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Algebraic expressions and polynomials, explaining the concepts of constants, variables, terms, like terms, and unlike terms. It covers the identification of variables and constants, the definition of polynomials, and the fundamental operations on them. Students will learn how to identify and determine the degree of polynomials, as well as find the value of a polynomial for given values of variables.
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Algebraic Expressions and Polynomials
Notes
Algebra
So far, you had been using arithmetical numbers, which included natural numbers, whole numbers, fractional numbers, etc. and fundamental operations on those numbers. In this lesson, we shall introduce algebraic numbers and some other basic concepts of algebra like constants, variables, algebraic expressions, special algebraic expressions, called polynomials and four fundamental operations on them.
After studying this lesson, you will be able to
Algebraic Expressions and Polynomials
Notes
Algebra
You are already familiar with numbers 0, 1, 2, 3, ...., ,....^2 ,... 4
etc. and operations of
addition (+), subtraction (–), multiplication (×) and division (÷) on these numbers. Sometimes, letters called literal numbers , are also used as symbols to represent numbers. Suppose we want to say “The cost of one book is twenty rupees”.
In arithmetic, we write : The cost of one book = ` 20
In algebra, we put it as: the cost of one book in rupees is x. Thus x stands for a number.
Similarly, a, b, c, x, y, z, etc. can stand for number of chairs, tables, monkeys, dogs, cows, trees, etc. The use of letters help us to think in more general terms.
Let us consider an example, you know that if the side of a square is 3 units, its perimeter is 4 × 3 units. In algebra, we may express this as
p = 4 s
where p stands for the number of units of perimeter and s those of a side of the square.
On comparing the language of arithmetic and the language of algebra we find that the language of algebra is
(a) more precise than that of arithmetic.
(b) more general than that of arithmetic.
(c) easier to understand and makes solutions of problems easier.
A few more examples in comparative form would confirm our conclusions drawn above:
Verbal statement Algebraic statement
(i) A number increased by 3 gives 8 a + 3 = 8
(ii) A number increased by itself gives 12 x + x = 12, written as 2x = 12
(iii) Distance = speed × time d = s × t, written as d = st
(iv) A number, when multiplied by itself b × b + 5 = 9, written as b^2 + 5 = 9 and added to 5 gives 9
(v) The product of two successive natural y × (y + 1) = 30, wrtten as y (y + 1) = 30, numbers is 30 where y is a natural number.
Since literal numbers are used to represent numbers of arithmetic, symbols of operation +, –, × and ÷ have the same meaning in algebra as in arithmetic. Multiplication symbols in algebra are often omitted. Thus for 5 × a we write 5a and for a × b we write ab.
Algebraic Expressions and Polynomials
Notes
Algebra
One or more signs + or – separates an algebraic expression into several parts. Each part along with its sign is called a term of the expression. Often, the plus sign of the first term is omitted in writing an algebraic expression. For example, we write x – 5y + 4 instead of writing + x – 5y + 4. Here x, – 5y and 4 are the three terms of the expression.
In 3
xy, 3
is called the numerical coefficient of the term and also of xy. coefficient of x is
y and that of y is 3
x. When the numerical coefficient of a term is +1 or –1, the ‘1’ is
usually omitted in writing. Thus, numerical coefficent of a term, say, x^2 y is +1 and that of –x^2 y is –1.
An algebraic expression, in which variable(s) does (do) not occur in the denominator, exponents of variable(s) are whole numbers and numerical coefficients of various terms are real numbers, is called a polynomial.
In other words,
(i) No term of a polynomial has a variable in the denominator;
(ii) In each term of a polynomial, the exponents of the variable(s) are non-negative integers; and
(iii) Numerical coefficient of each term is a real number.
Thus, for example, 5, 3x –y , 3
a – b+ 2
and x 2y xy^8 4
− + − are all polynomials
whereas , and^5
− x + y x + x
x (^) are not polynomials.
x^2 +8 is a polynomial in one variable x and 2x^2 + y^3 is a polynomial in two variables x and y. In this lesson, we shall restrict our discussion of polynomials including two variables only.
