Assignment 1 - Power System Stability II | ECE 504, Assignments of Electrical and Electronics Engineering

Material Type: Assignment; Class: ST:Control Systems and Critical Infrastructures; Subject: Electrical & Computer Engr; University: University of Idaho; Term: Spring 2005;

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ECE 504 Special Topics Power System Stability II HW #1
r2i2
v2
+rm
i1i2
+
()
=r1i1
v1
+rm
i1i2
+
()
=
r2i2
v2
+vm
=vmrm
i1i2
+
()
=r1i1
v1
+vm
=
i2
vmv2
r2
=i1
vmv1
r1
=
C1
0
0
C2
dv1
dt
dv2
dt
i1
i2
=
C2
dv2
dt
i2
=C1
dv1
dt
i1
=
III. Generate the Needed Equations
Determine v1 and v2 as a function of time using eigenanalysis.
II.Goals
v0220:=v0110:=
r1
i1
+
v1
-
+
v2
-
rm
r2
i2
+
vm
-
C1C2
rm7.0:=r217.8:=r111.2:=C22:=C13:=
The parameters for the following circuit are:
I. Define the Situation ORIGIN 1:=
C:\JLAW\CLASSES\S05PSSII
\hw01.mcd page 1 of 5 January 24, 2005
pf3
pf4
pf5

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r 2

i 2

⋅ v 2

  • r m

− i 1

i 2

r = ⋅ 1

i 1

⋅ v 1

  • r m

− i 1

i 2

r 2

i 2

⋅ v 2

  • v m

v = m

r m

− i 1

i 2

r = ⋅ 1

i 1

⋅ v 1

  • v m

i 2

v m

v 2

r 2

i = 1

v m

v 1

r 1

C

C

dv 1

dt

dv 2

dt

i 1

i 2

C

dv 2

dt

⋅ i 2

C =

dv 1

dt

⋅ i 1

III. Generate the Needed Equations

Determine v 1

and v 2

as a function of time using eigenanalysis.

II.Goals

v 2

v0 := 20 1

r

1

i

1

v

1

v

2

r

m

r

2

i

+^2

v

m

C

1

C

2

r m

r :=7. 2

r :=17. 1

C :=11.

C := 2

The parameters for the following circuit are:

I. Define the Situation

ORIGIN := 1

C:\JLAW\CLASSES\S05PSSII page 1 of 5 January 24, 2005

r 1

r m

i 1

⋅ r m

i 2

  • ⋅ v 1

= − r m

i 1

⋅ r 2

r m

i 2

  • ⋅ v 2

r 1

r m

r m

r m

r 2

r m

i 1

i 2

v 1

v 2

F

r 1

r m

r m

r m

r 2

r m

:= F

F

i 1

i 2

v 1

v 2

i 1

i 2

F

1 −

v 1

v 2

C

C

dv 1

dt

dv 2

dt

⋅ F

− 1 −

v 1

v 2

C

C

C

:= C

C

dv 1

dt

dv 2

dt

⋅ F

− 1 −

v 1

v 2

dv 1

dt

dv 2

dt

C

− 1 − F

− 1 ⋅

v 1

v 2

C:\JLAW\CLASSES\S05PSSII page 2 of 5 January 24, 2005

0 50 100 150 200 250 300 350

0

5

10

15

20

25

z 1

( )t

z 2

( )t

t

z 2

( )t z 2

e

λ 2

⋅t

z := ⋅ 1

( )t z 1

e

λ 1

⋅t

λ 1

z

z0 ψ =

v 1

v 2

dz

dt

= Λ ⋅z

Λ φ =

− 1

:= A ⋅φ

V. Transform to an Orthogonal Space

ψ 2

ψ =( −0.742 0.7) 2

ψ

T

2

T

Left Eigenvector

Associated with (^) λ 1

ψ 1

ψ =( 0.833 0.588) 1

ψ

T

1

T

Left Eigenvector

Associated with (^) λ 1

The program nomalizes the right eigenvectors such that the product of

the left and right eigenvectors associated with the same eigenvalue is

one.

ψ φ⋅

C:\JLAW\CLASSES\S05PSSII page 4 of 5 January 24, 2005

VI. Solution

d 11

φ 1 1, ψ 1 1, ⋅ v 1

⋅ φ 1 1, ψ 1 2, ⋅ v 2

:= + ⋅ d 11

d 12

φ 1 2, ψ 2 1, ⋅ v 1

⋅ φ 1 2, ψ 2 2, ⋅ v 2

:= + ⋅ d 12

d 21

φ 2 1, ψ 1 1, ⋅ v 1

⋅ φ 2 1, ψ 1 2, ⋅ v 2

:= + ⋅ d 21

d 22

φ 2 2, ψ 2 1, ⋅ v 1

⋅ φ 2 2, ψ 2 2, ⋅ v 2

:= + ⋅ d 22

x 1

( )t d 11

e

λ 1

⋅t

⋅ d 12

e

λ 2

⋅t

:= + ⋅ x 2

( )t d 21

e

λ 1

⋅t

⋅ d 22

e

λ 2

⋅t

x 1

x 2

0 50 100 150 200 250 300 350

0

5

10

15

20

x 1

( )t

x 2

( )t

t

C:\JLAW\CLASSES\S05PSSII page 5 of 5 January 24, 2005