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Download ACTUAL AQA 2025 AQA A LEVEL PHYSICS PAPER 2 JUNE 2025 WORKED EXAM SOLUTIONS and more Exams Physics in PDF only on Docsity!
Please write clearly in block capitals. Centre number Candidate number Surname Forename(s) Candidate signature | declare this is my own work. A-level PHYSICS Paper 2 Monday 9 June 2025 Morning Time allowed: 2 hours Materials For this paper you must have: * a pencil and a ruler * ascientific calculator « a Data and Formulae Booklet * a protractor. Instructions ¢ Use black ink or black ball-point pen, « Fill in the boxes at the top of this page. * Answer all questions. « You must answer the questions in the spaces provided, Do not write outside the box around each page or on blank pages. « If you need extra space for your answer(s), use the lined pages at the end of this book. Write the question number against your answer(s). © Do all rough work in this book, Cross through any work you do not want to be marked. © Show all your working. Information e The marks for questions are shown in brackets. «¢ The maximum mark for this paper is 85. * You are expected to use a scientific calculator where appropriate. e A Data and Formulae Booklet is provided as a loose insert. INU NALA vu 40 IB/M/Jun25/G4006/E 12 For Examiner's Use Question Mark alalalolrse|— 7-31 TOTAL 7408/2 Section A Answer all questions in this section. Information about the radius of a nucleus can be deduced from the closest approach of alpha particles and from electron diffraction. (o[4).4) Alpha particles, each with a kinetic energy of 5.59 MeV, are fired at a thin foil made of gold ('35.au) atoms. Some of the alpha particles are scattered through an angle of 180°. Estimate the radius of a 133, Au nucleus from this information. [3 marks] 14 Atb6kIO 6 74+ Le aDO™ = = |y.066 A197 -14 SS4A Cate x UNCh eraco"?) amy radius of nucleus = U-o7x'0 m {o[4].[2] Explain why your answer to Question 01.1 is an estimate. [2 marks] Tre Aypha Pe dew pt cons fo pep ahs Ja fau 7 We neler, mee fre differ meqrrel he ety hee wy pla hee hifi bochrrcen pre tofou fhe pueten cro fine Uw { hee od ple pore wu IBMiJun257408/2 Do not write outside the box Da not write outside the [o[1].[4] Results from electron-diffraction experiments lead to the equation: bom t R=R,AB Show that the equation provides evidence for the constant density of nuclear material, [2 marks] tng row fo mucha mas Mass = § > Volant youwMt> uy t a" = yn “tA 2 An. (Bal-$ Yon byt OW ox ett nu daainh Unrtlet Cheeky proof : MN IBMidun257408/2 4 Do not write outside the box (0 | 2) The derivation of the equation pl’ = aN M(C.)° (S$ based on several assumptions. [o[2|.[4] One of these assumptions is that particle motion is random. State what is meant by random particle motion. [2 marks] fewn AA port aw 2 fan ia a4 durefien wus pote inethan 7 whi [o[2].[2] State two other assumptions required for this derivation. [2 marks] a 1 (oldisteonl ove eye —= Ke + menvtn i A 1 pare Vv © neh 2 Jor velrme Wee i bu p t a 1 a A fe pete 7 Wn COAPey AL Nice easy written 9¢ Question 2 continues on the next page Turn over 05 IB/M/Jun25/7408/2 Do not write outside the box The average kinetic energy of the particles of an ideal gas is equal to Ser é This is not true for a real gas. [o[2].[4] Helium behaves as an ideal gas. The temperature of a sample of helium gas is increased from 27 °C to 77 °C. Calculate the change in the average kinetic energy of a helium atom in the sample. [1 mark] DMe = not bt bore h cont fo helan a ar dalferernie vot bt fit 23 -33 Jone Abe reat ) (77-27) = (earn) ; change in average kinetic energy = louse J [o[2].