Algebra-based Physics II, Exams of Algebra

These are called nucleons. What distinguishes different elements in the periodic table is the # of protons they have in their nucleus. This is ...

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Algebra-based Physics II
Dec. 3rd: Chap 31 Nuclear Physics and
Radioactivity
Announcements:
Final exam: Mon-Wed.
Extra Review session: Sunday 5-7:00 PM, Nicholson #130
How to find nuclear binding energy?
How to calculate radius of a nucleus?
How to identify different radioactive decay?
How to determine radioactive activity?
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Algebra-based Physics II

Dec. 3rd: Chap 31 Nuclear Physics and

Radioactivity

Announcements:

  • Final exam: Mon-Wed.
  • Extra Review session: Sunday 5-7:00 PM, Nicholson #
  • How to find nuclear binding energy?
  • How to calculate radius of a nucleus?
  • How to identify different radioactive decay?
  • How to determine radioactive activity?

Chapter 31 – Nuclear Physics and Radioactivity

31.1 Nuclear Structure

We’ve been studying atomic structure – the Rutherford model of the atom, where electrons orbit around a nucleus.

And now we know that it takes Quantum Mechanics to correctly describe the nature of these orbits.

But what about the nucleus?

Well, so far we just know about protons.

But, in 1932 scattering experiments by English physicist James Chadwick discovered another particle in the nucleus which had no charge  neutron.

Shorthand notation for element representation:

X

A

So oxygen would be: Z

O

16 8 The mass of the elements is usually given in atomic mass units ( u ).

1 u 1.6605 10 kg

 

Nuclei that contain the same number of protons but a different number of neutrons are called isotopes.

For example, boron exists in nature as two stable isotopes:

B

10 5

B

11 5 Most boron atoms have 6 neutrons (81.1%), but some (18.9%) have only 5 neutrons.

The atomic mass number (A) listed on the periodic table is the average atomic mass of the isotopes, for boron this is 10.811.

30.2 Strong Nuclear Force and Stability

What does the nucleus look like? Why Coulomb repulsion does tear apart nucleus? The protons and neutrons are clustered together in a blob that is approximately spherical. The radius of the nucleus is ~ 1 fm = 1 × 10 -15^ m.

Experiments show that: 15 1 / 3 r ( 1. 2 10 m) A   

The Nucleon Density, which is the # of protons and neutrons per unit volume, is the same for all atoms!

So we have this spherical blob of positive protons and neutral neutrons.

How does it stay together???

Example: He nucleus: 2 protons and 2 neutrons

Most nuclei listed in the periodic table are stable, but some are not.

The stability of a nucleus depends on the balancing between the electrostatic repulsion between protons and the strong nuclear attractive force between all nucleons.

Every proton in the nucleus feels Coulombic repulsion from every other proton, since the electro- static force is long-ranged.

But each proton and neutron only feels the strong nuclear force from its closest neighbors. To compensate for this, the more protons I add to the nucleus, an even greater number of neutrons must be added to try and balance the electrostatic force. As I create larger and larger nuclei, the neutron number keeps getting bigger and bigger. Notice how the neutron # deviates from the N = Z line for large nuclei.

Eventually, as more and more protons are added, no # of extra neutrons can compensate for the large electrostatic repulsion, and the nucleus breaks apart.

This occurs at Z = 83, which is bismuth (Bi).

Any element with an atomic number Z > 83 will be unstable and break apart over time. It will rearrange itself into a stable nuclei. This process is called Radioactivity.

31.3 Nuclear Binding Energy

In order to separate two nucleons, we have to overcome the strong nuclear force.

We refer to this as the Nuclear Binding Energy.

To analyze this problem quantitatively, we have to use Einstein’s famous E =mc^2.

This equation gives us the rest mass energy. Thus, a change in mass of a system equals

a change in rest mass energy: D E = D mc^2.

The binding energy of the nucleus appears as extra mass in the separated nucleons.

In other words, the sum of the masses of the individual nucleons is greater than

the mass of the stable nucleus by an amount D m , where D m = the mass defect of

the nucleus.

The nuclear binding energy then is just this mass converted to energy:

2 2 Binding Energy  (mass defect) c  D mc

Example: The binding energy of a helium nucleus:

The most abundant isotope of helium has a nucleus whose mass is 6.6447× 10 -27^ kg. For this nucleus, calculate (a) its mass defect and (b) its binding energy.

