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Three sample problems and solutions related to the division of algebraic expressions. The problems involve simplifying and finding the quotient of expressions with variables. The solutions provide step-by-step explanations of the process of simplification and division. useful for students studying algebraic expressions and division in mathematics.
Typology: Exercises
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04 - 22- 23
Solution: ๐ ๐ โ 1 ๐^2 + 1 ๐ 4 ๐ โ 1 2 Rewrite the expressions as follows, ๐ ๐ โ 1 ๐^2 + 1 ๐ 4 ๐ โ 1 2
Cancel out the expressions that has common on both numerator and denominator, as follows, ๐ โ ๐ โ ๐ (^) โ ๐^2 + 1 ๐ โ ๐^3 โ ๐ โ ๐ โ ๐ โ 1 ๐ 2
๐ ๐^2 โ 1 ๐+
Solution: ๐ 2 โ 1 2 ๐ ๐ + 1
2 โ 1 ๐ + 1 2 Take the reciprocal of the second term, then proceed to multiplication, so we have, ๐ 2 โ 1 2 ๐ ๐ + 1
2 โ 1 ๐ + 1 2
4 ๐ + 1
๐ ๐ + ๐ ๐ ๐ 4 ๐ + 1
๐ ๐ ๐ Rewrite the expressions for further simplification as follows, ๐^4 ๐ + 1
3 ๐ 3 โ ๐ ๐ + 1
3 Then cancel out some expressions, such as, ๐๐^ โ ๐ ๐ + ๐
๐ ๐ ๐ + ๐ Therefore, the quotient of the given problem is ๐ ๐ + ๐.
๐+ 4 ๐ 4 ๐^2 โ 1
Solution: ๐^3 ๐^2 โ 1 2 ๐ + 1
2 โ 1 Take the reciprocal of the second term, then proceed to multiplication, so we have,
3 ๐ 2 โ 1 2 ๐ + 1
๐ ๐ ๐ ๐ ๐ โ ๐ ๐ 3 ๐ 2 โ 1 2 ๐ + 1
๐ โ ๐ ๐ + ๐ ๐ ๐ ๐ Rewrite the expressions for further simplification as follows, ๐ 3 ๐ 2 โ 1 2 ๐ + 1
2 โ 1 ๐ + 1 4 ๐ 4 ๐๐^ ๐^2 โ 1 2 ๐ + 1
Then cancel out some expressions, such as, ๐๐^ ๐^2 โ 1 2 ๐ + 1
4 ๐ ๐ โ ๐ ๐ 2 โ 1 2 ๐ + 1
2 โ 1 ๐ + 1 4 ๐ ๐ ๐ โ ๐ ๐ ๐ ๐ + ๐ ๐ Therefore, the quotient of the given problem is ๐ ๐ โ๐ ๐ ๐ ๐+๐ ๐ . RSM