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Material Type: Assignment; Class: Mathematical Modeling; Subject: Mathematics; University: University of California - Los Angeles; Term: Unknown 1989;
Typology: Assignments
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Math 142 Homework #
Answer:
Answer: The growth is governed by
dN dt =^ R(N^ )N
Equilibrium occurs when the time derivative is zero. This can happen when N = 0 and when R = 0. Since R is zero at two non-zero N values, there are three equilibrium positions. At N = N 1 , the growth rate is negative, and the population returns to zero. So N = 0 is stable. At the left most root of R(N ), the growth rate is positive for values slightly larger than Neq. This is unstable. Finally, at the other root of R(N ), the growth rate is negative to the right, and positive to the left. This is stable.
Sketch the phase plane solutions of the following systems
a. dx dt
= x + y dy dt =^ x Answer: The phase plane equation is dy dx =^
x x + y This gives a zero isocline at x = 0 and an infinity isocline at y = โx. When x = 0, dx dydt^ =^ y^ which means that^ x^ is increasing when^ y^ is positive, and vice versa. When^ y^ =^ โx, dt =^ โy^ which means^ y^ is decreasing when^ y^ is positive.
Straight-line trajectories are given by
m = x x + mx m = 1 1 + m m + m^2 โ 1 = 0 m = โ^1 2
m โ 0. 62 , โ 1. 62
x
y
b.
dx dt =^2 x^ +^ y dy dt
= โx + y
Answer: The phase plane equation is
dy dx
= โx^ +^ y 2 x + y
This gives a zero isocline at y = x and an infinity isocline at y = โ 2 x. When y = x, dx dt = 3x^ which means that^ x^ is increasing when^ x^ is positive, and vice versa.^ When y = โ 2 x, dydt = โ 3 x which means y is decreasing when x is positive.