Banach Spaces Lecture Notes (Michaelmas 2010) by Bernd Kirchheim, Study notes of Mathematics

These are the notes from lectures 7 and 8 of the banach spaces course given by bernd kirchheim during michaelmas term 2010. The notes cover the separability of normed vector spaces, the definition and properties of linear operators, and examples of bounded linear operators. The document also includes proofs and theorems related to these topics.

Typology: Study notes

2010/2011

Uploaded on 09/08/2011

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B4a Banach spaces Michaelmas 2010
lectured by Bernd Kirchheim based on notes by CJK Batty
Lectures 7 and 8
4. Theorem Let Xbe a normed vector space and let Sbe a countable
subset of Xsuch that span(S) = X1, then Xis separable.
5. Corollary Let Xbe a normed vector space and SX. Then
spanS= spanS.
Hence, if there exists a countable set SXsuch that spanS=X, then X
is separable.
Remark Beside telling us when a space is separable, the Corollary also
gives us a tool how to show that a certain linear subspace is dense - in the
Example 6.(iii) below we see that “nice” functions (continuous and vanishing
“near infinity”) are dense in the space of all (possibly very wild) Lebesgue
integrable functions.
6. Examples
(i) The space
C[a,b](R) = {f:RF:fcontinuous and f(x) = 0 x /[a, b]}
with the supremum norm is separable.
This follows easily using piecewise affine approximations with rational values
in the divisionpoints. The crucial argument is that uniform continuity of an
fC[a,b]ensures that the pwa approximations get uniformly close to fif
the division is fine enough.
(ii) Cc(R) = {f:RR:fcontinuous & Rf:|x|> Rff(x) = 0},
the space of all continuous functions vanishing near infinity ( also said to
have a compact support ), with the supremums norm is separable.
(iii) Cc(R) = S
n=1 C[n,n]is dense in (L1(R),k · k1), and hence L1(R) is
separable.
1span(S) is the smallest linear subspace of Xcontaining S
1
pf3

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B4a Banach spaces Michaelmas 2010 lectured by Bernd Kirchheim based on notes by CJK Batty

Lectures 7 and 8

  1. Theorem Let X be a normed vector space and let S be a countable subset of X such that span(S) = X 1 , then X is separable.
  2. Corollary Let X be a normed vector space and S ⊂ X. Then

spanS = spanS.

Hence, if there exists a countable set S ⊂ X such that spanS = X, then X is separable.

Remark Beside telling us when a space is separable, the Corollary also gives us a tool how to show that a certain linear subspace is dense - in the Example 6.(iii) below we see that “nice” functions (continuous and vanishing “near infinity”) are dense in the space of all (possibly very wild) Lebesgue integrable functions.

  1. Examples (i) The space

Ca,b = {f : R → F : f continuous and f (x) = 0 ∀x /∈ [a, b]}

with the supremum norm is separable. This follows easily using piecewise affine approximations with rational values in the divisionpoints. The crucial argument is that uniform continuity of an f ∈ C[a,b] ensures that the pwa approximations get uniformly close to f if the division is fine enough. (ii) Cc(R) = {f : R → R : f continuous & ∃Rf : |x| > Rf ⇒ f (x) = 0}, the space of all continuous functions vanishing near infinity ( also said to have a compact support ), with the supremums norm is separable. (iii) Cc(R) =

n=1 C[−n,n]^ is dense in (L

(^1) (R), ‖ · ‖ 1 ), and hence L (^1) (R) is

separable.

(^1) span(S) is the smallest linear subspace of X containing S

We consider the set C = {χM : M ⊂ R bounded and measurable}, then span(C) contains all simple functions, by a4 integration these are dense in L^1. We show that C ⊂ Cc(R) in L^1 and than use Corollary 5. To establish this claim

  • for each U open bounded construct continuous : fn : R → [0, 1], fn ≤ χU and fn ր χU. Then Lebesgue’s DCT implies that fn → χU in L^1 so we conclude χU ∈ Cc(R)
  • for each M bounded measurable and ε > 0 find U ⊃ M open bounded s.t. m(U \ M ) < ε. Hence

dist(χM , Cc(R)) ≤ ‖χM − χU ‖ 1 = ‖χU \M ‖ 1 < ε,

so sending ε ց 0 we have χM ∈ Cc(R).

5 Linear Operators

  1. Definition Let X, Y be normed vector spaces. A mapping T : X → Y such that for all x 1 , x 2 ∈ X and α 1 , α 2 ∈ C

T (α 1 x 1 + α 2 x 2 ) = α 1 T x 1 + α 2 T x 2

is said to be a Linear Operator from X to Y.

The linear operator T is said to be bounded if there exists M > 0 such that for all x ∈ X ‖T x‖Y ≤ M ‖x‖X

Let B(X, Y ) denote the set of bounded linear operators from X to Y (we write B(X) = B(X, Y ) if X = Y ).

  1. Lemma Let X, Y be normed vector spaces, let T ∈ B(X, Y ) and let

N 1 (T ) = inf {M : ‖T x‖ ≤ M ‖x‖ ∀x ∈ X} N 2 (T ) = sup{‖T x‖ : x ∈ B¯ 1 } ( B¯ 1 = {x ∈ X : ‖x‖ ≤ 1 })

N 3 (T ) = sup{

‖T x‖ ‖x‖

: x ∈ X and x 6 = 0}

N 4 (T ) = sup{‖T x‖ : x ∈ X ‖x‖ = 1}