General form of a polynomial in one variable x is:
a 0 + a 1 x + a 2 x^2 + ....+anxn
where coefficients a 0 , a 1 , a 2 , ....an are real numbers, x is a variable and n is a whole number. a 0 , a 1 x, a 2 x^2 , ...., anxn^ are (n + 1) terms of the polynomial.
An algebraic expression or a polynomial, consisting of only one term, is called a monomial.
Thus, –2, 3y, –5x^2 , xy, 2
x^2 y^3 are all monomials.
An algebraic expression or a polynomial, consisting of only two terms, is called a binomial. Thus, 5 + x, y 2 – 8x, x^3 – 1 are all bionomials.
Algebraic Expressions and Polynomials
Notes
Algebra
An algebraic expression or a polynomial, consisting of only three terms, is called a trinomial. Thus x + y + 1, x 2 + 3x + 2, x 2 + 2xy + y^2 are all trinomials. The terms of a polynomial, having the same variable(s) and the same exponents of the variable(s), are called like terms. For example, in the expression 3xy + 9x + 8xy – 7x + 2x 2 the terms 3xy and 8 xy are like terms; also 9x and –7x are like terms whereas 9x and 2x^2 are not like terms. Terms that are not like, are called unlike terms. In the above expression 3xy and –7x are also unlike terms.
Note that arithmetical numbers are like terms. For example, in the polynomials x^2 + 2x + 3 and x^3 – 5, the terms 3 and – 5 are regrded as like terms since 3 = 3x^0 and
Solution: Variables : x and y Constants: 2 and 5 Example 3.2: In 8x^2 y^3 , write the coefficient of (i) x^2 y^3 (ii) x^2 (iii) y^3 Solution: (i) 8x^2 y^3 = 8 × (x 2 y^3 )
∴ Coefficient of x^2 y^3 is 8 (ii) 8x^2 y^3 = 8y^3 ×(x^2 ) ∴ Coefficient of x^2 is 8y^3. (iii) 8x^2 y^3 = 8x^2 ×(y^3 ) ∴ Coefficient of y^3 is 8x^2.
Example 3.3: Write the terms of expression
3 x^2 y − x − y +
Solution: The terms of the given expression are
3x 2 y, y 3
x, 2
Algebraic Expressions and Polynomials
Notes
Algebra
(i) 2 + abc (ii) a + b + c + 2 (iii) 2
x 2 y−2xy^2 −
(iv) x^3 y^2 8
(i) – xy 2 + x^2 y + y^2 + 3
y^2 x (ii) 6a + 6b – 3ab + 4
a^2 b + ab
(iii) ax 2 + by 2 + 2c – a 2 x – b 2 y – 3
c^2
(i) 3
x^3 + 1 (ii) 5 2 – y^2 – 2 (iii) 4x–3^ + 3y
(iv) 5 (^) x + y+ 6 (v) 3x 2 – 2 y^2 (vi) y 2 – (^) y 2
(i) x 3 + 3 (ii) 3
x^3 y^3 (iii) 2y^2 + 3yz + z^2
(iv) 5 – xy – 3x^2 y^2 (v) 7 – 4x^2 y^2 (vi) – 8x^3 y^3
The sum of the exponents of the variables in a term is called the degree of that term. For
example, the degree of 2
x^2 y is 3 since the sum of the exponents of x and y is 2 + 1, i.e.,
Algebraic Expressions and Polynomials
Notes
Algebra
A polynomial has a number of terms separated by the signs + or –. The degree of a polynomial is the same as the degree of its term or terms having the highest degree and non-zero coefficient.
For example, consider the polynomial
3x 4 y^3 + 7 xy 5 – 5x 3 y^2 + 6xy
It has terms of degrees 7, 6, 5, and 2 respectively, of which 7 is the highest. Hence, the degree of this polynomial is 7.
