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A step-by-step solution to calculate the velocity at a point on an airfoil surface in an isentropic flow, given the freestream conditions and the pressure at the point. The solution involves the use of the isentropic relation and the mach number.
Typology: Assignments
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โ
= 0.61 atm, ๐
โ
= 0.819 kg/m
3
, and ๐
โ
m/s. At a point on the airfoil surface, the pressure is 0.5 atm. Assuming isentropic
flow, calculate the velocity at that point.
โ
= 0. 61 atm
โ
= 0. 819 kg/m
3
โ
= 300 m/s
P = 0.5 atm
โ
โ
โ
โ
๐
โ
๐
โ
๐
โ
( 0. 61 ๐๐ก๐)(
101 , 325 ๐๐
1 ๐๐ก๐
)
( 0. 819
๐๐
๐
3
)( 287. 08
๐ฝ
๐๐โ๐พ
โ
๐
โ
๐ โ
๐
โ
๐
๐
โ
๐
โ
๐
๐
Name: ALDECOA, Mico Onil Ram
BLEN, Juliane Nicole A.
VILLARUEL, Pee-Jaye
Instructor: Engr. Roberto Renigen
Submission Date: 18 March 2024
Rating:
โ
โ
๐
๐ โ
๐
โ
2
๐
2
2
โ
โ
2
2
2
1
๐
๐ โ
1
๐ โ
2
๐ 2
2
๐
๐
โ
1
2
2
โ
2
2
2
๐
โ
2
(
๐
๐
โ
)
1
2
2
๐
โ
2
(
๐
๐
โ
)
1
2
๐
โ
2
(
๐
๐
โ
)
1
2
( 0. 923 )
2
(
5
61
)
1
2
3
Outside the converging-diverging nozzle, the pressure is atmospheric and designed
to have a Mach No. of 1.0 and 1. 5 at the throat and exit, respectively. The area at
the throat is 0.11m
2
. Calculate the following:
(a) Temperature and speed of sound at the tank
(b) Pressure, density, temperature, and speed of sound at the throat
(c) Mass flow at the exit
o
= 196.32 KPa = 196,320 Pa
ฯ o
= 1.9 kg/m
3
Area at the throat (๐ด
๐ก
) = 0.11m
2
(a) ๐
๐
๐ 0
(b) ๐
๐
๐
๐
๐
๐
(c) แน
๐ธ
(a) ๐
๐
= ฯ o
๐
๐
๐ ๐
๐๐
196 , 320 Pa
( 1. 9
๐๐
๐
3
)( 287. 08
๐ฝ
๐๐โ๐พ
)
๐
๐
๐
๐
= 380.38 m/s
(b)
๐
๐ก
๐
0
(๐
1
)
2
(๐
2
)
2
๐
( 1 )
2
( 1. 5 )
2
๐
= 101.23 Kpa = 101,230 Pa
๐ ๐
๐ ๐
๐ ๐
๐ ๐
1
๐
๐
๐
๐
๐
1
(๐
๐
๐
23 ๐พ๐๐
32 ๐พ๐๐
1
๐๐
๐
3
๐
๐๐
๐
3
๐
๐
๐
๐
๐
๐
๐
๐
๐
( 1. 184
๐๐
๐
3
) ( 287. 08
๐ฝ
๐๐โ๐พ
)
๐
Speed of Sound at that section
Va T
๐
Va T
Va T
= 346.01 m/s