Trigonometric Functions: Evaluating Angles in Quadrant II, Assignments of Trigonometry

The definitions and instructions for evaluating the six trigonometric functions (sin, cos, tan, cot, sec, and csc) for an angle θ in standard position with given x and y coordinates. The example problem determines the quadrant of θ based on sin θ and sec θ values.

Typology: Assignments

Pre 2010

Uploaded on 07/30/2009

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Evaluating Trigonometric Functions
If we have any angle, θ, in standard position with a point (x, y) on the terminal side of θ
and r=px2+y2>0, then use the following definitions to evaluate the six trigonometric
functions:
sin θ=y
rcos θ=x
r
tan θ=y
x, x 6= 0 cot θ=x
y, y 6= 0
sec θ=r
x, x 6= 0 csc θ=r
y, y 6= 0
The following figure shows us the quadrants and will also help us to evaluate the
functions:
Quadrant II Quadrant I
sin θ: + sin θ: +
cos θ:cos θ: +
tan θ:tan θ: +
Quadrant III Quadrant IV
sin θ:sin θ:
cos θ:cos θ: +
tan θ: + tan θ:
Problem 4.
Give the quadrant in which θlies.
sin θ=25
5
sec θ=5
Solution Step 1:
Using the co ordinate system above, we can see that sin θ > 0 in quadrants
I and II. Since sec θ < 0 in quadrants II and III, θlies in quadrant II.

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Evaluating Trigonometric Functions

If we have any angle, θ, in standard position with a point (x, y) on the terminal side of θ

and r =

x^2 + y^2 > 0, then use the following definitions to evaluate the six trigonometric

functions:

sin θ=

y r

cos θ=

x r

tan θ=

y x

, x 6 = 0 cot θ=

x y

, y 6 = 0

sec θ=

r

x

, x 6 = 0 csc θ=

r

y

, y 6 = 0

The following figure shows us the quadrants and will also help us to evaluate the functions:

Quadrant II Quadrant I sin θ : + sin θ : + cos θ : − cos θ : + tan θ : − tan θ : +

Quadrant III Quadrant IV sin θ : − sin θ : − cos θ : − cos θ : + tan θ : + tan θ : −

Problem 4.

Give the quadrant in which θ lies.

sin θ =

sec θ = −

Solution Step 1:

Using the coordinate system above, we can see that sin θ > 0 in quadrants

I and II. Since sec θ < 0 in quadrants II and III, θ lies in quadrant II.