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Exercise 4.3 a, c-f and empirical exercise 4.1
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a) 710.7 is the intercept and 8.8 is the slope. 8.8 shows the marginal effect of average monthly income (AMI) on average monthly expenditures (AME). AME is expected to increase by 8.8 for every unit increase in AMI. b) — c) R^2 =0,03. This indicates that the regressor is not very good at predicting Y. R^2 is a fraction between 0 and 1 and has no units. R^2 → is unit free d) AME = 710.7 + 8.8 * AMI Person with income €100: AME=710.7+8.8100 = € 1590.7. A person with income 100 will have an AME of 1590.7. Person with income €200: AME=710.7+8.8200= €2470.7. person with income 200 will have an AME of 2470. e) No it would not since the sample goes from 100 to 1.5 million. 2 million is outside our range for sample data. f) Distribution of earrings is usually highly skewed. We have statistical models for income distribution. In regression analysis usually the distribution of independent variable is not considered. Normality of errors is only needed for testing of hypothesis for regression coefficient and coefficient interval construction. So we can se that error term has a normal distribution.
a) Here we have a scatterplot of average annual growth rate on the y-axis and tradeshere on the x-axis. We can se a positive relationship between the variables. b) We can see Malta in the upper right corner. Malta do look like an outlier. c) Growth=β 0 +β 1 trade share β 0 =0,64 (_cons) β 1 =2.3(tradeshare) Growth(tradeshare=0,5)=0,64+2,300,5=1, Growth(tradeshare=1)=0,64+2,30*1=2,