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A collection of problems from a university-level mathematics course focused on elementary number theory. The problems cover topics such as the chinese remainder theorem, solving polynomial congruences, and properties of integers. Students are asked to find solutions to systems of linear congruences, determine the least number of eggs in a basket based on an ancient indian problem, and prove various number theoretic results.
Typology: Assignments
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JOHN VOIGHT
4.3: The Chinese Remainder Theorem
Problem 4.3.4(c). Find all the solutions to the following system of linear congruences:
x ≡ 0 (mod 2) x ≡ 0 (mod 3) x ≡ 1 (mod 5) x ≡ 6 (mod 7).
Problem 4.3.12. Solve the following ancient Indian problem: If eggs are removed from a basket 2, 3 , 4 , 5 , 6 at a time, there remain, respectively, 1, 2 , 3 , 4 , 5 eggs. But if the eggs are removed 7 at a time, no eggs remain. What is the least number of eggs that could have been in the basket?
Problem 4.3.14∗. Show that if a, b, c ∈ Z have gcd(a, b) = 1, then there is an integer n such that gcd(an + b, c) = 1.
Problem 4.3.A. Let f (x) ∈ Z[x] be a polynomial with integral coefficients. For m ∈ Z> 1 , let #X(Z/mZ) denote the number of solutions in Z/mZ of the congruence
f (x) ≡ 0 (mod m). (a) Prove that if m = m 1 m 2 , where gcd(m 1 , m 2 ) = 1, then #X(Z/mZ) = #X(Z/m 1 Z) · #X(Z/m 2 Z). (b) What can you conclude if gcd(m 1 , m 2 ) > 1?
4.4: Solving Polynomial Congruences
Problem 4.4.1. Find all the solutions of each of the following congruences:
(a) x^2 + 4x + 2 ≡ 0 (mod 7) (b) x^2 + 4x + 2 ≡ 0 (mod 49) (c) x^2 + 4x + 2 ≡ 0 (mod 343)
Problem 4.4.10. How many incongruent solutions are there to the congruence x^5 +x− 6 ≡ 0 (mod 144)?
Problem 4.4.A. Let k ∈ Z> 0.
(a) Show that the product of any k consecutive integers is divisible by k!. [Hint: Use a binomial coefficient.] Date: Due Wednesday, 25 February 2009. 1
(b) Let f (x) ∈ Z[x] be a polynomial with integer coefficients, let r ∈ Z. Let f (k)(x) denote the kth derivative of f (x). Show that each coefficient of f (k)(x) is divisible by k!. Conclude that for any r ∈ Z, f (k)(r)/k! is an integer.
Computation 4.4.2∗. Find all solutions of x^9 + 13x^3 − x + 100336 ≡ 0 (mod 17^9 ).
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