Ap calculus questions, Exercises of Mathematics

unit 3 ap calculus ab excersises

Typology: Exercises

2022/2023

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AP
Calculus
,?"'\
SHOW
ALL
WORK
Ill
Find dy/dx as a function
of
x.
1)
y=(-2x+l0)
3
'f'-:.
l3l(-2')(t(0)1.
(-).,
'/-:.
_ b
(-1.l)(tlO)'
Chain
Rule
WS
Find the derivative
of
the
function.
"t
3)
:l1£
{'-('t-)
!.
{)
~
-'t,
: , (
{5
f
:fl
r2.
r I
5-
cJ
,
1•
\
~':
i (
/5,-~1r;:-
[
15-~o)
Name
511\wi.w....J
Bloc
k:
Finddy/dt.
6)
y=t5(t
4+8)5
y'
.Q
1
(r'tg)5,
(~(t
'tstf ) (t
')
.
£i-t
10)
(xLsr5
y':.
-5(xt..sf\f,x-f}
y''=
(y!_
b)-('=tr-~t
({r1]
(-/~sr\-t~
-i)
t .
--b(1Ls}.
if¾
ll)
y=
3
x5
(
4x
-6
)2
N1-6)(2fx
5)
' ;
V
'::
{4x-6f(l5,x'f}1
(3?<
5
) ·
J('f,:-6)(qT7
y
,,
:
(1x-6r
(
/20,x)}-t
l
/5'X'f)-
2(~ix
-
b)
(
4)
+ (
~x-b
)
(
n,Ory<1)
-t
(21./xs/
('i)
pf2

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AP Calculus

,?"'\ SHOW ALL WORK Ill

Find dy/dx as a function of x.

  1. y=(-2x+l0) 3

'f'-:. l3l(-2')(t(0)1. (-).,

'/-:. _ b (-1.l)(tlO)'

Chain Rule WS

Find the derivative of the function. "t

  1. :l1£ {'-('t-) !.

{)~ -'t, : , ({5 f :fl r2. r I 5- cJ , 1•
~': i ( /5,-~1r;:- [ 15-~o)

Name 511\wi.w....J

Bloc k:

Finddy/dt.

  1. y=t5(t^4 +8)^5

y' .Q 1 (r'tg)5, (~(t 'tstf ) (t ')

. £i-t

  1. (xLsr5 y':. -5(xt..sf\f,x-f}

y''= (y! b)-('=tr-~t ({r1] (-/~sr-t~ -i)_

t. --b(1Ls}. if¾

ll) y= 3 x5 (4x -6 )2 N1-6)(2fx 5 ) ' ;

V ':: {4x-6f(l5,x'f}1 (3?< 5 ) · J('f,:-6)(qT

y ,, : (1x-6r ( /20,x)}-t l/5'X'f)- 2(~ix-b) (4) + (~x-b )

( n,Ory<1) -t (21./xs/ ('i)

Suppose that the functions f and g and their derivatives with respect to x have the following values at the given values of x. Find the derivative with respect to x of the

given combination at the given value of x.

x f(x) (x) { (x) ' (x)

  1. 3 1 16 6 7 4 -3 3 5 -

f(g{x)), X = 4-

f !~I~)}· ~'fa)

:r'(,) '-b

.,__ b. - h

: -~b x f(x) (x) { (x) (x)

  1. 3 1 9 8 5 4 -3 3 5 -

~ , x= 3 [rjlx)}

1

{ (~rx) ri (~I [x))

- ½( 9 f½ f')

  • ;

x f(x) (x) { (x) (x)

  1. 3 1 16 6 5 4 3 3 5 -

x=3 i (fM-t~/11)) (f(~ (,'~\

i (1,16J{6,t5)

: 3.(11)111)

  • l~t

Solve the problem.

  1. The position of a particle moving along.a coordinate line is s=~ withs in -- meters and tin seconds. Find the particle's velocity at t = 1 sec. s : (q t\1-t)
    II: ½:l'Hl'l)(11.) 6('/fllt)

I

)h, v-il')

  1. The position of a particle moving along a coordinate line is s =~with s in meters and t in seconds. Find the particle's .i.

acceleration att:;c 11 sec. S : 'o tb{) 2.

II'- t{3-lb{J•(b) = -

">: - ½.(3tbdt6Jl:i,} -:.{?>+bt)-q)

,._(f}:,~ \

-rtr~ :_ 2+

Find a and b so that f is continuous at every point.

J§2..

x^2 , x<- f(x)= ax+b,-5:!:ix:!:i - x+6, x>-

- -----2.^ Find^ th^ e^ limi^ t.

x f(x ) {x) ( (x) (x)

  1. 3 1 4 6 7 4 -3 3 5 - I

g(x +f(x)), x = 3 ~, { i+ f (x}) {~-tf !1)

:~ '{ 3t l) (l +b )

" -5 • l-

2

  1. Jim -^ 14x2-^ 3x^ +1^7 x-+-"' -6x^2 +Bx + 13