Aqueous Solution, Lecture Notes - Chemistry, Study notes of Chemistry

Acid-Base Solubility Equilibrium Ionic Bond Acid Base theories pH values equilibrium constant common ion effect solubility cuprite

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2010/2011

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Geochemistry
DM Sherman, University of Bristol
2010/2011
Aqueous Solutions
Acid-Base and Solubility Equilibria!
Geochemistry, DM Sherman
University of Bristol
The Water Molecule!
The O-H bond is “polar covalent”; from the difference
in electronegativity, the OH bond is 39 % ionic. This
gives the water molecule a large dipole moment.
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DM Sherman, University of Bristol

Aqueous Solutions

Acid-Base and Solubility Equilibria

Geochemistry, DM Sherman University of Bristol

The Water Molecule

The O-H bond is “polar covalent”; from the difference in electronegativity, the OH bond is 39 % ionic. This gives the water molecule a large dipole moment.

DM Sherman, University of Bristol

Hydrogen Bonding

Water molecules are attracted to each other via the hydrogen bond (dipole-dipole interaction): Because of the hydrogen bond, water has a much higher boiling point than that for molecules of similar mass (e.g., CH 4 ).

Ion Hydration

The dipole moment of the water molecule means that water molecules will be attracted to ions in solution. This is why ionic compounds will dissolve in water.

+ -^

DM Sherman, University of Bristol

Acid -Base Theories (Cont.)

The Lewis acid-base theory gives a more generalized picture: CO 2 + H 2 O = HCO 3 -^ + H+ The generalized acid-base reaction can be viewed as Acid + Base → Weaker Acid + Weaker Base Acid Base Base Acid Fe3+^ + H 2 O = Fe(OH)2+^ + H+

Acids and Bases Aqueous Systems

In aqueous systems, all acids stronger that H 2 O generate excess H+^ ions (or H 3 O+); all bases stronger than H 2 O generate excess OH-: ( or, Fe3+^ + H 2 O → Fe(OH)2+^ + H+^ ) ii) CO 3 2-^ + H 2 O → HCO 3 -^ + OH- i) Fe(H 2 O) 6 3+^ + H 2 O → Fe(H 2 O) 5 (OH)2+^ + H 3 O+ Hence, in aqueous solutions, the Lewis acid-base picture becomes the Bronsted acid-base picture.

DM Sherman, University of Bristol

Acid-Base Properties of Minerals

Most minerals are salts of weak acids and strong bases. Such minerals react with water to raise the pH: 2KAlSi 3 O 8 + 2H 2 O = Al 2 Si 2 O 5 (OH) 4 + 2K+^ + 2OH- 2Mg 2 SiO 4 + 3H 2 O = Mg 3 Si 2 O 5 (OH) 4 + Mg2+^ + 2OH- CaCO 3 + H 2 O = HCO 3 -^ + Ca2+^ + OH- A few minerals are salts of weak bases and strong acids. Such minerals react with water to lower the pH: KFe 3 (SO 4 ) 2 (OH) 6 + 3H 2 O = K+^ + 3Fe(OH) 3 + 2SO 4 2-^ + 3 H+

Aqueous Systems

Hence, regardless of the nature of the acid or base:

  • The acidity of the aqueous solution is given by the H+ concentration.
  • The basicity is given by the OH- concentration. Note: The alkalinity of an aqueous solution is given by 2[CO 3 2-] + [HCO 3 - ] + [OH-] -[H+]. This is a measure of the titratable basicity.

DM Sherman, University of Bristol

Speciation of H 2 CO 3

pH and Proton

Free Energy

The “proton ladder” gives a useful picture of the relative strengths of acids and bases in aqueous solutions.

DM Sherman, University of Bristol

Ion-Ion Interactions and Activities

In very dilute aqueous solutions, the ions do not interact with each other. Moreover, the presence of the ions has no effect on the bulk structure of water. We will take this as the standard state for ions in aqueous solution: a 1 molal solution with the properties of infinite dilution. In dilute solutions: Activity = concentration

Ion-Ion Interactions

With increasing concentration, ions start to interact with each other. The chemical potential of an ion will depend upon the concentration of the other ions. Ion-ion interactions may be specific (e.g., ion- pairs or complexes ) or non-specific (long-range coulombic interactions).

DM Sherman, University of Bristol

Saturation, Unsaturation and

Supersaturation

  • A solution will be saturated in a solid CaSO 4 if that solid is present. The ion product Q = [Ca][SO 4 ] = K.
  • A solution will be unsaturated if solid CaSO 4 is absent and Q = [Ca][SO 4 ] < K
  • A solution will be supersaturated if CaSO 4 is absent and Q = [Ca][SO 4 ] > K.
  • The saturation index = log(Q/K) = pK- pQ Consider the dissolution of CaSO 4 = Ca2+^ + SO 4 -2^ :

Common Ion Effect

CaSO 4 (s) = Ca+2^ + SO 4 - PbSO 4 (s) = Pb+2^ + SO 4 - = 6.3 x 10- = 2.0 x 10-

DM Sherman, University of Bristol

Common Ion Effect

Because of charge balance , we have [Ca] + [Pb] = [SO 4 ]. But since CaSO 4 is much more soluble PbSO 4 , [Ca] >> [Pb] or [Ca] + [Pb] [Ca]. Hence [Ca] [SO 4 ] Since KCaSO4 = [Ca][SO 4 ] = 6.3 x 10- we get [SO 4 ] = 7.9 x 10-

Common Ion Effect (cont.)

Since KPbSO4 =[Pb][SO 4 ] = 2.0 x 10- we get [Pb] = 2.5 x 10- If CaSO 4 was absent then [Pb] = [SO 4 ] So that, [Pb] = 1.4 x 10-

DM Sherman, University of Bristol

Solubility of Cuprite Cu 2 O (cont.)

Cl complexation changes the solubility of Cu 2 O by 8 orders of magnitude.

Solubility of FeOOH

In addition to the simple solubility equilibrium: Fe3+^ + H 2 O = FeOH+2^ + H+^ pK = 2. Fe3+^ + 2H 2 O = Fe(OH) 2 +^ + 2H+^ pK = 5. Fe3+^ + 3H 2 O = Fe(OH) 30 + 3H+^ pK = 12. Fe3+^ + 4H 2 O = Fe(OH) 4 -^ + 4H+^ pK = 21. FeOOH + 3H+^ = Fe+3^ + 2H 2 O pK = -0. We also need to account for the hydrolysis of Fe3+:

DM Sherman, University of Bristol

Solubility of FeOOH (cont.)

By taking the “p-function” (i.e., -log) of the equilibrium expressions, we get: p[FeOH+2] = pK 2 - pH + p[Fe+3] = 1.66 + 2pH (2) p[Fe+3] = pK 1 + 3pH = -0.53 + 3pH (1) p[Fe(OH) 2 +] = pK 3 - 2pH + p[Fe+3] = 5.14 + pH (3) p[Fe(OH) 3 ] = pK 4 - 3pH + p[Fe+3] = 12.03 (4) p[Fe(OH) 4 - ] = pK 5 - 4pH + p[Fe+3] = 21.1 - pH (5) Plotting the p[Fe(OH)n] (equations 1-5) gives a map of the saturation field of FeOOH and the dominant aqueous Fe complexes at each pH.

Solubility of FeOOH

(cont.)

Notice that [Fe]tot reaches a minimum at the pH of seawater. 1 2 3 4 5