Algebra( solving logarithmic equations), Lecture notes of Mathematics

Lecture slides on how to solve logarithmic equations easily

Typology: Lecture notes

2018/2019

Uploaded on 11/24/2019

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Lecture 2
Logarithms
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Lecture 2

Logarithms

A logarithm or simply log for short is

another name for a power or index.

When the base of a logarithm is not

written it, means it is in base 10.

The logarithms of a negative number

does not exist.

Key Notes

log 2 8 = 3

  1. W ๐‘Ÿ๐‘–๐‘ก๐‘’ 2 3 = 8 ๐‘–๐‘› ๐‘™๐‘œ๐‘”๐‘Ž๐‘Ÿ๐‘–๐‘กh๐‘š๐‘–๐‘ ๐‘“๐‘œ๐‘Ÿ๐‘š.

2 .๐‘Š๐‘Ÿ๐‘–๐‘ก๐‘’ 4 2 = 16 ๐‘–๐‘›๐‘™๐‘œ๐‘”๐‘Ž๐‘Ÿ๐‘–๐‘กh๐‘š๐‘–๐‘ ๐‘“๐‘œ๐‘Ÿ๐‘š.

log 4 16 = 2

log 5 1 = 0

  1. W ๐‘Ÿ๐‘–๐‘ก๐‘’ 5 0 = 1 ๐‘–๐‘› ๐‘™๐‘œ๐‘”๐‘Ž๐‘Ÿ๐‘–๐‘กh๐‘š๐‘–๐‘ ๐‘“๐‘œ๐‘Ÿ๐‘š.

Rule 1 ๐ฅ๐จ๐  ๐’ƒ ๐’Ž + ๐ฅ๐จ๐  ๐’ƒ ๐’ = ๐ฅ๐จ๐  ๐’ƒ ๐’Ž๐’ 1_._ log 2 4 +log 2 3 =log 2 ( 4 ร— 3 )=log 2 12

  1. log 3 5 + log 3 7 =log 2 ( 5 ร— 7 )=log 2 35
  2. log 5 11 + log 2 9 =log 2 ( 11 ร— 9 )=log 2 99 ๐บ๐‘–๐‘ฃ๐‘’๐‘›๐‘กh๐‘Ž๐‘ก ๐‘š ๐‘Ž๐‘›๐‘‘ ๐‘› ๐‘Ž๐‘Ÿ๐‘’ ๐‘๐‘œ๐‘ ๐‘–๐‘ก๐‘–๐‘ฃ๐‘’

Rule 2

๐’ƒ

๐’ƒ

๐’ƒ (^) (

)

  1. log 10 15โˆ’ log 10 5= lo g (^10) ( 15 5 ) = lo g 10 3
  2. log 3 70โˆ’ lo g 3 10= lo g (^3) ( 70 10 ) = lo g 3 7
  3. lo g 5 12โˆ’ lo g 5 3= lo g (^5) ( 12 3 ) = log 5 4

Rule 4 ๐ฅ๐จ๐  ๐’ƒ ๐’Ž = ๐ฅ๐จ๐  ๐’‚ ๐’Ž ๐ฅ๐จ๐  ๐’‚ ๐’ƒ

  1. log 2 8 = log 5 7 log 5 2
  2. log 7 12 = log 3 12 log 3 7
  3. log 3 4 = log 2 4 log 2 3

Rule 5 ๐ฅ๐จ๐  ๐’ƒ ๐’ƒ = ๐Ÿ

  1. log 4 4 = 1
  2. log 7 7 = 1
  3. log 9 9 = 1

Illustrative examples

Example 1 log 3 24 + log 3 15 โˆ’ log 3 10 =log 3 ( 24 ร— 15 ) โˆ’ log 3 10 ยฟ log 3 360 โˆ’ log 3 10 ยฟ log (^3) ( 360 10 ) ยฟ log 3 36 log 3 24 + log 3 15 โˆ’ log 3 10 Simplify Solution

Example 2 Expand log ( 10 ๐‘ฅ 4 3 ๐‘ฆ (^2) )

log ( 10 ๐‘ฅ 4 3 ๐‘ฆ (^2) ) log 10 ๐‘ฅ 4 โˆ’ log 3 ๐‘ฆ 2 log 10 + log ๐‘ฅ 4 โˆ’ (log 3 + log ๐‘ฆ 2 ) log 10 + 4 log ๐‘ฅ โˆ’ log 3 โˆ’ 2 log ๐‘ฆ

Example 3 log 3 ( 9 ๐‘ฅ 4 โˆš ๐‘ฆ^ ) =log 3 9 ๐‘ฅ 4 โˆ’ log 3 ๐‘ฆ 1 2 ยฟ log 3 9 +log 3 ๐‘ฅ 4 โˆ’ log 3 ๐‘ฆ 1 2 ยฟ log 3 3 2

  • 4 log 3 ๐‘ฅ โˆ’ 1 2 log 3 ๐‘ฆ ยฟ 2 log 3 3 + 4 log 3 ๐‘ฅ โˆ’ 1 2 log 3 ๐‘ฆ ยฟ 2 + 4 log 3 ๐‘ฅ โˆ’ 1 2 log 3 ๐‘ฆ Write the term log^3 ( 9 ๐‘ฅ 4 โˆš ๐‘ฆ^ ) . ๐‘บ๐’๐’๐’–๐’•๐’Š๐’๐’

Solution (b)

Example 4 Conโ€™t

Trial Questions