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A series of chemical equations and corresponding stoichiometry problems. Students are asked to determine mole ratios, moles of reactants and products, and grams of reactants and products. The problems involve both one-step and three-step reactions.
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Part A Review: For the following chemical equations, write the possible mole ratios.
2 CO 2 CO 1 O 2 1 O 2 2 CO 2 2 CO 2
1Al 2 (CO 3 ) 3 1 Al 2 (CO 3 ) 3 1 Al 2 O 3 1 Al 2 O 3 3 CO 2 3 CO 2
2 CO 2 CO 1 O 2 1 O 2 2 CO 2 2 CO 2
Part B Review: Using arrows to map your work solve the following 1-step and 2-step stoichiometry problems.
7 moles CO x 2 moles O 2 = 3.5 moles O 2
2 moles CO
b. How many moles of carbon dioxide, CO 2 , can be formed by the decomposition of 5 moles of aluminum carbonate, Al 2 (CO 3 ) 3?
Al 2 (CO 3 ) 3 โ Al 2 O 3 + 3 CO 2
5 moles Al 2 (CO 3 ) 3 x 3 moles CO 2 = 15 moles CO 2
1 moles Al 2 (CO 3 ) (^3)
oxygen gas, O 2?
3 moles O 2 x 2 moles CO = 6 moles CO
1 moles O 2
6 moles CO x 28.01 g = 168.06 g 1 mole CO
Part C: Using arrows to map your work solve the following 3-step stoichiometry problems.
10 g x 1 moles C 2 H 6 = 0.3324 moles C 2 H 6 30.08 g
0.3324 moles C 2 H 6 x 7 moles O 2 = 1.1636 moles O (^2) 2 moles C 2 H 6
1.1636 moles O 2 x 32 g = 37.23 g 1 moles O 2
KClO 3?
2 KClO 3 โ 2 KCl + 3 O 2
10 g x 1 moles KClO 3 = 0.081599 moles KClO (^3) 122.55 g
0.081599 moles KClO 3 x 3 moles O 2 = 0.122399 moles O (^2) 2 moles KClO 3
0.122399 moles O 2 x 32 g = 3.9167 g 1 moles O 2