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Atomic Physics Worksheet. 1. Which of the gas samples shows an emission line with a wavelength between 4000 and 5000 Angstroms (400-500 nanometers): ...
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Atomic Physics Worksheet
between 4000 and 5000 Angstroms (400-500 nanometers): __________________
between 6500 and 7500 Angstroms (650-750 nanometers):__________________
(There may be more than one.)
n = ∞ (^) E = 0 eV
n = 5
n = 6 E = ñ0.54 eV
E = ñ0.38 eV
n = 4 (^) E = ñ0.85 eV
n = 3 (^) E = ñ1.51 eV
n = 2 (^) E = ñ3.40 eV
n = 1 (^) E = ñ13.6 eV
In the diagram above we have represented some allowed energy levels of the electron in a hydrogen atom. Ordinarily, the electron is in the ìground stateî ( n = 1) and has energy of ñ13.6 eV. ( eV = 1.6 × 10 ñ19^ J.) This means that you would have to add 13.6 eV of energy to the electron in order to break it away from the hydrogen atom. (If the electron just barely escaped from the atom ñ and had no energy left over to go anywhere ñ we would say that it has ìzeroî total energy, or E = 0 eV.) If an electron in the ground state ( n = 1) gains energy its energy level would rise, for instance to n = 2, n =3, or some higher value of n. The larger the value of n , the greater is the energy of the electron. The maximum possible energy for an electron in the hydrogen atom (E ≈ 0 eV) would correspond to n = ∞.
When fast-moving electrons are sent flowing through a tube of hydrogen gas, some of them collide with the hydrogen atoms and increase the energy of the electrons in the atoms. In this way, the hydrogen electrons may briefly acquire some of the higher energy levels shown in this diagram. Usually, after a brief moment, these electrons will abruptly lose at least some of their extra energy. When they do this, we say they ìdropî in energy level. In this process, they can emit one single electromagnetic photon ñ sort of a ìparticleî composed of e-m waves. The energy of the emitted photon must exactly equal the amount of energy that is lost by the electron as it changes its energy level.
When observing hydrogen gas in an electrical discharge tube (in which high-energy electrons are passed through the gas), the hydrogen glows with a colorful light. When the light is examined through a specially designed filter (a spectroscopic ìgratingî), it is possible to identify the wavelengths of the individual electromagnetic waves that make up that glowing light. These include the following wavelengths: 656.3 nm; 486.1 nm; 434.1 nm; 410.2 nm. (1 nm = 1 × 10 ñ9^ m). Letís try to identify which electronic transitions in the hydrogen atom correspond to these different e-m photons. (Here weíll need to recall that the energy of a photon of frequency f is given by E = hf; Planckís constant h has the value h = 6.63 × 10 ñ34^ J-s = 4.14 × 10 ñ15^ eV-s.)
symbol wavelength (nm)
frequency (Hz)
color photon energy (eV)
Hα 656. Hβ 486. Hγ 434. Hδ 410.
b) If not, state whether or not the e-m wave corresponding to that photon should be visible. Explain your reasoning. If yes, what color would it be?
a) How many different photons in the Lyman series could be emitted as a result of electronic transitions among the six levels represented on this diagram? (There exist many others besides these.
Questions #10-15 refer to this energy level diagram of some unknown atom. The distances between the horizontal lines are proportional to the energy differences between the levels.
n = 4
I J
G H
E F
B
C D
A
n = 3
n = 2
n = 1
Then could transition D represent:
A) emission of infrared light B) emission of ultraviolet light C) absorption of infrared light D) absorption of ultraviolet light Explain your answer:
lowest frequency _________________________________________highest frequency
smallest wavelength _________________________________________longest wavelength
Explain how you found the answer to this question.