CS 417/517 Assignment 8: Computational Methods and Software - Spring 2004, Assignments of Computer Science

Assignment 8 for the cs 417/517 computational methods and software course offered in spring 2004. The assignment covers topics such as eigenvalues, eigenvectors, and similarity of matrices. Students are required to answer true or false questions and perform matrix calculations.

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CS 417/517 Computational Methods and Software
Spring 2004
Assignment 8
Assigned: Thurs April 8, 2004; Due: Thurs April 15, 2004
1. True or false? Give a reason for your answer to receive any credit.
(a) False, because eigenvalues are the roots of the charactarstic polynomial.
(b) False, n×nmatrix has nlinearly independent eigenvectors if it is not defective.
(c) True, If a square matrix is singular, then one of its eigenvalues is
equal to 0.
(d) False, If two matrices are similar, then they have the same eigenvalues.
(e) False, If two matrices A, B have same eigenvalues, and there exist a nonsingular matrix
Tsuch that B=T1AT then they are similar.
2. The same eigenvalue correspond to two distinct eigenvectors, but
the same eigenvector can not correspond to two distinct eigenvalues.
3. (a) Hv = (I2vTv)v
Hv =v2vTvv =v.
(b) Hx = (I2vTv)x
Hx =x2vTxv =x.
4. Yes, because λ3= 0
5. (a) λ22λ3
(b) λ22λ3 = 0
λ1= 3 and λ2=1
(c) λ1= 3 and λ2=1
(d) eigenvectors of the matrix
v1= 2
1!, v2= 2
1!.
(e)
1 4
1 1 ! 1
1!= 5
2!.
5/29
2/29 !
(f) Power iteration converge to the dominant eigenvalue.

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CS 417/517 Computational Methods and Software

Spring 2004 Assignment 8 Assigned: Thurs April 8, 2004; Due: Thurs April 15, 2004

  1. True or false? Give a reason for your answer to receive any credit.

(a) False, because eigenvalues are the roots of the charactarstic polynomial. (b) False, n × n matrix has n linearly independent eigenvectors if it is not defective. (c) True, If a square matrix is singular, then one of its eigenvalues is equal to 0. (d) False, If two matrices are similar, then they have the same eigenvalues. (e) False, If two matrices A, B have same eigenvalues, and there exist a nonsingular matrix T such that B = T −^1 AT then they are similar.

  1. The same eigenvalue correspond to two distinct eigenvectors, but

the same eigenvector can not correspond to two distinct eigenvalues.

  1. (a) Hv = (I − 2 vT^ v)v

Hv = v − 2 vT^ vv = −v. (b) Hx = (I − 2 vT^ v)x Hx = x − 2 vT^ xv = x.

  1. Yes, because λ 3 = 0
  2. (a) λ^2 − 2 λ − 3

(b) λ^2 − 2 λ − 3 = 0 λ 1 = 3 and λ 2 = − 1 (c) λ 1 = 3 and λ 2 = − 1 (d) eigenvectors of the matrix

v 1 =

( 2 1

) , v 2 =

( − 2 1

) .

(e) ( 1 4 1 1

) ( 1 1

)

( 5 2

) .

( 5 /

)

(f) Power iteration converge to the dominant eigenvalue.