[5] When an ideal gas is heated at constant volume, all of the energy supplied by heating is used to increase the average kinetic energy of the particles. When water vapour is heated at constant volume, its specific heat capacity is 1400 Jkg! K!. Deduce whether Water Vieja laiaialtitaiitelthtaiaeiaiiiaeliibtiidalaiaialiaidit constant volume. Starting To get a bit tricky mass of a water molecule = 3,0 * 10 °° kg [3 marks] Qe mbar WA | fy 1k nevegt end ft rl Ql Baio 2* / jyoo + | = Upen FF OG = NbKe Ak aT eo - ny ae ‘te gi Se Q.0 Ferg Pty lune worty Se dives pt aed as on idee jes Turn over & UU IBAMJun25/7408/2 7 Do not write outside the A radioisotope thermoelectric generator (RTG) uses radioactive decay to generate al electrical energy. A vehicle that is used to examine the surface of Mars includes an RTG that initially contains 3.23 = 10° atoms of plutonium-238 [0[3].[4] Determine the initial mass of plutonium-238 in the RTG. [2 marks] N= 4aNpn Me = 246 5 ra! e Rig ee OO ware me nM =" . . "a 6.oaszr0 ** f Ss initial mass = (2 rKy kg st abit of chem 068 IBIMidun257408/2 8 10 Da not write: outside the (o[3].[3] The vehicle has a battery-powered laser that is used to vaporise small samples of ice. ton On Mars, ice changes directly from solid to vapour at a temperature of 0) °C. The ice does not form a liquid. The energy required to vaporise |.0 g of solid ice directly into water vapour is the same as the total energy required to melt |.0 g of ice and then to vaporise the melted ice. The laser produces an output power of 1.0 kW for a maximum time of 3.0 s before its battery needs to be recharged. The laser heats the ice from an initial temperature of -25 °C to a temperature of 0.0 °C. The laser then transfers energy to vaporise the ice at 0.0 °C. Determine whether the laser is able to vaporise 1.0 g of the ice that is initially at —25 °C before the battery needs to be recharged. specific heat capacity of ice =2, = specific latent heat of fusion of ice = 3. Back to back lo ng qs eS specific latent heat of vaporisation = 25305= [4 marks] Q he 7 shih —= gr) Ugaiel on fr fost MOT of ° a t ) r mo ued ) m=: aio" -dr ae Op» mear + me (aca = ty | - F » aad * te (gc yeehar + 33ua0e) Cia = atato? Talk ~ = ley Cy geurld? Ty, mh t do nyse se ger Qa mt 1 sa eno. U by = £fousio ae ara aroos aroet seg.r takes ST €. . = € rc Cremona 2 Tn MES oie rey ae Gtr bare hes us ie chief Aeros} fee okie wu IBMidun2s7408/2 10 1 Do not write outside the [o[4].[4] Mimas and Enceladus are moons of Saturn. box Mimas orbits at a height of 1.28 « 10° m above the surface of Saturn. The orbital period of Mimas is 0.94 Earth days. Enceladus orbits at a height of 1.80 = 10° m above the surface of Saturn. Calculate, in Earth days, the orbital period of Enceladus. radius of Saturn = 5.8 « 10’ m [3 marks] * é Rshir By staple Regalos ebato mM hee bei ye pense? = 2.3¢ar0? vA ker ls y On ies 4 4 Ta Be Tet te? te. [Tet = [ o-4u". a. ag200 bent leegaret * 46d) orbital period = 1.36 Earth days Question 4 continues on the next page Turn over 11 IB/Midun25/74082 11 13 Do not write outside the [o[4].[2] A student suggests that, over the range of distances shown in Figure 2, the bon gravitational field strength due to the mass of Saturn alone is approximately constant. Explain why the suggestion /s correct. [1 mark] ov =. an hat at ho cs j bp ro ¢ oy Sfefeyal geet Dont hue fut wit be tt os hae given rugs [o]4|.[3] At a point P, the resultant gravitational field strength due to Saturn and Titan is zero. Determine, using the solid line in Figure 2, the distance from Saturn to P. Mar f ided were & ales hal fiuld <0 [1 mark) Ghar ce® distance = 12-04 evo m [o[4].[4] The centre of Titan is 12.22 = 10° m from the centre of Saturn. Show that the gravitational potential due to the mass of Titan at a distance of 12.08 « 10° m from Saturn is about ~7 « 10° J kg!. Go on to determine the mass of Titan. V V [3 marks] Thy = V, t Vv i tr 4 Vicha Vrtd — Vien wh Ip rade iow ~Bagl-- 2.132 2-0 06SF KIO. L Cr pe Fp & -7a 10% % at Ver Tia Ware C= 14. 