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The course gives the students a sound knowledge of Fourier transforms along with Fourier integrals, partial differential equations, advanced vector analysis, complex variables and complex integrals. This lecture includes: BJT, High, Low, Frequency, Response, Analysis, Mid, band, Gain, Base, Resistance, Equivalent, Circuit, Coupling, Capacitance
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EE216 Fall 2011
2
^
Microelectronic Circuits Sixth Edition,
by Sedra, Smith Oxford University Press
^
Fundamentals of Microelectronics, by Behzad Razavi, John Wiley & Sons Inc Modified by Assistant Professor Saleem Iftekhar, SEECS NUST
RECALL: BJT High Frequency Analysis
H
'
H
'
1
1
1
ω
ω^
s A
R C
R A sC
V V A^
M
sig in
sig M in
o sig
RECALL: BJT High Frequency Analysis
ⅴ⅘
BJT Mid-band Gain with
ⅴ
⅘
L C m sig
B B
B B
M^
R R g R r R r R
r R r R
π
π
π
π
L C m sig
B
B
o sig M v^
π
π
sig
B B
B
L C m B
M
R r R r R r R R R g r R A
π
π π
π
(^
)^
(^
)
sig
sig B B
L C B
sig
B
B
L C B
M^
Rr
R R r R
R R R R r R r R
π
π
π
π
(^
)^
sig B sig B
sig B
L C B
sig B sig B
L C B
o sig M
R R R R r R R
R R R R R R R r
π
π
β
β
sig B
L C
sig B
B
M
r
β π
ⅴ⅘^
ⅴⅨ
⅙⅙❸
)
BJT Low Frequency Response (
⅙⅙❸
)
⅙⅙❸
)
BJT Low Frequency Response (
⅙⅙❸
)
ⅴ⅘^
ⅴⅨ
)
(^
L C m sig
B
B
o sig
M v^
R R g R r R
r R
V V
A G^
π
π
⅙⅙❸
)
The input side equivalent Circuit LFR (
⅙⅙❸
)
o s
s
s T
ω+
==) (
)
(
1
Where
1
1
sig
B C o P^
R r R C^
= ≡
π
ω ω
⅙⅙❸
)
BJT Low Frequency Response (
⅙⅙❸
)
)
(
1 1
1
sig
B C
P^
R r R C^
=
π
ω
ⅴ⅘
ⅴⅨ
↉↕^
∄≐
⅙Ⅱ
)
BJT Low Frequency Response (
⅙Ⅱ
)
=
β
ω
1 1
2
sig B e E
P
R R r C
⅙Ⅱ
)
BJT Low Frequency Response (
⅙Ⅱ
)
ⅴ⅘
)
(^
L C m sig
B
B
M^
R R g R r R
r R
A^
−=
π
π
[^
]^
s A R R r C s
s A
V V s A^
M P
L C o C P P M
o sig
3
2
3
3
1
1
) (
ω
ω
ω^
⅙⅙❹
)
BJT Low Frequency Response (
⅙⅙❹
)
Combined BJT Low Frequency Response ) =^ )(
3
2
1
=
=
P
P
P
M
o sig
s
s
s
s
s
s
A
V V s A
ω
ω
ω
1
1
1
(^12)
2 2
1 1
^
≈
C C E E C C
L^
R C R C R C f
π
Example 5.19 S&S 5Ed