Physics Quiz: Conservation of Energy in Projectile Motion, Quizzes of Physical Education and Motor Learning

A physics quiz question about the conservation of energy in projectile motion. The question asks to find the kinetic energy of a projectile when its potential energy is given, and vice versa. The problem involves calculating the energy changes using the principle of conservation of energy. The document also includes an explanation of how the net force acts on the projectile at its highest point.

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Pre 2010

Uploaded on 07/28/2009

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Quiz 8
March 29, 2001
3. A projectile starting with a potential energy, PEG = 10 Joules , is fired
straight upward with a kinetic energy, KE = 50 Joules. When the
projectile has potential energy, PEG = 30 Joules, what is the kinetic
energy of the projectile?
The only force acting is gravity and therefore, energy is conserved.
a) 20 Joules
*b) 30 Joules
c) 40 Joules
d) 60 Joules
e) 80 Joules
4. A spring fires a projectile, with mass m , straight up into the air. What is
the magnitude of the net force acting on the mass at its highest point.
Throughout the flight of the projectile, the only force acting is gravity,
F
G=mg
. At the highest point, v is zero, but the net force is still
F
G
. At
that point, gravity changes the object's direction from up to down.
*a) mg
b) 2 mg
c) zero
d) 1/2mg2
e) kx
KE0+PE0=KE +PE
50 J
( )
+10 J
( )
=KE +30 J
( )
KE =30 J

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Quiz 8 March 29, 2001

  1. A projectile starting with a potential energy, PE G = 10 Joules , is fired straight upward with a kinetic energy, KE = 50 Joules. When the projectile has potential energy, PE G = 30 Joules , what is the kinetic energy of the projectile?

The only force acting is gravity and therefore, energy is conserved.

a) 20 Joules *b) 30 Joules c) 40 Joules d) 60 Joules e) 80 Joules

  1. A spring fires a projectile, with mass m , straight up into the air. What is the magnitude of the net force acting on the mass at its highest point.

Throughout the flight of the projectile, the only force acting is gravity, FG = mg. At the highest point, v is zero, but the net force is still FG. At

that point, gravity changes the object's direction from up to down.

*a) mg b) 2 mg c) zero d) 1/2 mg^2 e) kx

KE 0 + PE 0 = KE + PE

(^ 50 J ) +^ (10 J ) =^ KE^ +^ (30 J )

KE = 30 J