42 He

  • Binding Energy 

Nucleus +

2 separated protons and 2 separated neutrons

Solution:

(a) The massdefect Themassof theseparatednucleons-Themassof thestablenucleus

D m  2 mp  2 mnm Henucleus 27 27 27 2 ( 1. 6726 10 ) 2 ( 1. 6749 10 ) 6. 6447 10

    D m       29 5.03 10 kg

  

(b)Binding Energy, E (D m ) c^2  E ( 5. 03  10 ^29 )( 3  108 )^2

  1. 53 10 J 2. 83 10 eV 28. 3 MeV 12 7       This is 2 million times greater energy than it takes to remove an electron from an atom!

31.4 Radioactivity

So any nucleus with more than 83 protons is unstable, or radioactive. These nuclei disintegrate over time, and during this process, 3 types of radiation may be produced:

The 3 types of radiation were discovered by Becquerel in 1896, and then later labeled by Rutherford:

  1. a Rays
  2. b Rays
  3. g Rays

Increasing Energy

  1. a Rays are actually a particles (helium nuclei). They consist of 2 protons and 2 neutrons.
  2. b Rays are electrons.
  3. g Rays are high-energy photons.

A radioactive nucleus is emitting all 3 types of radiation. The radiation

travels through a uniform magnetic field that is directed everywhere into

the page and follows the paths shown. What kind of radiation follows

path 3?

Alpha rays^ Beta rays Gamma rays No way to tell...

17%

3%

12%

68%

1 2

3

Clicker Question 31 - 2

  1. Alpha rays
  2. Beta rays
  3. Gamma rays
  4. No way to tell.

U Th He 4 2

234 90

238 92  

After the initial alpha decay, the daughter nucleus (^234 Th) is still radioactive. It then undergoes beta decay:

 ThPa b^ Explicitly, we write this as: Th Pa e 0

  • 1

234 91

234 90  

Parent Nucleus (P)

Daughter Nucleus (D)

b particle (electron) So, in general then, for b decay, we have:

P D e

A

Z 1

A

Z    

*Notice again, that the charge is conserved!

So where does the electron come from???

It turns out that neutrons themselves are unstable, and they will decay into a proton. When the neutron decays into a proton, it releases an electron (b-) and an antineutrino (n-e)

2. b Radiation:

Beta rays are negatively charged particles, and experiments show them to be electrons.

There is a 2nd^ type of b decay called b+^ decay.

Here, the nucleus emits a positron.

The positron is the electron’s antiparticle : it’s antimatter!

The positron has the same mass and spin of the electron, but opposite electric charge. The positron is created when a nuclear proton is transformed into a neutron:

P D e

A

Z 1

A

Z    

Parent Nucleus (P)

Daughter Nucleus (D)

b^ particle (electron)

There is a 3rd^ type of b decay called electron capture:

Here, the nucleus pulls in an orbital electron from the K-shell.

31.6 Radioactivity

Assume I have a chunk of radioactive material that contains N radioactive nuclei, or parent nuclei. Which one of these nuclei is going to decay, and when?

Since radioactivity is a quantum-mechanical process , we can’t know with certainty. We can only predict when a particular nucleus will decay. Thus, radioactivity is a statistical process.

As time passes, some of the nuclei will decay, and N will decrease.

To help describe this process, it’s useful to define something called the half-life:

It is represented by T 1/2, and it is the time it takes for ½ of the nuclei present to decay.

So T 1/2 will have units of time [s]. If the half-life is long, it can also be represented in years.

As an example, let’s say that I have some radioactive element X which has a half- life of 1 year, and I originally start with 100 atoms of it.

How many atoms will be left after 1 year, 2 years, 3 years, and so on???

Time # of X atoms left

0 100

1 year (1 half-life) 50 (1/2 left)

2 years (2 half-lives) 25 (1/4 left)

3 years (3 half-lives) 12.5 (1/8 left)

4 years (4 half-lives) 6.25 (1/16 left)

..

n years (n half-lives) (^) n n (1/2 n^ left)

N 2 2

100 

Let’s make a plot of the atoms left versus time: