MATH 515 Homework Assignment 4: Convexity and Concavity, Assignments of Mathematics

Solutions to problem 8 and problem 9 from homework assignment 4 of the math 515 course, spring 09. Problem 8 deals with the relationship between convex sets and linear combinations of vectors, while problem 9 discusses convex, concave, and strictly convex functions, and their relationship with the derivative. The document also includes proofs for jensen's inequality and holder's inequality.

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Homework Assignment 4, MATH 515, Spring 09
Problem 8) (4 pts) A subset Dof a real vector space Eis convex if for all
x, y Dand 0 < t < 1 it follows tx + (1 t)yD. Show the following: If
x1, . . . , xnDthen also t1x1+. . . +tnxnDfor all t1, . . . , tn>0 such that
Pn
i=1 ti= 1. Conversely, for given x1, . . . , xnEthe set of all combinations as
above is a convex set.
Problem 9) (12 pts) (a) Let DRnbe convex. A function f:DRis
called convex if f(tx+(1t)y)tf(x)+(1t)f(y) for all x, y Dand 0 <t<1.
The function fis called strictly convex if strict inequality holds whenever x6=y
and 0 <t<1. The function fis concave respectively strictly concave if f
is convex respective strictly convex. Show the following: If f: (a,b)Ris
differentiable then fis convex f0is increasing, and fis concave f0
is decreasing. In particular, if fis twice differentiable and f00 0 then fis
convex, while if f00 0 then fis concave. Also f00 >0 then fis strictly convex
and if f00 <0 then fis strictly concave.
(b) Prove Jensen’s inequality: For Da convex subset of a vector space Eand
f:DRa concave function show that
n
X
i=1
tif(xi)f n
X
i=1
tixi!
whenever x1,...xnD,t1, . . . , tn(0,1) and Pn
i=1 ti= 1. Furthermore, if
fis strictly concave then equality holds if and only if x1=.. . =xn. Hint:
induction on n.
(c) Apply (b) to f(x) = log(x) to show that if a1,...an0 and p1, . . . , pn>0
are real numbers with Pn
i=1 pi= 1 then
n
Y
i=1
api
i
n
X
i=1
piai
with equality if and only if a1=. . . =an.
(d) Prove that for a, b 0 and p, q > 1 with 1
p+1
q= 1 it follows ab ap
p+bq
q
with equality if and only if ap=bq.
Problem 10 (8 pts) Prove older’s inequality: Suppose p, q > 1 and 1
p+1
q= 1.
Then for complex numbers a1, . . . , an, b1, . . . , bnwe have
n
X
k=1
akbk
n
X
k=1
|ak|p!1/p n
X
k=1
|bk|q!1/q
with equality if and only if all akare 0 or |bk|q=t|ak|pand akbk=e|akbk|for
all kand some tand θ. Hints: Reduce to the case Pn
k=1 |ak|p=Pn
k=1 |bk|q= 1.

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Homework Assignment 4, MATH 515, Spring 09

Problem 8) (4 pts) A subset D of a real vector space E is convex if for all x, y ∈ D and 0 < t < 1 it follows tx + (1 − t)y ∈ D. Show the following: If x∑ 1 ,... , xn ∈ D then also t 1 x 1 +... + tnxn ∈ D for all t 1 ,... , tn > 0 such that n i=1 ti^ = 1. Conversely, for given^ x^1 ,... , xn^ ∈^ E^ the set of all combinations as above is a convex set.

Problem 9) (12 pts) (a) Let D ⊂ Rn^ be convex. A function f : D → R is called convex if f (tx+(1−t)y) ≤ tf (x)+(1−t)f (y) for all x, y ∈ D and 0 < t < 1. The function f is called strictly convex if strict inequality holds whenever x 6 = y and 0 < t < 1. The function f is concave respectively strictly concave if −f is convex respective strictly convex. Show the following: If f : (a, b) → R is differentiable then f is convex ⇐⇒ f ′^ is increasing, and f is concave ⇐⇒ f ′ is decreasing. In particular, if f is twice differentiable and f ′′^ ≥ 0 then f is convex, while if f ′′^ ≤ 0 then f is concave. Also f ′′^ > 0 then f is strictly convex and if f ′′^ < 0 then f is strictly concave.

(b) Prove Jensen’s inequality: For D a convex subset of a vector space E and f : D → R a concave function show that

∑^ n

i=

tif (xi) ≤ f

( (^) n ∑

i=

tixi

whenever x 1 ,... xn ∈ D, t 1 ,... , tn ∈ (0, 1) and

∑n i=1 ti^ = 1.^ Furthermore, if f is strictly concave then equality holds if and only if x 1 =... = xn. Hint: induction on n.

(c) Apply (b) to f (x) = log(x) to show that if a 1 ,... an ≥ 0 and p 1 ,... , pn > 0 are real numbers with

∑n i=1 pi^ = 1 then ∏^ n

i=

ap i i≤

∑^ n

i=

piai

with equality if and only if a 1 =... = an.

(d) Prove that for a, b ≥ 0 and p, q > 1 with (^1) p + (^1) q = 1 it follows ab ≤ a

p p +^

bq q with equality if and only if ap^ = bq^.

Problem 10 (8 pts) Prove H¨older’s inequality: Suppose p, q > 1 and (^1) p + (^1) q = 1. Then for complex numbers a 1 ,... , an, b 1 ,... , bn we have

∣ ∣ ∣ ∣ ∣

∑^ n

k=

akbk

( (^) n ∑

k=

|ak|p

) 1 /p ( (^) n ∑

k=

|bk|q

) 1 /q

with equality if and only if all ak are 0 or |bk|q^ = t|ak|p^ and akbk = eiθ^ |akbk| for all k and some t and θ. Hints: Reduce to the case

∑n k=1 |ak| p (^) = ∑n k=1 |bk| q (^) = 1.