Refresher Course Math 1050 and 1060 Practice Problems Set 4 - Spring 2008, Assignments of Algebra

Math problems and solutions for refresher course math 1050 and 1060 from spring 2008. It includes finding the graphs of various functions, calculating the difference between two functions, determining the domain of a sum of functions, finding logarithmic functions and their domains, and finding the inverse of a function.

Typology: Assignments

Pre 2010

Uploaded on 07/30/2009

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Refresher
Course
Math
1050
and
1060 Practice Problems Set 4
Spring
2008
1.) Sketch the graph
of
each
of
the following:
a.) y=_(X+3)2 b.)
g(x)=.Jx-2-1
c.) y=lx+31+5
d.)
f(x)
=
_x
3
+2
e.)
p(x)
=
-3x
2
L
(.\1
\
irY:;Jl
\'-3
Jt77
'f
'f-=-=l~,,{j)1.
...,
><
1..
~
lL
~
y::_(~./3)
~.
d)
__
~1o::---7
>(
't
j
'1. 'f-:;
-~
-t 1
_--t---"t'""---:J1
X
Page 1
of2
pf2

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Refresher Course Math 1050 and 1060 Practice Problems Set 4 Spring 2008

1.) Sketch the graph of each of the following: a.) y=(X+3)2_ b.) g(x)=.Jx-2-1 (^) c.) y=lx+31+

d.) f(x) = _x^3 +2 e.) p(x) = -3x^2

L (.\1 \ irY:;Jl '-3 J t

'f 'f-=-=l~,,{j)1. ..., >< 1.. ~

lL ~ y::_(~./3)

~.

d)

__~1o::---7>(

't j '1. 'f-:; -~ -t _1 --t---"t'""---:J1 X

Page 1 of

Refresher Course Math 1050 and 1060 Practice Problems Set 4 Spring 2008

2.) Let I(x) = 2x +1 and g(x) = x 2 + 2x -1. Find (I - g)(x). Then evaluate the

difference when x=2.

~ -} )~) -:. F (;z) - ,. (xJ -=- G-:t-f()- LX. 2.- f 1.>(_I)

":. z)( of ( -)( 2.-_ 2..)( f f

-::. -x2.~ l.

~- r) ( 1.) -; - (1.)7- t 1. -:: - I:.( -I 2. =--;;1.

3.) Let I(x) = x and g(x) = .JX. Find the domain of I + g. I'

t-)Do .....~ of f: AU Yl./ h ll^ n.-!,-t".1 c)Do-.,"" of .tfl

(- -) -) ~ .... +-CYs~"h~ ....

4( '>l£ L ,~

E >

I ::::>x

~ O~ ....... ""- 0 I ,; X '> 0 [D..! 00) o

L ot:. >x

4.) Let I(x) = 2 and g(x) = x - 5. Find log and its domain.

x-

2.. 2.. L

~ D 1-~J -: .f:- ()-<fJ) -;.. &-s-) _ t -:... x. _ I L -s> r d...-y; c..f,- ~"

6-11 vl"l n~h-b<ys T!'~((ri x= I,

D" '"'" ,.1-.. ' 0 ~

C-~) I'Z..) V (,1./ O())

5.) Find the inverse of I(x) =2. - 3x.

... 2

c0 y::: s- ~.: ~ f -I (x) ~ - ~ X +f

c) :Lx -:: )--J 7

2.-)(-)" -;: - 3)

1:...-] X - 5:.--J =- Y

-3::-v +- ~ -= 'r. Page 2 of

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