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Jan 223:51 PM
Aim: How can a conservation of mass be shown in a
chemical equation?
Balancing Chemical Equations
Objective: Balance each chemical equation correctly so the number of atoms of each
element is the same on both sides of the reaction.
Dec 307:00 PM
Do Now
H
2
+ O
2
‡ H
2
O
H
O
H
O
2
H
2
O
H
2
H
O
H
___H
2
+ ___ O
2
‡ ___ H
2
O
H
O
H
H
O
H
Balanced version of the equation:
In terms of the atoms present, explain why the reaction belowis unbalanced.
Please take a copy of the note sheet up front and
answer the DO NOW question.
Dec 307:00 PM
Conservation of Matter
Law of conservation of matter:Matter cannot be created or
destroyed but is conserved.
- Mass, charge, and energy are conserved in chemical reactions.
- To show a conservation of mass , the number of each type of
atom on both sides of an equation MUST BE EQUAL
By placing coefficients in front of compounds/elements in a
chemical reaction we can balance the reaction.
Dec 307:00 PM
To balance an equation:
- Count the number of each type of atom on both sides.
- Balance, using coefficients,to adjust the number of atoms
for each element.
- NEVER change the subscripts in the chemical formulas.
- Always check for the lowest whole # ratio of coefficients.
(the coefficients should not be able to be reduced)
- For combustion equations, when the oxygen reactant cannot
be balanced w/ an even coefficient, double ALL other
coefficients.
a. Then recount and finish balancing the oxygen reactant.
___P + ___O 2
‡ ___ P 4
O 10
Example 1
Example #
__C 2
H 6
+__O 2 ‡ __ CO 2
+ __ H 2
O
Demonstrating
Rule 5
Dec 307:00 PM
Example #
2 C
H
O
Demonstrating
Rule
5 __C
2
H
6
+__O
2
__ CO
2
+ __ H
2
O
__C
2
H
6
+__O
2
__ CO
2
+ __ H
2
O
C
H
2 O
__C
2
H
6
+__O
2
__ CO
2
+ __ H
2
O
C
H
O
Use the double
rule for
combustion
(Rule 5) 4 4
Feb 410:24 AM
- ___ HgO ‐‐> ___ Hg + ___ O
2
- ___ Fe + ___ O
2
‐‐> ___ Fe
2
O
3
- ___ KClO
3
‐‐> ___ KCl + ___ O
2
Feb 410:24 AM
- ___ Ca(OH)
2
+ ___ H
2
SO
4
‐‐> ___ HOH + ___ CaSO
4
- ___ Cu + ___ AgNO
3
‐‐> ___ Cu(NO
3
)
2
- ___ C
4
H
8
2
‐‐> ___ CO
2
2
O
