AC Circuit Phasors - Lecture Slides | PHYS 102, Study notes of Physics

Material Type: Notes; Class: College Physics: E&M & Modern; Subject: Physics; University: University of Illinois - Urbana-Champaign; Term: Unknown 1989;

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Physics 102: Lecture 13, Slide 1
AC Circuit Phasors
Today’s lecture will cover Textbook
Section 21.5
Physics 102: Lecture 13
L
R
C
•I = I
maxsin(2πft)
•V
R= ImaxRsin(2πft)
•V
C= ImaxXCsin(2πft-π/2)
•V
L= ImaxXLsin(2πft+ π/2)
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Physics 102: Lecture 13^ AC Circuit Phasors• Today’s lecture will cover TextbookSection 21.

L R C

  • I = Imax

sin(2πft)

  • V^ = IR^

R sin(2max πft)

  • V^ = IC^

X^ sin(2max C^

πft-π/2)

  • V^ = IL^

X^ sin(2max L^

πft+^ π/

A reminder about sines andcosines Recall: Physics 102: Lecture 13, Slide 2

y^ coordinatesof endpoints are• a sin(θ^ +^ π/2) • a sin(θ) • a sin(θ^ -^ π/2)

a^

a a

Peak valuesin AC Circuits

,max^ max C

C V^ I ,max^ max R^ X = V^ I

R = ,max max L L V^ I

X = ,max max gen V^

I^ Z =

(^1) X = CC ω X L ω= L^2

2 (^

) L C Z^ R^

X^ X =^ +^

voltage^

reactance orimpedance

(capacitive reactance)(inductive reactance)

L R C (impedance)

Peak + RMS valuesin AC Circuits (REVIEW)

L R C

,max^ max C

C V^ I ,max^ max R^ X = V^ I

R = ,max max L L V^ I

X = ,max max gen V^

I^ Z = When asking about RMS or Maximum valuesrelatively simple expresions

(^1) X = CC ω X L ω= L^2

2 (^

) L C Z^ R^

X^ X =^ +^

π/

Phasor Diagrams

V^ sin( π/3 R,max^ f =1/12t = 2 2 π ft =^ π /3 ) max V

  • I = Imax

sin(π/3)

  • V^ = VR^

sin(R,max^

π/3) Length of vector = V

across that componentmax^ Vertical component = instantaneous value of V

Phasor Diagrams

V^ sin( π/2 )=VR,max^^ π/ t = 3 2 π ft =^ π /2^0 max V

  • I = Imax

sin(π/2)

  • V^ = VR^

sin(R,max^

π/2) Length of vector = V

across that componentmax^ Vertical component = instantaneous value of V

Phasor Diagrams

  • I = Imax

sin(2πft)

  • V^ = IR^

R sin(2max πft)

R^ ImaxI^ R sin(2max^

π ft)

• V^ = IC^

X^ sin(2max C^

πft-π/2)

  • V^ = IL^

X^ sin(2max L^

πft+π/ I^ X^ maxL sin(2 π ft+ π/2 ) )

I^ X^ maxC sin(2 π ft- π /2) ImaxX^ L^ I^ maxX^ C

Instantaneous Values: Voltage across resistor is always _______ with current!Voltage across capacitor always _______ current!Voltage across inductor always ________ current!

Phasor Diagram PracticeLabel the vectors that corresponds tothe resistor, inductor and capacitor.Which element has the largest voltageacross it at the instant shown?1) R^ 2) C^

  1. L Is the voltage across the inductorincreasing or decreasing?Which element has the largestmaximum voltage across it?

Drawing Phasor Diagrams

VL

(2) Capacitor vector: downwards•^ Length given by V

C

VC

(3) Inductor vector: upwards•^ Length given by V

L

VR

(1)^ Resistor vector: to the right•^ Length given by V

R (4) Generator vector: add first 3 vectors•^ Length given by V

gen

Vgen VR VC VL

(5) Rotate entire thing counter-clockwise•^ Vertical components give instantaneousvoltage across R, C, L, gen

Vgen

time 1^ Physics 102: Lecture 13, Slide 14

time 2

time 3^

time 4

ACTS 13.1, 13.2, 13.

When does VIs the phase angle positive or negative?

= Vgen R^ ? When does V

= 0 ?gen φ

AC Summary

Resistors:

V=I RR In phase with ICapacitors:^

V=ICmax^

Xmax C^ X= 1/(2c^

π f^ C)

Lags IInductors:^

V=ILmax^ max

XX L^

= 2π f^ LL

Leads IGenerator:^

V=Igenmax

Z^ max^

Z =^ √R

2 +(X-XL^

(^2) ) (^) C

Can lead or lag I

tan(φ) = (X

-X)/RL C

Power is only dissipated in resistor:

P = I^ Vrms

cos(φrms )

Problem Time!

An AC circuit with R= 2

Ω, C = 15 mF, and L = 30 mH is driven by a generator with voltage V(t)=2.5 sin(

πt)

Volts. Calculate the maximum current in the circuit, andthe phase angle.I= V^ max^ gen,max

/Z^

L R C

Z =

ACT: Voltage Phasor Diagram LX^ max^ I

R^ maxICX^ maxI φ gen,maxV

Rotates Counter ClockwiseAt this instant, the voltageacross the generator ismaximum.

What is the voltage across the resistor at this instant?1) V^ = IR^ max

R^ 2) V

= IR sin(R max

φ )^ 3) V

= IR cos(R max

φ )

See you next time!

  • Read Sections 21.6, 22.1, 4-5, 9