A polynomial of degree 2 is also called a quadratic polynomial. For example, 3 – 5x + 4x^2 and x 2 + xy + y 2 are quadratic polynomials.
Note that the degree of a non-zero constant polynomial is taken as zero.
When all the coefficients of variable(s) in the terms of a polynomial are zeros, the polynomial is called a zero polynomial. The degree of a zero polynomial is not defined.
We can evaluate a polynomial for given value of the variable occuring in it. Let us understand the steps involved in evaluation of the polynomial 3x 2 – x + 2 for x = 2. Note that we restrict ourselves to polynomials in one variable.
Step 1: Substitute given value(s) in place of the variable(s).
Here, when x = 2, we get 3 × (2)^2 – 2 +
Step 2: Simplify the numerical expression obtained in Step 1.
3 × (2)^2 –2 + 2 = 3 × 4 = 12
Therefore, when x = 2, we get 3x 2 – x + 2 = 12 Let us consider another example.
Example 3.6: Evaluate
(i) 1 – x^5 + 2x 6 + 7 x for x = 2
(ii) 5x 3 + 3x 2 – 4x – 4 for x = 1
Solution: (i) For x = 2
, the value of the given polynomial is:
5 6 ⎟ +^ × ⎠
Algebraic Expressions and Polynomials
Notes
Algebra
, 9x, – 25x^3 , 2.
(i) 5x 6 y^4 + 1 (ii) 10^5 + xy^3 (iii) x^2 + y^2 (iv) x 2 y + xy^2 – 3xy + 4
(i) x^2 – 25 for x = 5 (ii) x^2 + 3x – 5 for x = –
(iii) 5
x + x − for x = – 1 (iv) 2x^3 – 3x 2 – 3x + 12 for x = – 2
You are now familiar that polynomials may consist of like and unlike terms. In adding polynomials, we add their like terms together. Similarly, in subtracting a polynomial from another polynomial, we subtract a term from a like term. The question, now, arises ‘how do we add or subtract like terms?’ Let us take an example.
Suppose we want to add like terms 2x and 3x. The procedure, that we follow in arithmetic, we follow in algebra too. You know that
5 × 6 + 5 × 7 = 5 × (6 + 7) 6 × 5 + 7 × 5 = (6 + 7) × 5
Therefore, 2x + 3x = 2 × x + 3 × x
= (2 + 3) × x = 5 × x = 5x
Similarly, 2xy + 4 xy = (2 + 4) xy = 6xy
3x 2 y + 8x^2 y = (3 + 8)x 2 y = 11x 2 y
In the same way, since
7 × 5 – 6 × 5 = (7 – 6) × 5 = 1 × 5 ∴ 5y – 2y = (5 – 2) × y = 3y
and 9x 2 y^2 – 5x 2 y^2 = (9 – 5)x 2 y^2 = 4x 2 y^2
Algebraic Expressions and Polynomials
Notes
Algebra
In view of the above, we conclude:
1. The sum of two (or more) like terms is a like term whose numerical coefficient is _the sum of the numerical coefficients of the like terms.
Therefore, to add two or more polynomials, we take the following steps:
Step 1: Group the like terms of the given polynomials together.
Step 2: Add the like terms together to get the sum of the given polynomials.
Example 3.8: Add – 3x + 4 and 2x 2 – 7x – 2
Solution: (–3x + 4) + (2x 2 – 7x – 2) = 2x^2 + (–3x –7x) + (4 – 2) = 2x^2 + (–3 – 7)x + 2 = 2x^2 + (–10)x + 2 = 2x^2 – 10x + 2 ∴ (–3x + 4) + (2x^2 – 7x – 2) = 2x 2 – 10x + 2 Polynomials can be added more conveniently if (i) the given polynomials are so arranged that their like terms are in one column, and (ii) the coefficients of each column (i.e. of the group of like terms) are added Thus, Example 3.8 can also be solved as follows:
–3x + 4 2x 2 –7x – 2 2x 2 + (–7 –3)x + (4– 2) ∴ (–3x + 4) + (2x^2 – 7x – 2) = 2x 2 – 10x + 2
Example 3.9: Add 4
and 2x y 4
5x +3y− − + +
Solution: 4
5x + 3y−
−2x + y+
3x 4y
= 3x + 4y + 1
Algebraic Expressions and Polynomials
Notes
Algebra
4x 3x 7
9x 2 3x^2 = 21
13 x^2 − 6 x −
Example 3.12: Subtract 3x – 5x^2 + 7 + 3x 3 from 2x 2 –5 + 11x – x^3.
