MATH 121: Absolute Value Problems and Inequalities, Study notes of Pre-Calculus

Solutions to various absolute value problems and inequalities from math 121, including writing inequalities, solving algebraic equations, and finding solution sets using interval notation. Topics covered include section 3.5 and section 4.6.

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MATH 121
Absolute Value Problems
1. (Section 3.5) Write an inequality of the form
x a C
or of the form
x a C
so that the inequality has the given solution set.
a)
3,3
b)
2,8
c)
3,17
d)
,9 13,
2. (Section 4.6) Solve each of the following algebraically and use your calculator to
check your solution.
a)
65
2 xx
b)
xx 1881
2
(Be careful here...)
c)
44 xx
(Be extra careful here...)
3. (Section 3.5) Solve for
in each of the following equations.
(a)
12
4
3
8
3 x
(b)
12
4
3
8
3 x
(c)
8
13
4
3
8
32 x
(d)
22 4
3
4
3 xx
4. (Section 3.5) Let
5
1
21
x
xf
. Find all numbers, x, such that
1xf
.
5. (Section 3.5) Solve for x in each of the following.
(a)
377
2
8
x
(b)
21
3
1
59
x
(c)
2
1
5
211
x
(d)
2
1
5
121
x
6. (Section 3.5) Solve each of the following, using interval notation for your solution:
a)
24
3
1
x
b)
61325 x
pf2

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MATH 121

Absolute Value Problems

  1. (Section 3.5) Write an inequality of the form xaC or of the form xaC

so that the inequality has the given solution set.

a)  3,3

b)  2,8

c)  3,17

d)  ,9  13, 

  1. (Section 4.6) Solve each of the following algebraically and use your calculator to

check your solution.

a) 5 6

2 xx

b) x 81 18 x

2   (Be careful here...)

c) x  4  x  4 (Be extra careful here...)

  1. (Section 3.5) Solve for x in each of the following equations.

(a) 83  43 x  2  1 (b) 83  43 x  2  1

(c) 83  43 x  2 ^138 (d) 43 x  2  43 x  2

  1. (Section 3.5) Let  ^ 5

x f x. Find all numbers, x , such that f   x  1.

  1. (Section 3.5) Solve for x in each of the following.

(a) 7 7 3 2

x (b) 21 3

x

(c) 2

  x (d) 2

x

  1. (Section 3.5) Solve each of the following, using interval notation for your solution:

a)^42 3

x  b) 5  23 x  1  6

Answer Keys:

  1. Note that xaC means that x is less than C units from a and xaC means

that x is more than C units from a on the real line. So if the interval is (4, 8) then

since 6 is the midpoint of 4 and 8, the inequality is (^) x  6  2.

a) x  3

b) x  3  5

c) x  10  7

d) x  11  2

  1. a) 6, -1, 3, 2

b) 9

c) x  4

  1. a) no solution

b)

c) x  0

d) x  0

  1. (a) 15 > x > 13

(b)  , 17  19, 

(c) no solution

(d)

  ^ 

  1. (a) 7  x  5

(b) no solution