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Solutions to problem 8 and problem 9 from homework assignment 4 of the math 515 course, spring 09. Problem 8 deals with the relationship between convex sets and linear combinations of vectors, while problem 9 discusses convex, concave, and strictly convex functions, and their relationship with the derivative. The document also includes proofs for jensen's inequality and holder's inequality.
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Homework Assignment 4, MATH 515, Spring 09
Problem 8) (4 pts) A subset D of a real vector space E is convex if for all x, y ∈ D and 0 < t < 1 it follows tx + (1 − t)y ∈ D. Show the following: If x∑ 1 ,... , xn ∈ D then also t 1 x 1 +... + tnxn ∈ D for all t 1 ,... , tn > 0 such that n i=1 ti^ = 1. Conversely, for given^ x^1 ,... , xn^ ∈^ E^ the set of all combinations as above is a convex set.
Problem 9) (12 pts) (a) Let D ⊂ Rn^ be convex. A function f : D → R is called convex if f (tx+(1−t)y) ≤ tf (x)+(1−t)f (y) for all x, y ∈ D and 0 < t < 1. The function f is called strictly convex if strict inequality holds whenever x 6 = y and 0 < t < 1. The function f is concave respectively strictly concave if −f is convex respective strictly convex. Show the following: If f : (a, b) → R is differentiable then f is convex ⇐⇒ f ′^ is increasing, and f is concave ⇐⇒ f ′ is decreasing. In particular, if f is twice differentiable and f ′′^ ≥ 0 then f is convex, while if f ′′^ ≤ 0 then f is concave. Also f ′′^ > 0 then f is strictly convex and if f ′′^ < 0 then f is strictly concave.
(b) Prove Jensen’s inequality: For D a convex subset of a vector space E and f : D → R a concave function show that
∑^ n
i=
tif (xi) ≤ f
( (^) n ∑
i=
tixi
whenever x 1 ,... xn ∈ D, t 1 ,... , tn ∈ (0, 1) and
∑n i=1 ti^ = 1.^ Furthermore, if f is strictly concave then equality holds if and only if x 1 =... = xn. Hint: induction on n.
(c) Apply (b) to f (x) = log(x) to show that if a 1 ,... an ≥ 0 and p 1 ,... , pn > 0 are real numbers with
∑n i=1 pi^ = 1 then ∏^ n
i=
ap i i≤
∑^ n
i=
piai
with equality if and only if a 1 =... = an.
(d) Prove that for a, b ≥ 0 and p, q > 1 with (^1) p + (^1) q = 1 it follows ab ≤ a
p p +^
bq q with equality if and only if ap^ = bq^.
Problem 10 (8 pts) Prove H¨older’s inequality: Suppose p, q > 1 and (^1) p + (^1) q = 1. Then for complex numbers a 1 ,... , an, b 1 ,... , bn we have
∣ ∣ ∣ ∣ ∣
∑^ n
k=
akbk
( (^) n ∑
k=
|ak|p
) 1 /p ( (^) n ∑
k=
|bk|q
) 1 /q
with equality if and only if all ak are 0 or |bk|q^ = t|ak|p^ and akbk = eiθ^ |akbk| for all k and some t and θ. Hints: Reduce to the case
∑n k=1 |ak| p (^) = ∑n k=1 |bk| q (^) = 1.