Solution: – x 3 + 2x^2 + 11x – 5
3x 3 – 5x^2 + 3x + 7
(–1–3)x^3 + (2 + 5)x 2 + (11 – 3)x + (–5 – 7)
= – 4x 3 + 7x^2 + 8x – 12
∴ (2x^2 –5 + 11x – x^3 ) – (3x – 5x 2 + 7 + 3x 3 ) = – 4x 3 + 7x 2 + 8x – 12
Example 3.13: Subtract 12xy – 5y^2 – 9x 2 from 15xy + 6y 2 + 7x 2.
Solution: 15xy + 6y 2 + 7x 2
12xy – 5y 2 – 9x^2
3xy + 11y 2 + 16x 2
Thus, (15xy + 6y^2 + 7x^2 ) – (12xy – 5y^2 – 9x 2 ) = 3xy + 11y^2 + 16x 2
We can also directly subtract without arranging expressions in columns as follows:
(15xy + 6y^2 + 7x 2 ) – (12xy – 5y 2 – 9x^2 )
= 15xy + 6y 2 + 7x^2 – 12xy + 5y^2 + 9x 2
= 3xy + 11y^2 + 16x^2 In the same manner, we can add more than two polynomials. Example 3.14: Add polynomials 3x + 4y – 5x 2 , 5y + 9x and 4x – 17y – 5x 2. Solution: 3x + 4y – 5x 2 9x + 5y 4x – 17y – 5x^2
16x – 8y – 10x^2
∴ (3x + 4y – 5x^2 ) + (5y + 9x) + (4x – 17y – 5x^2 ) = 16x – 8y – 10x^2
Example 3.15: Subtract x^2 – x – 1 from the sum of 3x^2 – 8x + 11, – 2x^2 + 12x and
Algebraic Expressions and Polynomials
Notes
Algebra
Solution: Firstly we find the sum of 3x^2 – 8x + 11, – 2x^2 + 12x and – 4x^2 + 17.
3x 2 – 8x + 11
Now, we subtract x^2 – x – 1 from this sum.
Hence, the required result is – 4x 2 + 5x + 29.
(i) x^5 4
x 7
x x 1; 3
(ii) x x 1; 2x x–^3 5
(iii) y 3
7x 2 −3x+4y; 3x^3 +5x^2 −4x+
(iv) 2x 3 + 7x 2 y – 5xy + 7; – 2x 2 y + 7x^3 – 3xy – 7
(i) x 2 – 3x + 5, 5 + 7x – 3x 2 and x 2 + 7
(ii) x and x x 8
x 5 3
x 5, 8
x 3
(iii) a^2 – b 2 + ab, b^2 – c 2 + bc and c 2 – a 2 + ca (iv) 2a^2 + 3b^2 , 5a^2 – 2b^2 + ab and – 6a^2 – 5ab + b^2
(i) 7x 3 – 3x 2 + 2 from x^2 – 5x + 2 (ii) 3y – 5y^2 + 7 + 3y 3 from 2y^2 – 5 + 11y – y^3
Algebraic Expressions and Polynomials
Notes
Algebra
Example 3.17: Multiply 2x – 3 + x 2 by 1 – x.