82x — Rog prot it = Mate? ya Dead question cus of graph mass = Juageo** kg 8 Turn over > 13 IBA Jun25/7408/2 13 14 fo[s5|.[1| A material used between the plates of a capacitor has a dielectric constant of 7.0 State what is meant by a dielectric constant of 7.0 [1 mark] fre pele perrath uh ig Wee cliele stmt _4 T hath leet rw het fre space Ihauw ergot aber (AGEYpeS Dawes Cnprented Ay ye Oe thnl pel prepnt Figure 3 shows a circuit that is used to charge and discharge a capacitor. Figure 3 ban fo dot tenet opened “hy « Brana teh penitue sah wan fi = a 4 who fw ek wll Val or tal —— « Alto jah piitins The battery has negligible internal resistance. =e aNeows If The two resistors in the circuit are identical. be, Tet a elt The capacitor is fully charged and the switch is then moved from position A to position B at time 1=0 Figure 4 shows the variation of the microammeter reading with ¢ until = 120 s. Te AC Cheeky bit of capacitance® G. 36.5 Ke fr oles por “ser ln | Z| 2 € Teg wes feo wer are 14 IBMiJun257408/2 16 Do not write: outside the [o[5|.[4] The capacitor is fully discharged and then the switch is moved from position B to non position A as shown in Figure 3. Draw, on Figure §, the variation of the microammeter reading with time after the switch is moved to position A. In Figure 5, the time is 0 at the instant when the switch is moved to position A. [3 marks] | t +t Ht | microammeter reading / pA “8. IBIMidun2s74082 16 17 poaching lons orbit Jupiter in a ring called a plasma torus as shown in Figure 6. bon This question is about applying gravitational, magnetic and electric fields to a particle in the plasma. Figure 6 plasma torus Jupiter ion An ion travels in a circular path at a speed of 74.2 kms"! and ata distance of 4.22 10* m from the centre of Jupiter, [o[6|.[4] Student A suggests that the gravitational force acting on the ion due to Jupiter provides the centripetal acceleration of the ion. Deduce whether this suggestion is correct. mass of Jupiter = 1.90 « 10°7 kg [3 marks] ae ch GG7AtO x |.axt0?” ; ct = I (& aarrat)? a a . wt Sacariet BAS sie Gone 2 tora? 4 ag eo” oam* ZB rs.er prvktnet fre iy mt purad ty atunt fo pa rele pati - Question 6 continues on the next page Turn over 17 IB/Midun25/7408/2 17 19 Do not write outside the The ion has a charge of +3.20 x 10°!’ C and a mass of 5.31 * 10°°° kg. box [0|6].[3] The ion moves with a speed of 74.2 km s” in a circle of radius 4,22 « 10* m. Calculate the magnitude of the magnetic flux density required for this motion. State, in fundamental (base) units, the unit for your answer. Ignore any contribution from the gravitational field. “14 Qe 84x" Co, = Bav - 2b m. 3x10 KH ‘ me, bav jot . ts “aed Med ee my op rov rq vr 74 carer 2 ? 2 fap quaaro es 4a2al x § o419° | EF. ble mee gmt a = 2-4%a'0 25 im aig Te RM 7 ae magnetic flux density = 2.4 x10" unit = & rial [0|6|.[4] Anelectric field of strength 371 j\V m”! can also accelerate the ion. Calculate the acceleration of the ion due to this electric field. [3 marks] €Q £ i F-€Q Gs es ” =4 emsle -fagne™ SO $-4).410778 acceleration = 2226 ms? Question 6 continues on the next page Turn over > 19 IB/WJun25/7408/2 19 20 Do not write: outside the fol6|.[5| The plasma torus contains two ions X and Y as shown in Figure 8. ton X has a charge of +2e. Y has a charge of tle. Assume that each ion acts as a point charge. Figure 8 2.0cm q i Hl ' ! H ae | i KS +2-==5 an i \ 2.0cm Ye------- e Calculate the magnitude of the resultant electric field strength at point P in Figure 8 due to the two ions. [3 marks] fe KS : me “7 Dont mind it” f OFA a weg par” Cy xs aaa 2 iit” oO Cn ey 2 hme, |.6ar0 BE 2a arent o.0a* . ie P Ce I Qinsne ee ae ee en resultant electric field strength = Ruste” Vm! | 13 Overall decent section. Some gs took abit too long for what they were worth 20 IBMidun257408/2 20 
