Homework Solutions for Chapter 7: Hypothesis Testing - Prof. Spencer Muse, Assignments of Data Analysis & Statistical Methods

Solutions to homework problems in chapter 7 of a statistics textbook, focusing on hypothesis testing. Topics covered include testing for normal distribution, one-sided and two-sided alternatives, confidence intervals, and the significance of p-values. The document also discusses the importance of large sample sizes and independent groups.

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Uploaded on 03/18/2009

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ST301
Homework11Solutions
CH7
53.)(a)Thedatacan’tbenormallydistributedbecausethereareonly7possiblevalues(06),all
integers.ThisdataactuallyhasaBinomialdistribution.
(b)Wehavetwolargesamples(n1=165andn2=212),sothesamplemeanswillhavenormal
distributions.Sothemethodsofthischapterareapplicable.
(c)H0:µINTERVENTION=µCONTROL
HA:µINTERVENTION≠µCONTROL(twosided)
HA:µINTERVENTION>µCONTROL(onesided)
Theonesidedalternativewouldreflecttheresearcher’sbeliefthattheinterventiongroupshouldhavea
highermeanscore.Thetwosidedalternativeallowsforthepossibilitythattheinterventiongrouphasa
lowerscorethanthecontrol.
(d)


 ..
.
 .
 6.258
.

df=354(software)or164(approx).Eitherway,p<0.0001.
Withsuchasmallpvalue,RejectH0.Concludethatthereisasignificantdifferenceinmeanscore
betweentheinterventiongroupandthecontrolgroup.Sincethedatashowthattheinterventionscore
washigher,wecanconcludefurtherthattheinterventionincreasesmeanscoreovercontrol.
(e)95%CI:(xbar1xbar2)±t*SEDIFF=(5.084.33)±t*(.
 )
t*dependsonthedfused,buttheintervalisabout(0.51,0.99).Thismeansweare95%confidentthat
themeanscorefortheinterventiongroupisbetween0.51and0.99pointshigherthanforthecontrol
group.
(f)Theresultsarenotgeneralizabletootherpopulations.
55.)n1=115,xbar1=18.0,s1=7.8
n2=220,xbar2=6.5,s2=3.4
(a)Ifthiscompany’sworkingconditionsaresimilarenoughtoothers’,thismaybeagoodenough
randomsample.
(b)Youmayusedf=137.1(software)or114(approximation)or100(closestvalueintableD).
pf2

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