Solution: Arranging polynomials in decreasing powers of x, we get
(x 2 + 2x – 3) × (– x + 1) = x^2 × (–x) + x^2 × (1) + 2x × (–x) + 2x × 1 – 3 × (–x)
Alternative method:
x^2 + 2x – 3 one polynomial
To divide a monomial by another monomial, we find the quotient of numerical coefficients and variable(s) separately using laws of exponents and then multiply these quotients. For example,
(i) y
y x
x x y
x y x y x y
3 2
3 2
3 3 3 3 2 5
= 5 × x 1 × y 2 = 5xy 2
(ii) x
x 1
a 4
4x
12ax 12ax 4x
2 2 −^2 ÷ =− =− × ×
= – 3ax To divide a polynomial by a monomial, we divide each term of the polynomial by the monomial. For example,
(i) (^ )^ x
x x
x x
x x x x x 3
3 2 (^3) − (^2) + ÷ = − +
= 5x^2 – x + 6
(ii) (^ )^ (^ )^ 2x
10x 2x
8x 8x 10x 2x
2 2 −
x 2
x
x 2
= 4x – 5
Algebraic Expressions and Polynomials
Notes
Algebra
The process of division of a polynomial by another polynomial is done on similar lines as in arithmetic. Try to recall the process when you divided 20 by 3.
Divisor
3 20 Dividend 18 2 Remainder The steps involved in the process of division of a polynomial by another polynomial are explained below with the help of an example. Let us divide 2x^2 + 5x + 3 by 2x + 3.
Step 1: Arrange the terms of both the polynomials in decreasing powers of the variable common to both the polynomials. Step 2: Divide the first term of the dividend by the first term of the divisor to obtain the first term of the quotient. Step 3: Multiply all the terms of the divisor by the first term of the quotient and subtract the result from the dividend, to obtain a remainder (as next dividend) Step 4: Divide the first term of the resulting dividend by the first term of the divisor and write the result as the second term of the quotient. Step 5: Multiply all the terms of the divisor by the second term of the quotient and subtract the result from the resulting dividend of Step 4. Step 6: Repeat the process of Steps 4 and 5, till you get either the remainder zero or a polynomial having the highest exponent of the variable lower than that of the divisor. In the above example, we got the quotient x + 1 and remainder 0. Let us now consider some more examples. Example 3.18 : Divide x 3 – 1 by x – 1.
Solution:
2 3
x x x x x^3 – x 2
2 x + 32 x^2 + 5 x + 3
x 2 x + 32 x^2 + 5 x + 3
Quotient
x x x x 2x 2 + 3x
x 2 x + 32 x^2 + 5 x + 3 2x 2 + 3x
Algebraic Expressions and Polynomials
Notes
Algebra
a 0 + a 1 x + a 2 x^2 + ....+ a (^) nxn^ (or written in reverse order) where a 0 , a 1 , a 2 , .... an are real numbers and n, n–1, n–2, ...., 3, 2, 1 are whole numbers.
Algebraic Expressions and Polynomials
Notes
Algebra
(i) The coefficient of x^4 in 6x^4 y^2 is
(A) 6 (B) y^2 (C) 6y 2 (D) 4 (ii) Numerical coefficient of the monomial –x^2 y^4 is (A) 2 (B) 6 (C) 1 (D) – (iii) Which of the following algebraic expressions is a polynomial?
(A) x^8 3.7x 2
2x
2x + −
(C) (^) ( x 2 − 2y^2 ) ÷(x 2 +y^2 ) (D) (^6) + x−x−15x^2
(v) Which of the following expressions is a binomial? (A) 2x^2 y^2 (B) x^2 + y 2 – 2xy (C) 2 + x^2 + y^2 + 2x^2 y^2 (D) 1 – 3xy^3 (vi) Which of the following pairs of terms is a pair of like terms? (A) 2a, 2b (B) 2xy^3 , 2x^3 y
(C) 3x^2 y, yx^2 2
(D) 8, 16 a
(vii)A zero of the polynomial x^2 – 2x – 15 is (A) x = – 5 (B) x = – 3