
c) Find i L
).
d) Find i X
e) Find the energy stored in the inductor just before t = 0, w STO.BY.L
f) Find the energy stored in the inductor just after t = 0, w STO.BY.L
v S 1
=
300 [V]
SW 1
i S
= - 2 i X
t = 0
i L
R 1
= 300 []
L =
- 2 [H]
R 2
= 10 []
R 4
=
30 []
R 3
= 20 []
v S 2
=
100 [V]
SW 2
t = 0. 5 [s]
i X
Next slide
- In the circuit below, find the nonzero frequency at which the voltage v S (t) is in phase with the
current i S (t). Problem adapted from (PEQWS8, No. 9).
L =
50 [mH]
a
b
C =
1 [F]
R =
180 []
i
S
(t)
v
S
(t)
- A device was connected to a resistor and capacitor, as shown in Figure 1, and the steady-
state voltage that resulted was
rad ( ) 65.7 cos 500 172 [V]
s
X
v t t
The same device was then removed from that circuit, and was connected to a resistor and
inductor, as shown in Figure 2. The steady-state current that resulted was
rad ( ) 35.67 sin 500 99.8 [mA].
s
X
i t t
Next, the same device was removed from that circuit, and was connected to a resistor, as shown
in Figure 3. Find the steady-state value of v W (t).
R 1
= 1[k]
Figure 1
C 1
=
3.3[F]
Device
a
b
v X
(t)
+
-
Figure 2
Device
a
b
L 2 =
- 2 [H]
i X
(t)
R 2
=
- 3 [k]
Figure 3
Device
a
b
R 3
=
1[k]
v
W
(t)
+
-
- The circuit drawn below is in the steady state. Find i X (t). It is given that
v S (t) = 100 sin(25[rad/s] t + 20º)[V].
v S
(t)
R X
=
1[k]
i X
(t)
v Y +
v S
=
5 v
Y
L X
=
30[H]
C
X
=
100[F]
- Find the steady-state value of v X (t).
v
X
(t)
L
1
=
6[H]
C
1
=
1000[F]
i
1
(t) R
1
=
500[]
L
2
=
325[mH]
C 2
=
60[F]
i
2
(t)
i 1
(t) = 15 cos (200[rad/s] t + 56°) [mA]
i
2
(t) = 20 sin (200[rad/s] t - 32°) [mA]
Next slide
