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Ionic Formula Writing
Using the cards complete the table below Ions # of atoms ( cards) used Ionic Formula Compound Name when a metal/cation is present no prefixes are added
#1 Cation (+ ion): Be^2 +^1 BeCl 2 Beryllium Chloride
Anion (- ion): Cl^1 -^ 2
#2 Cation (+ ion): K^1 +
Anion (- ion): Br^1 -
#3 Cation (+ ion): Ca^2 +
Anion (- ion): P^3 -
#4 Cation (+ ion): Al^3 +
Anion (- ion): S^2 -
The charge of the ion Electrons are donated to obey the octet rule Number of valence electrons Accepting electrons to obey octet rule
The number of cards = the number of atoms= the subscript number= BeCl 2
Beryllium loses 2 e- 1 atom of beryllium needs 2 atoms of chlorine to balance out 2 chlorine atoms are needed because each individual chlorine can only accept 1 electron and 1 Beryllium atom is giving up 2 electrons to follow the octet rule
#5) Why is a roman numeral used when naming a transition metal compound? #6) What three transition metals do not need a roman numeral? #7) What two metals need a roman numeral but are not transition metals? #8) How is the roman numeral determined? Example FeCl 3 #9) What are the nine polyatomic ions that need to be memorized? (look at the flowchart sheet and include the chemical formula with subscripts and the charge) Ions # of atoms ( cards) used Ionic Formula Compound Name when a metal/cation is present no prefixes are added
#10 Cation (+ ion): Co^3 +
Anion (- ion): Br^1 -
#11 Cation (+ ion): K^1 +
Anion (- ion): (SO 42 - )
#12 Cation (+ ion): Zn^2 +
Anion (- ion): P^3 -
#13 Cation (+ ion): Co^3 +
Anion (- ion): (NO 31 - )
#14 Cation (+ ion): Al^3 +
Anion (- ion): (PO 4
3 -
Create your own compound with a transition metal &/or polyatomic ion #15 Cation (+ ion): Anion (- ion): Using the cards complete the table below:
