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This file contains solution to problems related Data Communication Systems. Mr. Prajin Ahuja assigned task at Birla Institute of Technology and Science. Its main points are: Bandwidth, Utiliztaion, Multiplexing, Analog, Hierarchy, Groups, Supergroups, Optical, Synchronous, Statistical
Typology: Exercises
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c. Master group: overhead = 2520 KHz − (10 × 240 KHz) = 120 KHz. d. Jumbo Group: overhead = 16.984 MHz − (6 × 2.52 MHz) = 1.864 MHz.
a. Each output frame carries 2 bits from each source plus one extra bit for syn- chronization. Frame size = 20 × 2 + 1 = 41 bits. b. Each frame carries 2 bit from each source. Frame rate = 100,000/2 = 50, frames/s. c. Frame duration = 1 /(frame rate) = 1 /50,000 = 20 μ s. d. Data rate = (50,000 frames/s) × (41 bits/frame) = 2.05 Mbps. The output data rate here is slightly less than the one in Exercise 16. e. In each frame 40 bits out of 41 are useful. Efficiency = 40/41= 97.5%. Effi- ciency is better than the one in Exercise 16.
Figure 6.1 Solution to Exercise 23
O L E L Y I E B H H TDM