Estimating Gravity's Acceleration with Newton's Second Law and Lab Data, Assignments of Linear Algebra

A problem that involves using newton's second law of motion to find the approximate value of the acceleration of gravity (g) based on the data collected from a lab experiment where a weight's vertical displacement from a reference point at different time intervals is measured.

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Pre 2010

Uploaded on 08/16/2009

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Math 304
A supplementary problem for Section 6.6
According to Newton’s second law of motion, a body near the earth’s surface falls vertically
downward according to
s=s0+v0t+.5gt2
where sis vertical displacement downward relative to some fixed point, s0is initial displacement
at time t= 0,v0is initial velocity at time t= 0,gis acceleration of gravity at earth’s surface.
Suppose a lab experiment is performed to evaluate gusing this equation. A weight is released
with unknown initial displacement and velocity and at certain times the distances fallen from
some fixed reference point are measured. In particular, suppose that at times t=.1, .2, .3, .4, .5
seconds it is found that the weight has fallen s=.18, .31,1.03,2.48,3.73 feet, respectively,
from the reference point. Find an approximate value of gusing these data.
Answer: gis approx. 32.2ft/s2.
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Math 304

A supplementary problem for Section 6.

According to Newton’s second law of motion, a body near the earth’s surface falls vertically downward according to s = s 0 + v 0 t +. 5 gt^2

where s is vertical displacement downward relative to some fixed point, s 0 is initial displacement at time t = 0, v 0 is initial velocity at time t = 0, g is acceleration of gravity at earth’s surface. Suppose a lab experiment is performed to evaluate g using this equation. A weight is released with unknown initial displacement and velocity and at certain times the distances fallen from some fixed reference point are measured. In particular, suppose that at times t =. 1 ,. 2 ,. 3 ,. 4 ,. 5 seconds it is found that the weight has fallen s = −. 18 ,. 31 , 1. 03 , 2. 48 , 3. 73 feet, respectively, from the reference point. Find an approximate value of g using these data.

Answer: g is approx. 32. 2 f t/s^2.