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Plot a titration curve of pH vs. mL NaOH added using Excel and attach it to your lab report. Be sure to label graph and both of the axes. pH at ...
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Name: _______________________________________ Date:_______________________________ Lab Partners: ____________________________________________________________
By Thomas Cahill, Arizona State University, New College of Interdisciplinary Arts and Sciences. Background: One of the most common reactions in chemistry is the reaction of an acid with a base. This type of reaction is also called neutralization. The mechanism of this process is the combination of hydroxide ions and hydronium to create water: H 3 O+(aq) + OH−(aq) → 2H 2 O(l) (1) It is important to note that the hydronium ion (H 3 O+) is often simply represented as H+. The hydronium ion representation is technically a more accurate representation of association between a hydrogen ion and a water molecule, but either representation is acceptable and interchangeable in this class. The acid-base reaction is a second order reaction, thus the rate of the reaction is dependent on the concentrations of both of the reactants. The concentration of hydronium ion is most commonly expressed as the pH of the solution. The equation to calculate pH is: pH= −Log[H+] (2) where [H+] is the concentration of the hydronium ion. The pH of a solution is a measure of the hydronium ion concentration in a solution. The pH scale ranges from 0 to 14. Any pH value lower then 7 indicates an acidic solution, a pH value above 7 denotes a basic solution, and a pH value of 7 indicates a neutral solution. The pH for several familiar substances can help give an idea of what the capricious pH values represent. Gastric juice has a pH of 1 while wine has a pH of around three. Conversely, household bleach has a pH of 12 and baking soda has a pH of eight. Human blood and tears are very close to the neutral pH of seven. One important thing to note about the pH scale is that it is based on the logarithmic scale. This means that for every single unit of change in pH there is actually a tenfold difference in the hydronium ion concentration. For example, if the pH of a solution drops from 6 to 5, the hydronium ion concentration has increased by a factor of 10, from 10−^6 M to 10−^5 M. The most accurate method of measuring the pH of a solution is utilizing a device called a pH meter. A specialized electrode, which measures the concentration of hydronium ions, is simply placed into the solution. A few seconds after the probe is submerged, the pH of the solution will be displayed on the pH meter’s screen. Colored pH paper and indicator dyes can also be used to roughly estimate the pH of the solution. Another important concept in acid-base chemistry is that of acid-dissociation constants. An acid dissociation constant, denoted by Ka , is an equilibrium constant for the dissociation of a weak acid.
HA representing an acid and A−^ representing the conjugate base of the acid. The acid dissociation constant is log-transformed to get it on the same scale as pH. This is defined as p Ka , which is calculated as:
The magnitude of Ka indicates the tendency of an acid to ionize in water. The larger the Ka value of an acid the stronger the acid. Conversely, the smaller the p Ka value the stronger the acid. Equations #5 and #2 are combined and manipulated to the Henderson-Hasselbalch equation:
This is a very useful equation since it relates pH to p Ka and the fraction of the acid that is ionized. People who often work with buffers use this equation to calculate the pH of buffers. Example: What is the pH of a buffer that is 0 .20 M in lactic acid (HC 3 H 5 O 3 ) and 0 .05 M in sodium lactate? Lactic acid has a Ka of 1.4×10−^4. pH = p Ka + Log ([base]/[acid]) = 3.85 + Log(.05/.20) = 3.85 + (−0.602) = 3. Titration Curves Titration is the technique used to accurately measure the characteristics of an acid. Typically, the acid is dissolved in a solution and then a burret with a strong based is placed over the beaker containing the acidic solution. The pH of the solution is monitored as the strong base is added to the solution. The plot of solution pH (y-axis) as a function of the volume of base added (x-axis) as shown in Figure 1 below. From this curve, the equivalence point can be determined and the stoichiometry of the reaction calculated. The equivalence point is the point at which equimolar amounts of acid and base have reacted, and is indicated by a sharp change in pH and an almost vertical rise in the titration curve. Figure 1 shows a graphical method for locating the equivalence point on a titration curve. This figure indicates that the equivalence point for the titration of a strong base with a weak acid occurs at pH 8.3.
Figure 2. Graphical method to determine the p Ka of a weak acid Weak acid - Strong base titration 0 2 4 6 8 10 12 14 0 5 10 15 20 25 mL of NaOH added pH Equivalence point (midpoint of steep section of titration plot) Volume of base needed to reach equivalence point = 15 mL Half equivalence point volume = 7.5 mL p K (^) a = 5. From the titration curve, the point denoted as half the equivalence point, where [HA] = [A − ], has a pH = 5.7, and the ionization constant is calculated as: pH = p Ka = 5. p Ka = −log Ka = 5. Ka = 2.0× 10 −^6 Determining the Molar Mass of an Unknown Salt The titration method can also be used in order to determine the molar mass of an unknown salt. A salt is composed of a positively charged cation and a negatively charged anion. For example, NaF is composed of Na+^ and F −. Anions are simply deprotonated acids and they can accept H+^ to again become acids. F −^ + H+^ → HF With the exception of the conjugate anions of strong acids (NO 3 − , Cl − , Br − , I − , ClO 3 − , ClO 4 −^ and HSO 4 − ), the anions of acids are weak bases. Therefore, you can titrate the weak anionic base with a strong acid and plot a titration curve of pH versus volume of acid added. The resulting equivalence point is the point at which equal moles of acid and base have been added together, thus the moles of acid will equal the moles of the anion. With the moles of anion calculated, you then divide the mass of the unknown sample by the moles of unknown that have been titrated and it will give you an estimate of the molar mass of the unknown substance. NOTE: this is the complete molar mass of unknown substance including the cation and any hydration complexes.
For example: An aqueous solution of an unknown salt that was prepared by adding 1.02 g of unknown to 100 mL DI water. The unknown salt solution is then titrated with 1.0M HCl. The volume of HCl added at the titration equivalence point was determined to be 5.75 mL. Calculate the molar mass of the unknown salt. Assume the salt cation:anion ratio is 1:1.
1. Use the provided excel file – “Calculate pH for Titration of Acetic acid vs. NaOH” to find the pH and fill in the data Table below. The “volume of NaOH added” is also shown in the excel file column C.
mL NaOH added (continued from prior columns)
**(continued from prior columns)
8.**
2. For the titration of H 3 PO 4 acid with NaOH, answer the following question: Plot a titration curve of pH vs. mL NaOH added using Excel and attach it to your lab report. Be sure to label graph and both of the axes. pH at 1st^ equivalence point: ________________________________________ pH at 2nd^ equivalence point: ________________________________________ Write the three acid dissociation reactions for this polyprotic acid in H 2 O :
______ of 4.5 pts
If you chose unkwown salt # 2, then use the provided excel file – “Calculate pH of Unknown Salt # from mL of HCl added” to find the pH and fill in the data Table below. If you chose unkwown salt # 3, then use the provided excel file – “Calculate pH of Unknown Salt # from mL of HCl added” to find the pH and fill in the data Table below. One student do only one unknown salt. Once you open the excel file, enter mass of the unknown salt in the appropriate cell in the excel file.
Volume 1M HCl (mL)
(mL)