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Lewis electron-dot structures and explanations of the bonding and molecular shapes for various fluorine and nitrogen compounds, including nf3, pf5, co2-, co2, co, cf4, xef4, and clf3. It covers topics such as resonance structures, bond lengths, and hybridization.
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(b) Which of the three species has the shortest C-O bond length? Explain the reason for your answer. (c) Predict the molecular shapes for the three species. Explain how you arrived at your predictions.
(a) Draw a Lewis electron-dot structure for each of the molecules above and identify the shape of each.
(b) Use the valence shell electron-pair repulsion (VSEPR) model to explain the geometry of each of these molecules.
(a) The compounds SF 4 and BF 3 react to form an ionic compound according to the following equation. SF 4 + BF 3 → SF 3 BF (^4) (i) Draw a complete Lewis structure for the SF 3 +^ cation in SF 3 BF 4. (ii) Identify the type of hybridization exhibited by sulfur in the SF 3 +^ cation. (iii) Identify the geometry of the SF 3 +^ cation that is consistent with the Lewis structure drawn in part (a)(i). (iv) Predict whether the F—S—F bond angle in the SF 3 +^ cation is larger than, equal to, or smaller than 109.50˚. Justify your answer.
(b) The compounds SF 4 and CsF react to form an ionic compound according to the following equation. SF 4 + CsF → CsSF 5 (i) Draw a complete Lewis structure for the SF 5 –^ anion in CsSF 5. (ii) Identify the type of hybridization exhibited by sulfur in the SF 5 –^ anion. (iii) Identify the geometry of the SF 5 –^ anion that is consistent with the Lewis structure drawn in part (b)(i). (iv) Identify the oxidation number of sulfur in the compound CsSF 5.
Answers
NF 3 PF (^5)
Your Lewis structures should show the sp 3 hybridization in NF 3 and the sp 3 d hybridization in PF 5. The reason NF 5 doesn’t exist is because N has no d orbitals available for hybridization.
-2-2 -2-2 (^) -2-
Tetrahedral Square planar T-shaped
(b) CF 4 has 4 shared, no unshared pairs. The maximum angular separation gives a tetrahedron.
XeF 4 has two unshared pairs on opposite sides of the Xe. This forces the remaining F atoms into a central plane.